Math Olympiad Questions 2009 || National

 

Primary Category
1. āĻāĻ•āĻĻāϞ āĻļāĻŋāĻ•ā§āώāĻžāĻ°ā§āĻĨā§€ āĻāĻ•āϟāĻŋ āφāĻ¸ā§āϤāĻžāĻŦāϞ āĻĒāϰāĻŋāĻĻāĻ°ā§āĻļāύ⧇ āĻ—āĻŋāϝāĻŧ⧇āϛ⧇āĨ¤ āĻāĻ• āϏāĻŽāϝāĻŧ āĻĻ⧇āĻ–āĻž āϗ⧇āϞ āφāĻ¸ā§āϤāĻžāĻŦāϞ⧇ 71āϟāĻŋ āĻŽāĻžāĻĨāĻž āφāϰ 228āϟāĻŋ āĻĒāĻž āφāϛ⧇āĨ¤ āϐ āϏāĻŽāϝāĻŧ⧇ āφāĻ¸ā§āϤāĻžāĻŦāϞ⧇ āĻ•āϤ⧋āϜāύ āĻļāĻŋāĻ•ā§āώāĻžāĻ°ā§āĻĨā§€ āĻ›āĻŋāϞ?

Some students are visiting a stable. At a certain time, it was counted that there are 71 heads and 228 legs were there. How many students were there at the time of counting?

2. 2,3,5,8 –āĻāχ āĻ…āĻ™ā§āĻ• āϗ⧁āϞ⧋ āĻĻāĻŋāϝāĻŧ⧇ āĻŽā§‹āϟ āĻ•āϝāĻŧāϟāĻŋ āĻĻ⧁āχ āĻ…āĻ™ā§āĻ• āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āĻ—āĻ āύ āĻ•āϰāĻž āϝāĻžāĻŦ⧇ ? āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āϗ⧁āϞ⧋ āϞāĻŋāĻ–āĨ¤

In how many ways is it possible to form two-digit prime number with the digits 2,3,5,8? Write all of them.

3. āĻŽāĻžāϰāϜāĻžāύ āĻāĻ•āϟāĻŋ āĻŦāχ āĻĒāĻĄāĻŧāϛ⧇ āϝāĻžāϤ⧇ āĻŽā§‹āϟāĻž 242 āĻĒ⧃āĻˇā§āĻ āĻž āφāϛ⧇āĨ¤ āĻ“ āĻĒā§āϰāĻĨāĻŽ āĻĻāĻŋāύ 22 āĻĒ⧃āĻˇā§āĻ āĻž āĻĒāĻĄāĻŧāϞ⧋āĨ¤ āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āĻĻāĻŋāύ āĻ“ āĻĒā§āϰāĻĨāĻŽ āĻĻāĻŋāύ⧇āϰ āĻšā§‡āϝāĻŧ⧇ 4 āĻĒ⧃āĻˇā§āĻ āĻž āĻŦ⧇āĻļāĻŋ āĻĒāĻĄāĻŧāϞ⧋, āϤ⧃āϤ⧀āϝāĻŧ āĻĻāĻŋāύāĻ“ āϤāĻžāχāĨ¤ āĻāϰāĻĒāϰ āĻĒā§āϰāϤāĻŋāĻĻāĻŋāύ āĻŽāĻžāϰāϜāĻžāύ āϝāĻĻāĻŋ āϤ⧃āϤ⧀āϝāĻŧ āĻĻāĻŋāύ⧇āϰ āĻšā§‡āϝāĻŧ⧇ 2 āĻĒ⧃āĻˇā§āĻ āĻž āĻŦ⧇āĻļāĻŋ āĻĒāĻĄāĻŧ⧇, āϤāĻžāĻšāϞ⧇ āĻ•āϤ⧋āĻĻāĻŋāύ⧇ āĻŽāĻžāϰāϜāĻžāύ⧇āϰ āϐ āĻŦāχāϟāĻŋ āĻĒāĻĄāĻŧāĻž āĻļ⧇āώ āĻšāĻŦ⧇āĨ¤

The book that Marjan reads has 242 pages. The first day he has read 22 pages. During the second day he has read 4 pages more than the first and the same during the third day. How many days will Marjan need to finish the book if he reads two pages more than the third days each day from the fourth day onward?

4. \[\frac{1}{2}, \frac{1}{3}, \frac{1}{12}, \frac{1}{18}, \frac{1}{x} \] = 1 āĻšāϞ⧇ x āĻāϰ āĻŽāĻžāύ āĻŦ⧇āϰ āĻ•āϰ⧋āĨ¤
Given that \[\frac{1}{2}, \frac{1}{3}, \frac{1}{12}, \frac{1}{18}, \frac{1}{x} \] = 1, what is the value of x.

5. āĻŽāĻŋāϞāĻž 3,7,1,9,0 āĻ“ 4 -āĻāχ āĻ…āĻ™ā§āĻ•āϗ⧁āϞ⧋ āĻāĻ•āĻŦāĻžāϰ āĻ•āϰ⧇ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰ⧇ 6 āĻ…āĻ‚āϕ⧇āϰ āĻŦ⧃āĻšāĻ¤ā§āϤāĻŽ āĻ“ āĻ•ā§āώ⧁āĻĻā§āϰāϤāĻŽ āϏāĻ‚āĻ–ā§āϝāĻž āĻ—āĻ āύ āĻ•āϰ⧇āĨ¤ āϤāĻžāϰāĻĒāϰ āϏ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāĻĻ⧁āĻŸā§‹āϰ āĻ…āĻ¨ā§āϤāϰāϕ⧇ 9 āϗ⧁āĻŖ āĻ•āĻŽāĻŋāϝāĻŧ⧇ āĻĢ⧇āϞ⧇āĨ¤ āϤāĻžāϰ āĻ•āĻžāϛ⧇ āϏāĻŦāĻļ⧇āώ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋ āĻ•āϤ⧋ ?

From the digits 3,7,1,9,0 and 4 Mila formed the biggest and the smallest six- digit number using each digit exactly once in each of the two numbers. Then she reduced their difference 9 times. Which number she get?

