BD math Olympiad 2024 regional questions

 

āĻŦāĻ—ā§ā§œāĻž āφāĻžā§āϚāϞāĻŋāĻ• āĻ—āĻŖāĻŋāϤ āĻ…āϞāĻŋāĻŽā§āĻĒāĻŋ⧟āĻžāĻĄ
āĻ•ā§āϝāĻžāϟāĻžāĻ—āϰāĻŋ: āĻĒā§āϰāĻžāχāĻŽāĻžāϰāĻŋ (ā§Šā§Ÿ -ā§ĢāĻŽ āĻļā§āϰ⧇āĻŖāĻŋ)

1. 5 āĻĨ⧇āϕ⧇ 15 āĻĒāĻ°ā§āϝāĻ¨ā§āϤ āϏāĻ•āϞ āĻœā§‹āĻĄāĻŧ āϏāĻ‚āĻ–ā§āϝāĻžāϰ āϝ⧋āĻ—āĻĢāϞ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋āĨ¤
Find the sum of all even numbers from 5 to 15.

2. 350 āĻāϰ āϏāĻžāĻĨ⧇ āĻ¨ā§āϝ⧂āύāϤāĻŽ āϕ⧋āύ āϧāύāĻžāĻ¤ā§āĻŽāĻ• āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻž āϝ⧋āĻ— āĻ•āϰāϞ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋ āĻāĻ•āϟāĻŋ āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻž āĻšāĻŦ⧇?(āϕ⧋āύ⧋ āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻž āĻāĻŽāύ āĻāĻ•āϟāĻŋ āĻŦāĻ°ā§āĻ—āϏāĻ‚āĻ–ā§āϝāĻž āĻĨāĻžāϕ⧇ āϝ⧇āϕ⧋āύ⧋ āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻž āĻāĻŦāĻ‚ āϐ āĻāĻ•āϟāĻŋ āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻžāϰ āϗ⧁āĻŖāĻĢāϞ⧇āϰ āφāĻ•āĻžāϰ⧇ āĻĒā§āϰāĻ•āĻžāĻļ āĻ•āϰāĻž āϝāĻžāϝāĻŧāĨ¤ āϝ⧇āĻŽāύāσ 25 = 5 × 5, 36 = 6 × 6 āχāĻ¤ā§āϝāĻžāĻĻāĻŋ )

What is the smallest integer that is to be added with 𝟑𝟓𝟎 so that it becomes a perfect square number? (A perfect square is a number that can be expressed as the product of an integer by itself. Such as: 𝟐𝟓 = 𝟓 × 𝟓, 𝟑𝟔 = 𝟔 × 𝟔 etc)

3. āĻœā§āϝ⧋āϤāĻŋ āĻāĻ•āϟāĻŋ āϰ⧇āĻ¸ā§āϟ⧁āϰ⧇āĻ¨ā§āĻŸā§‡ āĻ—āĻŋā§Ÿā§‡āϛ⧇, āϝ⧇āĻ–āĻžāύ⧇ āĻ“ā§ŸāĻžāχāĻĢāĻžāχ āϏ⧁āĻŦāĻŋāϧāĻž āφāϛ⧇āĨ¤ āϏ⧇ āĻ“ā§Ÿā§‡āϟāĻžāϰāϕ⧇ āĻ“ā§ŸāĻžāχāĻĢāĻžāĻ‡ā§Ÿā§‡āϰ āĻĒāĻžāϏāĻ“ā§ŸāĻžāĻ°ā§āĻĄā§‡āϰ āĻŦā§āϝāĻžāĻĒāĻžāϰ⧇ āϜāĻŋāĻœā§āĻžā§‡āϏ āĻ•āϰāĻžā§Ÿ, āϤāĻŋāύāĻŋ āύāĻŋāĻšā§‡āϰ āϚāĻŋāĻ¤ā§āϰāϕ⧁āϟāĻŋāϟāĻŋ āĻĻāĻŋāϞ⧇āύ āĻāĻŦāĻ‚ āĻŦāϞāϞ⧇āύ āϝ⧇ āĻĒāĻžāϏāĻ“ā§ŸāĻžāĻ°ā§āĻĄāϟāĻŋ āĻāĻ•āϟāĻŋ āϏāĻ‚āĻ–ā§āϝāĻžāĨ¤ *(āĻ¸ā§āϟāĻžāϰ) āϚāĻŋāĻšā§āύāĻŋāϤ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋ āĻĒāĻžāϏāĻ“ā§ŸāĻžāĻ°ā§āĻĄ āĻšāϞ⧇ āĻāĻŦāĻ‚ āĻĒā§āϰāϤāĻŋāϟāĻŋ āχāĻ‚āϰ⧇āϜāĻŋ āĻŦāĻ°ā§āĻŖ āĻāĻ•āϟāĻŋ āĻ•āϰ⧇ āĻ…āĻ•ā§āώāϰ āύāĻŋāĻ°ā§āĻĻ⧇āĻļ āĻ•āϰāϞ⧇, āĻĒāĻžāϏāĻ“ā§ŸāĻžāĻ°ā§āĻĄā§‡āϰ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋ āύāĻŋāĻ°ā§āϧāĻžāϰāĻŖ āĻ•āϰ⧋āĨ¤

BD math Olympiad 2024 regional questions

Juty went to a restaurant, where WiFi service is available. When she asked the waiter about the WiFi password, the waiter gave her the following piece of paper and told her that the password is a number. If the *(star) marked number is the password and each letter represents a digit, then find the number of the password.