 

6. āĻĻ⧁āχāϟāĻŋ āϏāϰāϞāϰ⧇āĻ–āĻž āĻāĻ•āϟāĻŋ āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āĻŽāĻŋāϞāĻŋāϤ āĻšāĻ“āϝāĻŧāĻžāϝāĻŧ āϚāĻžāϰāϟāĻŋ āϕ⧋āύ āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āĻšāϞ⧋, āĻāϰ āĻŽāĻ§ā§āϝ⧇ āĻĻ⧁āχāϟāĻŋ āϏ⧂āĻ•ā§āĻˇā§āĻŽāϕ⧋āĻŖ āĻ“ āĻĻ⧁āχāϟāĻŋ āĻ¸ā§āĻĨā§‚āϞāϕ⧋āĻŖāĨ¤ āϏ⧂āĻ•ā§āĻˇā§āĻŽāϕ⧋āĻŖ āĻĻ⧁āχāϟāĻŋāϰ āϏāĻŽāĻˇā§āϟāĻŋ āĻĒā§āϰāϤāĻŋāϟāĻŋ āĻ¸ā§āĻĨā§‚āϞāϕ⧋āϪ⧇āϰ āĻ…āĻ°ā§āϧ⧇āĻ•āĨ¤ āϕ⧋āĻŖ āϚāĻžāϰāϟāĻŋāϰ āĻŽāĻžāύ āĻŦ⧇āϰ āĻ•āϰ⧋āĨ¤
Two lines intersect in one point and form four angles, two acute and two obtuse. The sum of the two acute angles is half of the one obtuse angle. Calculate these angles.
7. āĻāĻ• āφāχāϏāĻ•ā§āϰāĻŋāĻŽ āĻŦāĻŋāĻ•ā§āϰ⧇āϤāĻž āϏāĻžāϰāĻžāĻĻāĻŋāύ⧇ 20 āϕ⧇āϜāĻŋ āφāχāϏāĻ•ā§āϰāĻŋāĻŽ āĻŦāĻŋāĻ•ā§āϰāĻŋ āĻ•āϰ⧇āϛ⧇āĨ¤ āϏ⧇ āĻĒā§āϰāϤāĻŋāϟāĻŋ 2 āĻ¸ā§āϕ⧁āĻĒ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āϛ⧋āϟ āϕ⧋āύ āφāχāϏāĻ•ā§āϰāĻŋāĻŽ 1.20 āϟāĻžāĻ•āĻžāϝāĻŧ āĻāĻŦāĻ‚ āĻĒā§āϰāϤāĻŋāϟāĻŋ āĻ¸ā§āϕ⧁āĻĒ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āϕ⧋āύ āφāχāϏāĻ•ā§āϰāĻŋāĻŽ āĻĒā§āϰāϤāĻŋāϟāĻŋ 1.60 āϟāĻžāĻ•āĻžāϝāĻŧ āĻŦāĻŋāĻ•ā§āϰāĻŋ āĻ•āϰ⧇āĨ¤ āĻĒā§āϰāϤāĻŋ āϕ⧇āϜāĻŋ āφāχāϏāĻ•ā§āϰāĻŋāĻŽā§‡ 12āϟāĻŋ āĻ¸ā§āϕ⧁āĻĒ āϤ⧈āϰāĻŋ āĻšāϝāĻŧāĨ¤ āĻĻāĻŋāύ āĻļ⧇āώ āϤāĻžāϰ āĻŽā§‹āϟ āφāϝāĻŧ 137.60 āϟāĻžāĻ•āĻž āĻšāϞ⧇ āϏ⧇āĻĻāĻŋāύ āϏ⧇ āĻ•āϤāϟāĻŋ āĻŦāĻĄāĻŧ āϕ⧋āύ āφāχāϏāĻ•ā§āϰāĻŋāĻŽ āĻŦāĻŋāĻ•ā§āϰāĻŋ āĻ•āϰ⧇āϛ⧇?
An ice-cream seller prepares 20kg of ice-cream and sells it all in a day as small cones at 1.20 Taka with two scoops and big cones at 1.60 Taka with three scoops. Each kilogram of ice-cream gives 12 scoops. At the end of the day, he earned 137.60 Taka in total. How many big cones did he sell?

8. 3-āĻ…āĻ™ā§āĻ• āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻŦ⧇āĻœā§‹āĻĄāĻŧ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋āϰ āĻŽāĻ§ā§āϝ⧇ āϝ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋āϰ āĻ…āĻ™ā§āĻ•āϗ⧁āϞ⧋āϰ āϗ⧁āĻŖāĻĢāϞ 140 āϏ⧇āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋āϰ āϝ⧋āĻ—āĻĢāϞ āĻ•āϤ⧋?
Determine the sum of all odd 3-digit numbers whose product of digits is equal to 140?

9. āĻāĻ•āϟāĻŋ āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻŦāĻžāĻšā§āϗ⧁āϞāĻŋ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ a āĻ“ b āϏ⧇āĻŽāĻŋāĨ¤ āϝāĻĻāĻŋ a āĻŦāĻžāĻšā§āϕ⧇ b āĻĒāϰāĻŋāĻŽāĻžāύ āĻ“ b āĻŦāĻžāĻšā§āϕ⧇ a āĻĒāϰāĻŋāĻŽāĻžāĻŖ āĻŦāĻžāĻĄāĻŧāĻžāύ⧋ āĻšāϝāĻŧ, āϤāĻžāĻšāϞ⧇ āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻšāϝāĻŧ 100 āĨ¤ āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻŦāĻžāĻšā§āϗ⧁āϞāĻŋāϰ āĻĻ⧈āĻ°ā§āϘ āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻžāĨ¤ āĻāχ āĻļāĻ°ā§āϤ āĻĒā§‚āϰāĻŖ āĻ•āϰ⧇ āĻāĻŽāύ āϏāĻ°ā§āĻŦāύāĻŋāĻŽā§āύ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰāϟāĻŋ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋ āĨ¤

One rectangle has side a cm and b cm. If the side with length a cm is enlarged by b cm and the side with length b cm is enlarged by a cm then the resulting square has area of 100 cm2. Determine the rectangle that satisfies this condition with smallest area if its side lengths are positive integers.

10.āϕ⧋āύ āĻāĻ•āĻĻāĻŋāύ āϤ⧋āĻŽāĻžāϰ 5 āĻŦāĻ¨ā§āϧ⧁ āĻāĻ•āϟāĻŋ āĻ•ā§āϝāĻžāĻĢ⧇āϤ⧇ āϗ⧇āϞ āϕ⧇āĻ• āϖ⧇āϤ⧇āĨ¤ āϐ āĻ•ā§āϝāĻžāĻĢ⧇ āĻŽā§‹āϟ 4 āϰāĻ•āĻŽā§‡āϰ āϕ⧇āĻ• āϤ⧈āϰāĻŋ āĻ•āϰ⧇āĨ¤ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ• āĻŦāĻ¨ā§āϧ⧁ āĻĻ⧁āχāϟāĻŋ āĻ­āĻŋāĻ¨ā§āύ āϰāĻ•āĻŽā§‡āϰ āϕ⧇āĻ• āĻĒāĻ›āĻ¨ā§āĻĻ āĻ•āϰ⧇āĨ¤ āϤāĻžāĻĻ⧇āϰ āĻŦāĻŋāϞ āĻšāϞ⧋ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ 6 āϟāĻžāĻ•āĻž, 9 āϟāĻžāĻ•āĻž, 11 āϟāĻžāĻ•āĻž, 12 āϟāĻžāĻ•āĻž āĻ“ 15 āϟāĻžāĻ•āĻžāĨ¤ āĻĒāϰ⧇āϰāĻĻāĻŋāύ āϤ⧁āĻŽāĻŋ āύāĻŋāĻœā§‡ āϐ āĻĻā§‹āĻ•āĻžāύ⧇ āĻ—āĻŋāϝāĻŧ⧇ 4 āϰāĻ•āĻŽā§‡āϰ āϕ⧇āĻ• āĻāĻ•āϟāĻŋ āĻ•āϰ⧇ āϖ⧇āϞ⧇āĨ¤ āϤ⧋āĻŽāĻžāϕ⧇ āĻ•āϤ⧋ āϟāĻžāĻ•āĻž āĻŦāĻŋāϞ āĻĻāĻŋāϤ⧇ āĻšāĻŦ⧇?

One day five of your friends go to a cafÊ to eat cake. The cafÊ sells 4 different types of cake. Each friend chooses two different cakes. They find there bills are for Tk. 6, Tk. 9, Tk. 11 ¡ Tk. 12 and Tk 15. The next day you go to same cafÊ and buy one of each type of cake. How much you have to pay?

 

Junior Category

1. \[\frac{1}{2}, \frac{1}{3}, \frac{1}{12}, \frac{1}{18}, \frac{1}{x} \] = 1 āĻšāϞ⧇ x āĻāϰ āĻŽāĻžāύ āĻŦ⧇āϰ āĻ•āϰ⧋āĨ¤
Given that \[\frac{1}{2}, \frac{1}{3}, \frac{1}{12}, \frac{1}{18}, \frac{1}{x} \] = 1, what is the value of x.

2. 3-āĻ…āĻ™ā§āĻ• āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻŦ⧇āĻœā§‹āĻĄāĻŧ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋āϰ āĻŽāĻ§ā§āϝ⧇ āϝ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋āϰ āĻ…āĻ™ā§āϕ⧇āϰ āϗ⧁āĻŖāĻĢāϞ 140 āϏ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋āϰ āϝ⧋āĻ—āĻĢāϞ āĻ•āϤ⧋?
Determine the sum of all odd 3-digit numbers whose product of digits is equal to 140?
3. āĻāĻ•āϟāĻŋ 3×3 āĻšā§‡āĻ•āĻžāϰāĻŦā§‹āĻ°ā§āĻĄā§‡āϰ āύāϝāĻŧāϟāĻŋ āĻŦāĻ°ā§āĻ—āϕ⧇ āĻāĻŽāύāĻ­āĻžāĻŦ⧇ āϰāĻ‚ āĻ•āϰāϤ⧇ āĻšāĻŦ⧇ āϝāĻžāϤ⧇ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ• āϏāĻžāϰāĻŋ, āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ• āĻ•āϞāĻžāĻŽ āĻ“ āĻĻ⧁āϟāĻŋ āĻ•āĻ°ā§āϪ⧇āϰ āĻŽāĻ§ā§āϝāĻ•āĻžāϰ āĻĻ⧁āχāϟāĻŋ āĻŦāĻ°ā§āϗ⧇āϰ āϰāĻ‚ āĻāĻ•āχ āύāĻž āĻšāϝāĻŧāĨ¤ āĻ•āĻŽāĻĒāĻ•ā§āώ⧇ āĻ•āϤ⧋ āϰāĻ•āĻŽā§‡āϰ āϰāϙ⧇āϰ āĻĻāϰāĻ•āĻžāϰ?
The nine squares of a 3×3 checkerboard must be painted so that each row, each column, and each of the two diagonals have no two squares of the same colour. What is the least number of colours needed?
4. \[ x^2 – 8xy + 9y^2 – 16y + 10 \] āϰāĻžāĻļāĻŋāĻŽāĻžāϞāĻžāϰ āϏāĻŽā§āĻ­āĻžāĻŦā§āϝ āϏāĻ°ā§āĻŦāύāĻŋāĻŽā§āύ āĻŽāĻžāύ āĻ•āϤ⧋? (x āĻ“ y āĻŦāĻžāĻ¸ā§āϤāĻž āϏāĻ‚āĻ–ā§āϝāĻž)
Find the least possible value of the expression, \[ x^2 – 8xy + 9y^2 – 16y + 10 \]. (x and y both real number)
5. āĻāĻ•āϟāĻŋ N x N āĻ—ā§āϰāĻŋāĻĄ āĻĨ⧇āϕ⧇ āφāĻŦāĻŋāϰ āϤāĻŋāύāϟāĻŋ āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻŦ⧇āϛ⧇ āύāĻŋāϝāĻŧ⧇ āĻ¤ā§āϰāĻŋāϭ⧁āϜ āφāρāĻ•āϛ⧇āĨ¤ āĻŽāϜāĻžāϰ āĻŦāĻŋāώāϝāĻŧ āĻšāϞ⧋, āφāĻŦāĻŋāϰ āĻĒā§āϰāϤāĻŋāĻŦāĻžāϰāχ (,) āĻāχ āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϟāĻŋ āĻŦāĻžāĻ›āĻžāχ āĻ•āϰ⧇āĨ¤ āĻāĻ­āĻžāĻŦ⧇ āφāĻŦāĻŋāϰ⧇āϰ āφāρāĻ•āĻž āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āĻŦāĻĄāĻŧ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋āĨ¤ (āϤ⧋āĻŽāĻžāϰ āωāĻ¤ā§āϤāϰ⧇āϰ āϏāĻĒāĻ•ā§āώ⧇ āϝ⧁āĻ•ā§āϤāĻŋ āĻĻāĻžāĻ“)
In a N x N grid, Abir picks three lattice points as vertexes of a triangle. urprisingly, he always chooses the (0,0) point. What is the largest area of the triangle Abir can draw ? (Justify your answer.)
6. āĻāĻ•āϟāĻŋ āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰāϕ⧇ āϏāĻŽāĻžāύ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āϤāĻŋāύāϟāĻŋ āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇ āĻ­āĻžāĻ— āĻ•āϰāĻž āĻšāϞ (āύāĻŋāĻšā§‡āϰ āĻ›āĻŦāĻŋ āĻĻ⧇āĻ–ā§‹)āĨ¤ āϏāĻŽāĻžāĻ¨ā§āϤāϰāĻžāϞ āϰ⧇āĻ–āĻžāĻĻā§āĻŦāϝāĻŧ⧇āϰ āĻŽāĻ§ā§āϝāĻŦāĻ°ā§āϤ⧀ āĻĻā§‚āϰāĻ¤ā§āĻŦ 1 āϏ⧇.āĻŽāĻŋ. āĻšāϞ⧇ āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰāϟāĻŋāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻ•āϤ⧋?

Math Olympiad Questions 2009
A square is divided into three pieces of equal area as shown. The distance between the parallel lines is 1 cm. What is the area of the square?
7. \[\frac{7}{26}\] āϕ⧇ \[\frac{1}{a} + \frac{1}{b} \] āφāĻ•āĻžāϰ⧇ āĻĒā§āϰāĻ•āĻžāĻļ āĻ•āϰ⧋ āϝ⧇āĻ–āĻžāύ⧇ a āĻ“ b āϧāύāĻžāĻ¤ā§āĻŽāĻ• āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻžāĨ¤

Express \[\frac{7}{26}\] as \[\frac{1}{a} + \frac{1}{b} \] (a and b, both are positive integers)
ā§Ē. āĻāĻ•āχ āϏāĻŽāϤāϞ⧇ āϤāĻŋāύāϟāĻŋ āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āφāϛ⧇āĨ¤ āĻāχ āϤāĻŋāύāϟāĻŋ āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻĻāĻŋāϝāĻŧ⧇ āϝ⧇ āĻ•āϝāĻŧāϟāĻŋ āϏāĻžāĻŽāĻžāĻ¨ā§āϤāϰāĻŋāĻ• (āϏāĻžāĻŽāĻžāĻ¨ā§āϤāϰāĻŋāϕ⧇āϰ āϚāĻžāϰāϟāĻŋ āĻļā§€āĻ°ā§āώāĻŦāĻŋāĻ¨ā§āĻĻ⧁āϰ āϤāĻŋāύāϟāĻŋ āĻ…āĻŦāĻļā§āϝāχ āĻāχ āϤāĻŋāύāϟāĻŋ āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻšāĻŦ⧇) āφāρāĻ•āĻž āϏāĻŽā§āĻ­āĻŦ āϤāĻžāĻĻ⧇āϰ āĻŽāĻ§ā§āϝ⧇ āϏāĻ°ā§āĻŦā§‹āĻšā§āϚ āĻ“ āϏāĻ°ā§āĻŦāύāĻŋāĻŽā§āύ āĻĒāϰāĻŋāϏ⧀āĻŽāĻž āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āϏāĻžāĻŽāĻžāĻ¨ā§āϤāϰāĻŋāĻ• āĻĻ⧁āχāϟāĻŋāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ⧇āϰ āĻĒāĻžāĻ°ā§āĻĨāĻ•ā§āϝ āĻŦ⧇āϰ āĻ•āϰ⧋āĨ¤
There are three points in a plane. One can draw as many parallelograms as possible keeping those three points as the three vertices of the parallogram.

Find the difference between the area of parallelogram having the largest perimeter possible and the parallelogram having the minimum perimeter possible.
9. āϤāĻŋāύāĻŦāĻžāĻšā§ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻāĻŦāĻ‚ āϧāύāĻžāĻ¤ā§āĻŽāĻ• āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻŦāĻšā§āϭ⧁āϜ āĻšāϞ⧋ āĻ¤ā§āϰāĻŋāϭ⧁āϜāĨ¤ āĻāĻ•āϟāĻŋ āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻāĻ•āϟāĻŋ āϕ⧋āĻŖ āĻāĻ•āχ āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻ…āĻĒāϰ āĻāĻ•āϟāĻŋ āϕ⧋āϪ⧇āϰ āĻĻā§āĻŦāĻŋāϗ⧁āύāĨ¤ āĻāχ āĻĻ⧁āχāϟāĻŋ āϕ⧋āϪ⧇āϰ āĻāĻ•āϟāĻŋāϰ āĻŽāĻžāύ 120 āĻĄāĻŋāĻ—ā§āϰ⧀āĨ¤ āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āĻŦ⧃āĻšāĻ¤ā§āϤāĻŽ āϕ⧋āϪ⧇āϰ āϏāĻŽāĻĻā§āĻŦāĻŋāĻ–āĻ¨ā§āĻĄāĻ• āĻāϰ āĻŦāĻŋāĻĒāϰ⧀āϤ āĻŦāĻžāĻšā§āϕ⧇ D āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āϛ⧇āĻĻ āĻ•āϰ⧇āϛ⧇āĨ¤ āĻŦ⧃āĻšāĻ¤ā§āϤāĻŽ āϕ⧋āϪ⧇āϰ āĻļā§€āĻ°ā§āώ āĻĨ⧇āϕ⧇ D āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϰ āĻĻā§‚āϰāĻ¤ā§āĻŦ 10 āϏ⧇āĻŽāĻŋ. āϝāĻĻāĻŋ āĻ¤ā§āϰāĻŋāϭ⧁āϜāϟāĻŋāϰ āĻŦ⧃āĻšāĻ¤ā§āϤāĻŽ āĻŦāĻžāĻšā§āϰ āĻĻ⧈āĻ°ā§āϘ 2x āĻšāϝāĻŧ, āϤāĻŦ⧇ āύāĻŋāĻšā§‡āϰ āϏāĻŽā§āĻĒāĻ°ā§āĻ• āϏāĻŋāĻĻā§āϧ āĻšāϝāĻŧāĨ¤
\[ x^4-C_3x^3-C_2x^2-C_1x+1875 = 0 \]
\[ C_1, C_2, C_3 \]-āĻāϰ āĻŽāĻžāύ āĻŦāĻŋāĻļā§āϞ⧇āώāĻŖ āĻ•āϰ⧇ āĻŦ⧇āϰ āĻ•āϰ⧋āĨ¤ (āϏāĻžāĻšāĻžāĻ¯ā§āϝ : āĻĻ⧁āχāϟāĻŋ āϏāĻĻ⧃āĻļāϕ⧋āĻŖā§€ āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻŦāĻžāĻšā§āϗ⧁āϞāĻŋāϰ āĻ…āύ⧁āĻĒāĻžāϤ āϕ⧇āĻŽāύ?)
A triangle is a polygon with three sides and a strictly positive area. One angle of a triangle is twice of another angle of the same triangle. An angle of this triangle is 120 degree. The bisector of the second largest triangle intersects its opposite side at point D. The distance of D from the vertex containing the largest angle is 10 cm. If the length of the largest side of this triangle is 2x, then a relationship like the following is true:
\[ x^4-C_3x^3-C_2x^2-C_1x+1875 = 0 \]
Find the value of \[ C_1, C_2, C_3 \] analytically. (Hints – What is the relation between the sides of two similar triangles.)

10.āĻāĻ•āϟāĻŋ āĻ…āĻĻā§āϭ⧁āϤ āĻ­āĻžāώāĻžāϝāĻŧ āĻŽāĻžāĻ¤ā§āϰ āĻĻ⧁āϟāĻŋ āĻŦāĻ°ā§āĻŖ āφāϛ⧇, a āφāϰ bāĨ¤ āφāĻŦāĻžāϰ āĻŽā§‡āύ⧇ āύ⧇āĻ“āϝāĻŧāĻž āĻšāϝāĻŧ⧇āϛ⧇ āϝ⧇, āĻŦāĻ°ā§āĻŖ a āĻāĻ•āϟāĻŋ āĻļāĻŦā§āĻĻāĻ“ āĻŦāĻŸā§‡āĨ¤ āύāĻŋāĻšā§‡āϰ āύāĻŋāϝāĻŧāĻŽ āĻŽā§‡āύ⧇ āϏ⧇āĻ–āĻžāύ⧇ āύāϤ⧁āύ āĻļāĻŦā§āĻĻ āϤ⧈āϰāĻŋ āĻ•āϰāĻž āϝāĻžāϝāĻŧ
(i) āϝ⧇āϕ⧋āύ āĻļāĻŦā§āĻĻ⧇āϰ āĻĄāĻžāύāĻĒāĻžāĻļ⧇ āĻāĻ•āϟāĻŋ b āĻŦāϏāĻžāϞ⧇ āύāϤ⧁āύ āĻļāĻŦā§āĻĻ āϤ⧈āϰāĻŋ āĻšāϝāĻŧ,
(ii) āϝāĻĻāĻŋ āϕ⧋āύ āĻļāĻŦā§āĻĻ⧇ aaa āĻĨāĻžāϕ⧇ āϤāĻŦ⧇ āϏ⧇āϟāĻŋāϕ⧇ b āĻĻā§āĻŦāĻžāϰāĻž āĻĒā§āϰāϤāĻŋāĻ¸ā§āĻĨāĻžāĻĒāĻŋāϤ āĻ•āϰāϞ⧇ āύāϤ⧁āύ āĻļāĻŦā§āĻĻ āĻšāϝāĻŧ,
(iii) āϝāĻĻāĻŋ āϕ⧋āύ āĻļāĻŦā§āĻĻ⧇ bbb āĻĨāĻžāϕ⧇ āϤāĻŦ⧇ āϤāĻž āĻāϕ⧇āĻŦāĻžāϰ⧇ āĻĢ⧇āϞ⧇ āĻĻāĻŋāϞ⧇āĻ“ āĻļāĻŦā§āĻĻ āĻšāϝāĻŧ,
(iv) āϕ⧋āύ āĻļāĻŦā§āĻĻ⧇ āĻŦāĻ°ā§āĻŖāϗ⧁āϞāĻŋ āϝ⧇āĻ­āĻžāĻŦ⧇ āĻĨāĻžāϕ⧇ āϏ⧇āϗ⧁āϞ⧋āϕ⧇ āĻ•ā§āϰāĻŽ āĻ āĻŋāĻ• āϰ⧇āϖ⧇ āĻĒāϰāĻĒāϰ āĻĻ⧁āχāĻŦāĻžāϰ āϞāĻŋāĻ–āϞ⧇āĻ“ āύāϤ⧁āύ āĻļāĻŦā§āĻĻ āĻšāĻŦ⧇āĨ¤
āωāĻĻāĻžāĻšāϰāĻŖ āĻšāĻŋāϏāĻžāĻŦ⧇ āĻŦāϞāĻž āϝāĻžāϝāĻŧ, (iv) āύāĻŋāϝāĻŧāĻŽ āĻ…āύ⧁āϏāĻžāϰ⧇ aa āĻļāĻŦā§āĻĻ (āĻ•āĻžāϰāĻŖ, a āĻāĻ•āϟāĻŋ āĻļāĻŦā§āĻĻ āϝāĻž āĻŽā§‡āύ⧇ āύ⧇āĻ“āϝāĻŧāĻž āĻšāϝāĻŧ⧇āϛ⧇ āĻļ⧁āϰ⧁āϤ⧇āχ), āφāĻŦāĻžāϰ (iv) āĻ…āύ⧁āϏāĻžāϰ⧇ aaaa-āĻ“ āĻāĻ•āϟāĻŋ āĻļāĻŦā§āĻĻāĨ¤ āϏ⧁āϤāϰāĻžāĻ‚, (ii) āύāĻ‚ āύāĻŋāϝāĻŧāĻŽ āĻ…āύ⧁āϏāĻžāϰ⧇ ba āĻāĻ•āϟāĻŋ āĻļāĻŦā§āĻĻ, āϝāĻžāϤ⧇ (i) āύāĻ‚ āύāĻŋāϝāĻŧāĻŽ āĻĒā§āϰāϝāĻŧā§‹āĻ— āĻ•āϰāϞ⧇ bab-āĻ“ āĻāĻ•āϟāĻŋ āĻļāĻŦā§āĻĻāĨ¤ āφāĻŦāĻžāϰ āϝāĻĻāĻŋ (i) āύāĻ‚ āύāĻŋāϝāĻŧāĻŽ āĻĒā§āϰāϝāĻŧā§‹āĻ— āĻ•āϰāĻŋ āϤāĻžāĻšāϞ⧇ babb āĻļāĻŦā§āĻĻ āĻĒāĻžāĻŦā§‹āĨ¤ āĻāĻ–āύ āφāĻŦāĻžāϰ (iv) āύāĻ‚ āύāĻŋāϝāĻŧāĻŽā§‡ babbbabb āĻšāĻšā§āϛ⧇ āĻāĻ•āϟāĻŋ āύāϤ⧁āύ āĻļāĻŦā§āĻĻāĨ¤ āϏāĻŦāĻļ⧇āώ (iii) āύāĻŋāϝāĻŧāĻŽā§‡ baabb āĻāĻ•āϟāĻŋ āĻļāĻŦā§āĻĻāĨ¤
āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰ⧋ āϝ⧇, āĻāχ āĻ­āĻžāώāĻžāϝāĻŧ, baabaabaa āϕ⧋āύ āĻļāĻŦā§āĻĻ āύāϝāĻŧāĨ¤

In a strange language there are only two letters, a and b, and it is postulated that the letter a is a word. Furthermore, all additional words are formed according to the following rules:
i. Given any word, a new word can be formed from it by adding one b at the right hand end.
ii. If in any word a sequence aaa appears, a new word can be formed by replacing aaa by the letter b.
iii. If in any word a sequence bbb appears, a new word can be formed by omitting bbb.
iv. Given any word, a new word can be formed by writing down the
sequence that constitutes the given word twice.
For example, by (iv), aa is a word, and by (iv) again, aaaa is a word. Hence by (ii) ba is a word, and by (i), bab ia also a word. Again, by (i), babb is a word, and so by (iv), babbbabb is also a word. Finally, by (iii) we find that baabb is a word.
Prove that in this language baabaabaa is not a word.

 

Secondary Category

1. āĻāĻ•āϟāĻŋ āϘāϰ⧇ āϜāύ āϰāĻžāϜāύ⧀āϤāĻŋāĻŦāĻŋāĻĻ āĻŦāϏ⧇ āφāϛ⧇āύāĨ¤ āĻāĻĻ⧇āϰ āĻĒā§āϰāĻ¤ā§āϝ⧇āϕ⧇ āĻšāϝāĻŧ āĻ¸ā§Ž āĻ…āĻĨāĻŦāĻž āĻĻ⧁āĻ°ā§āύ⧀āϤāĻŋāĻŦāĻžāϜāĨ¤ āϤāĻŦ⧇, āĻ•āĻŽāĻĒāĻ•ā§āώ⧇ āĻāĻ•āϜāύ āĻ¸ā§ŽāĨ¤ āφāĻŦāĻžāϰ āϝ⧇āϕ⧋āύ āĻĻ⧁āχāϜāύ⧇āϰ āĻŽāĻ§ā§āϝ⧇ āĻāĻ•āϜāύ āĻ…āĻ¸ā§ŽāĨ¤ āϰāĻžāϜāύ⧀āϤāĻŋāĻŦāĻŋāĻĻāĻĻ⧇āϰ āĻŽāĻ§ā§āϝ⧇ āĻ•āϤ⧋āϜāύ āĻ¸ā§Ž āφāϰ āĻ•āϤ⧋āϜāύ āĻĻ⧁āĻ°ā§āύ⧀āϤāĻŋāĻŦāĻžāϜ ?
300 politicians are sitting in a room. Each one is corrupted or honest. At least one is honest. Given any two politicians, at least one is corrupt. How many are corrupted and how many are honest?
2. āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻžāϝāĻŧ āϏāĻŽāĻžāϧāĻžāύ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ \[\frac{x^2}{2} + \frac{5}{y} = 7\]
Find all integral solutions of the equation \[\frac{x^2}{2} + \frac{5}{y} = 7\]

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3. ABC āĻāĻ•āϟāĻŋ āϏ⧂āĻ•ā§āĻˇā§āĻŽāϕ⧋āĻŖā§€ āĻ¤ā§āϰāĻŋāϭ⧁āϜāĨ¤ ∠BAC āĻāϰ āϏāĻŽāĻĻā§āĻŦāĻŋāĻ–āĻ¨ā§āĻĄāĻ•, B āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻĨ⧇āϕ⧇ AC āĻŦāĻžāĻšā§āϰ āωāĻĒāϰ āĻ…āĻ‚āĻ•āĻŋāϤ āϞāĻŽā§āĻŦ āĻāĻŦāĻ‚ AB āĻŦāĻžāĻšā§āϰ āϞāĻŽā§āĻŦāĻĻā§āĻŦāĻŋāĻ–āĻ¨ā§āĻĄāĻ• āĻāĻ•āχāĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āϛ⧇āĻĻ āĻ•āϰ⧇āĨ¤ ∠BAC-āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋āĨ¤
Triangle ABC is acute with the property that the bisector of ∠BAC and the altitude from B to side AC and the perpendicular bisector of AB intersect at one point. Determine the angle ∠BAC.

4. ABC āĻāĻ•āϟāĻŋ āϏ⧂āĻ•ā§āĻˇā§āĻŽāϕ⧋āĻŖā§€ āĻ¤ā§āϰāĻŋāϭ⧁āϜ āĻāĻŦāĻ‚ M āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻĒāϰāĻŋāϕ⧇āĻ¨ā§āĻĻā§āϰāĨ¤ āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻ…āĻ­ā§āϝāĻ¨ā§āϤāϰ⧇ P āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋ āϝāĻž āύāĻŋāĻšā§‡āϰ āĻļāĻ°ā§āϤāĻžāĻŦāϞ⧀āϕ⧇ āĻĒā§‚āϰāĻŖ āĻ•āϰ⧇

1 ≤ \[\frac{∠APB}{∠ACB}\] ≤ 2, 1 ≤ \[\frac{∠BPC}{∠BAC}\] ≤ 2, 1 ≤ \[\frac{∠CPA}{∠CBA}\] ≤ 2

Triangle ABC is acute and M is its circumcenter. Determine what points P inside the triangle satisfy
1 ≤ \[\frac{∠APB}{∠ACB}\] ≤ 2, 1 ≤ \[\frac{∠BPC}{∠BAC}\] ≤ 2, 1 ≤ \[\frac{∠CPA}{∠CBA}\] ≤ 2

5. ABC āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡Â  ∠A = 90°āĨ¤ BCāĻāϰ āĻŽāĻ§ā§āϝāĻŦāĻŋāĻ¨ā§āĻĻ⧁ MāĨ¤ AC āĻāϰ āωāĻĒāϰ D āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻāĻŽāύāĻ­āĻžāĻŦ⧇ āύ⧇āĻ“āϝāĻŧāĻž āĻšāϞ āϝāĻžāϤ⧇ AD = AM āĻšāϝāĻŧāĨ¤ AMC āĻ“ BDC āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻĒāϰāĻŋāĻŦ⧃āĻ¤ā§āϤ āĻĻ⧁āχāϟāĻŋ āĻĒāϰāĻ¸ā§āĻĒāϰāϕ⧇ C āĻ“ P āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āϛ⧇āĻĻ āĻ•āϰ⧇āĨ¤ (∠ACB āĻ“ ∠PCB) –āĻāϰ āĻ…āύ⧁āĻĒāĻžāϤ āĻŦ⧇āϰ āĻ•āϰ⧋āĨ¤
In triangle ABC, ∠A = 90°. M is the midpoint of BC. Choose D on AC such that AD = AM. The circumcircles of triangles AMC and BDC intersect at C and at a point P. What is the ratio of angles: (∠ACB)/( ∠PCB)?
6. 40 āϜāύ āĻŽā§āĻ­āĻžāĻ°ā§āϏ {āĻ—āĻŖāĻŋāϤ āĻ…āϞāĻŋāĻŽā§āĻĒāĻŋāϝāĻŧāĻžāĻĄ āĻ¸ā§āĻŦ⧇āĻšā§āĻ›āĻžāϏ⧇āĻŦāĻ•} āĻŦ⧃āĻ¤ā§āϤāĻžāĻ•āĻžāϰ⧇ āĻŦāϏ⧇ āφāϛ⧇āĨ¤ āĻŽā§āύāĻŋāϰ āĻšāĻžāϏāĻžāύ āϤāĻžāĻĻ⧇āϰ āĻŽāĻ§ā§āϝ āĻĨ⧇āϕ⧇ 3āϜāύāϕ⧇ āĻĻ⧈āĻŦāϚāϝāĻŧāύ⧇ (āύāĻŋāĻ°ā§āĻŦāĻŋāϚāĻžāϰ) āύāĻŋāĻ°ā§āĻŦāĻžāϚāĻŋāϤ āĻ•āϰ⧇āϛ⧇ āĻĒ⧁āϰāĻ¸ā§āĻ•āĻžāϰ āĻŦāĻŋāϤāϰāύ⧀ āĻ…āύ⧁āĻˇā§āĻ āĻžāύ⧇ āϏāĻšāĻžāϝāĻŧāϤāĻž āĻ•āϰāĻžāϰ āϜāĻ¨ā§āϝāĨ¤ āĻ•āϤ⧋āĻ­āĻžāĻŦ⧇ āĻ¸ā§āĻŦ⧇āĻšā§āĻ›āĻžāϏ⧇āĻŦāĻ•āĻĻ⧇āϰ āĻŦāĻžāĻ›āĻžāχ āĻ•āϰāĻž āϝāĻžāĻŦ⧇, āϝāĻžāϤ⧇ āϐ 3āϜāύ⧇āϰ āĻŽāĻ§ā§āϝ⧇ āĻ•āĻŽāĻĒāĻ•ā§āώ⧇ āĻĻ⧁āχāϜāύ āĻŦāĻžāĻ›āĻžāχ-āĻāϰ āφāϗ⧇ āĻĒāĻžāĻļāĻžāĻĒāĻžāĻļāĻŋ āĻŦāϏ⧇āĻ›āĻŋāϞ?
ā§§ā§Š āĻĢ⧇āĻŦā§āϰ⧁āϝāĻŧāĻžāϰāĻŋ, ⧍ā§Ļā§Ļ⧝ āĻļ⧁āĻ•ā§āϰāĻŦāĻžāϰāĨ¤ āϏ⧇āĻ¨ā§āϟ āϝ⧋āϏ⧇āĻĢ āĻšāĻžāϝāĻŧāĻžāϰ āϏ⧇āϕ⧇āĻ¨ā§āĻĄāĻžāϰāĻŋ āĻ¸ā§āϕ⧁āϞ, āĻĸāĻžāĻ•āĻžāĨ¤
1
Forty Movers (Mathematical Olympiad Volunteers) are sitting in a circle. Munir Hasan randomly chooses 3 volunteers to help in the awards ceremony. In how many ways can the volunteers be chosen such that at least 2 of the volunteers were sitting next to each before being chosen?

7. 1  āĻ“ 0 āĻĒāϰāĻĒāϰ āĻĨāĻžāϕ⧇ āĻāϰāĻ•āĻŽ āϏāĻŋāϕ⧋āϝāĻŧ⧇āĻ¨ā§āϏ⧇āϰ āωāĻĻāĻžāĻšāϰāĻŖ āĻšāϞ⧋ N = 1010101 āĻāĻŦāĻ‚ āĻāĻ–āĻžāύ⧇ N-āĻāϰ āĻŦ⧈āĻļāĻŋāĻˇā§āĻŸā§āϝ āĻšāϞ⧋ 99N = 999999991 āĻāĻ–āύ, āĻ•āϤ⧋āϗ⧁āϞ⧋ āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āφāϛ⧇ āϝ⧇āϗ⧁āϞ⧋āϕ⧇ āĻāϰāĻ•āĻŽ 1 āĻ“ ) -āĻāϰ āĻĒāϰāĻĒāϰ āϏāĻŋāϕ⧋āϝāĻŧ⧇āĻ¨ā§āϏ āφāĻ•āĻžāϰ⧇ āϞ⧇āĻ–āĻž āϝāĻžāĻŦ⧇ āϝ⧇āĻ–āĻžāύ⧇ āĻĒā§āϰāĻĨāĻŽ āĻ“ āĻļ⧇āώ āĻ…āĻ™ā§āĻ• āĻšāĻŦ⧇ 1?
How many positive prime numbers can be written as an alternating sequence of 1’s and O’s where the first and last digit is 12 An alternating sequence of 1’s and 0’s is for example: N = 1010101, and has the property that 99N = 99999999.
8. A āĻ•ā§āώ⧇āĻ¤ā§āϰāϟāĻŋ x āĻ…āĻ•ā§āώ, y = \[\frac{x}{2}\]
āϏāϰāϞāϰ⧇āĻ–āĻž āĻ“ \[\frac{x^2}{9} + y^2\]=1 āωāĻĒāĻŦ⧃āĻ¤ā§āϤ āĻĻā§āĻŦāĻžāϰāĻž āϏ⧀āĻŽāĻžāĻŦāĻĻā§āϧāĨ¤ B āĻ•ā§āώ⧇āĻ¤ā§āϰāϟāĻŋ y-āĻ…āĻ•ā§āώ, y = mx āϏāϰāϞāϰ⧇āĻ–āĻž āĻ“ \[\frac{x^2}{9} + y^2\]=1 āωāĻĒāĻŦ⧃āĻ¤ā§āϤ āĻĻā§āĻŦāĻžāϰāĻž āϏ⧀āĻŽāĻžāĻŦāĻĻā§āϧāĨ¤ m –āĻāϰ āϕ⧋āύ āĻŽāĻžāύ⧇āϰ āϜāĻ¨ā§āϝ A āĻ“ B –āĻāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āϏāĻŽāĻžāύ āĻšāĻŦ⧇?

The region A is bounded by the x-axis, the line y = \[\frac{x}{2}\], and the ellipse \[\frac{x^2}{9} + y^2\]=1. The region B is
bounded by the y-axis, the line y = mx, and the ellipse = \[\frac{x^2}{9} + y^2\]=1. Find m such that area of region A is the equal to the area of region B.

9. āĻāĻ•āϟāĻŋ n × n āĻĻāĻžāĻŦāĻžāĻŦā§‹āĻ°ā§āĻĄā§‡āϰ āĻĒā§āϰāϤāĻŋāϟāĻŋ āĻŦāĻ°ā§āĻ— āĻšāϝāĻŧ āϞāĻžāϞ āĻ…āĻĨāĻŦāĻž āϏāĻŦ⧁āϜāĨ¤ āĻŦā§‹āĻ°ā§āĻĄāϟāĻŋāϕ⧇ āĻāĻŽāύāĻ­āĻžāĻŦ⧇ āϰāĻ‚ āĻ•āϰāĻž āĻšāϝāĻŧ⧇āϛ⧇ āϝ⧇, āϝ⧇āϕ⧋āύ 2×2 āĻŦā§āϞāϕ⧇āϰ āϏāĻ‚āϞāĻ—ā§āύ āĻŦāĻ°ā§āϗ⧇āϰ āĻŽāĻ§ā§āϝ⧇ āĻ āĻŋāĻ• 2āϟāĻŋ āϏāĻŦ⧁āϜ āĻ“ āĻ āĻŋāĻ• 2āϟāĻŋ āϞāĻžāϞ āĻŦāĻ°ā§āĻ— āϰāϝāĻŧ⧇āϛ⧇āĨ¤ āĻ•āϤ⧋āĻ­āĻžāĻŦ⧇ āĻāχ āĻĻāĻžāĻŦāĻž āĻŦā§‹āĻ°ā§āĻĄāϟāĻŋāϕ⧇ āϰāĻ‚ āĻ•āϰāĻž āϝāĻžāĻŦ⧇āĨ¤ āϞāĻ•ā§āώ āĻ•āϰ⧋ āϝ⧇, 2×2 āĻĻāĻžāĻŦāĻžāĻŦā§‹āĻ°ā§āĻĄā§‡āϰ āϜāĻ¨ā§āϝ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋ āĻšāĻšā§āϛ⧇ 6 āĻāĻŦāĻ‚ 3×3 āĻŦā§‹āĻ°ā§āĻĄā§‡āϰ āĻŦ⧇āϞāĻžāϝāĻŧ āĻŽā§‹āϟ āωāĻĒāĻžāϝāĻŧ āĻšāϞ⧋ 14 āϝāĻž 23 āĻĨ⧇āϕ⧇ āĻŦāĻĄāĻŧāĨ¤
Problem 9: Each square of an nxn chessboard is either red or green. The board is colored such that in any 2×2 block of adjacent squares there are exactly 2 green squares and 2 red squares. How many ways can the chessboard be colored in this way? Note the number of ways for a 2×2 chessboard is 6 and the number of ways for a 3×3 chessboard is 14 which is bigger than 23.
10.āϏ⧂āĻ•ā§āĻˇā§āĻŽāϕ⧋āĻŖā§€ ABC āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āϞāĻŽā§āĻŦāϕ⧇āĻ¨ā§āĻĻā§āϰ HāĨ¤ āĻ¤ā§āϰāĻŋāϭ⧁āϜāϟāĻŋāϰ āĻĒāϰāĻŋāĻŦ⧃āĻ¤ā§āϤ⧇āϰ āϕ⧇āĻ¨ā§āĻĻā§āϰ K āĻāĻŦāĻ‚ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ R = 1āĨ¤ HK āĻāĻŦāĻ‚ BC āϰ⧇āĻ–āĻžāϰ āϛ⧇āĻĻāĻŦāĻŋāĻ¨ā§āĻĻ⧁ DāĨ¤ āĻĻ⧇āĻ“āϝāĻŧāĻž āφāϛ⧇, DK. (DK – DH) = 1āĨ¤ ABHC āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋āĨ¤
Problem 10: H is the orthocenter of acute triangle ABC. The triangle is inscribed in a circle with center K with radius R = 1. Let D is the intersection of the lines passing through HK and BC. Also, DK.(DK – DH) = 1. Find the area of the region ABHC.

 

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