4. 100 āĻāϰ āĻšā§‡ā§Ÿā§‡ āϛ⧋āϟ āĻāĻŽāύ āĻ•āϤāϟāĻŋ āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻžāĻœā§‹ā§œ āĻĒāĻžāĻ“ā§ŸāĻž āϝāĻžāĻŦ⧇, āϝāĻžāĻĻ⧇āϰ āĻŦāĻŋāϝ⧋āĻ—āĻĢāϞ āĻāĻ•āϟāĻŋ āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āĻšāĻŦ⧇?
How many prime-pair smaller than 100 are there, such that their difference is a prime number?

5. āĻĒā§āϰāϤāĻŋāϟāĻŋ āϞāĻžāχāύ āĻŦāϰāĻžāĻŦāϰ āϚāĻžāϰāϟāĻŋ āĻ­āĻŋāĻ¨ā§āύ āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϰ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋āϰ āϝ⧋āĻ—āĻĢāϞ 2024āĨ¤
āϝāĻĻāĻŋ a < b < c < d, b = \[\frac{a+c}{2}\] āĻāĻŦāĻ‚ d = c+5 āĻšā§Ÿ,
āϤāĻžāĻšāϞ⧇ d āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āϪ⧟ āĻ•āϰ⧋āĨ¤%Focuse keyword%

The sum of the four dots on each line is 𝟐𝟎𝟐𝟒. If 𝒂 <𝒃 < 𝒄 < 𝒅, 𝒃 = \[\frac{a+c}{2}\] and 𝒅 = 𝒄 + 𝟓, then find the value of 𝒅.

6. āϚāĻŋāĻ¤ā§āϰ⧇, DC = 8, CB = 4, BA = 8 āĻšāϞ⧇, āĻ›āĻžā§ŸāĻžāĻ•ā§ƒāϤ āĻ…āĻ‚āĻļāϟāĻŋāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āύāĻŋāĻ°ā§āϪ⧟ āĻ•āϰ⧋āĨ¤

%Focuse keyword%

In the figure, if đ‘Ģđ‘Ē = 𝟖, đ‘Ē𝑩 = 𝟒, 𝑩𝑨 = 𝟖, then find the area of the shadow marked region.

7. āĻāĻ•āϟāĻŋ āϧāĻžāϰāĻžāϰ n-āϤāĻŽ āĻĒāĻĻ āĻšāϤ⧇ n-1-āϤāĻŽ āĻĒāĻĻ⧇āϰ āĻŦāĻŋāϝ⧋āĻ—āĻĢāϞāϕ⧇ āĻĒāĻĻ āĻĻ⧁āχāϟāĻŋāϰ āϗ⧁āĻŖāĻĢāϞ āĻĨ⧇āϕ⧇ āĻŦāĻŋāϝ⧋āĻ— āĻ•āϰāϞ⧇ n+1-āϤāĻŽ āĻĒāĻĻ āĻĒāĻžāĻ“ā§ŸāĻž āϝāĻžā§ŸāĨ¤ āϧāĻžāϰāĻžāϟāĻŋāϰ āĻĒā§āϰāĻĨāĻŽ āĻĻ⧁āχāϟāĻŋ āĻĒāĻĻ 1 āĻ“ 2 āĻšāϞ⧇, 999-āϤāĻŽ āĻĒāĻĻ āύāĻŋāĻ°ā§āϪ⧟ āĻ•āϰ⧋āĨ¤

By subtracting the (𝒏 − 𝟏)th term of a series from the 𝒏th term and then subtracting the result from the product of those two terms, you can find the (𝒏 + 𝟏)th term of the series. If the first two terms are 𝟏 and 𝟐, then find the 𝟗𝟗𝟗th term.

8. OA = 4 āĻāĻŦāĻ‚ OBDF āĻŦāĻ°ā§āĻ— OD = 10āĨ¤ āĻ•āĻžāϞ⧋ āĻ…āĻ‚āĻļāϟāĻŋāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞāϕ⧇ \[\frac{a}{2} – b\pi\] āφāĻ•āĻžāϰ⧇ āϞ⧇āĻ–āĻž āϝāĻžā§ŸāĨ¤ a + b-āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āϪ⧟ āĻ•āϰ⧋āĨ¤

%Focuse keyword%

đ‘ļ𝑨 = 𝟒 and in the square đ‘ļ𝑩đ‘Ģ𝑭, đ‘ļđ‘Ģ = 𝟏𝟎. The area of the shadowed region can be written as \[\frac{a}{2} – b\pi\]. Find the value of 𝒂 + 𝒃.

āĻŦāĻ—ā§ā§œāĻž āφāĻžā§āϚāϞāĻŋāĻ• āĻ—āĻŖāĻŋāϤ āĻ…āϞāĻŋāĻŽā§āĻĒāĻŋ⧟āĻžāĻĄ
āĻ•ā§āϝāĻžāϟāĻžāĻ—āϰāĻŋ: āϜ⧁āύāĻŋ⧟āϰ (ā§ŦāĻˇā§āĻ  -ā§ŽāĻŽ āĻļā§āϰ⧇āĻŖāĻŋ)

1. āĻŽāĻžāĻœā§‡āĻĻ⧇āϰ āĻšāĻžāϤ⧇ āĻĻ⧁āϟāĻŋ āϜāĻžāĻĻ⧁āϰ āĻĒāĻžāĻĨāϰ āφāϛ⧇āĨ¤ āϤāĻžāĻĻ⧇āϰāϕ⧇ āĻāĻ•āĻŦāĻžāϰ āϘāώāĻž āĻĻāĻŋāϞ⧇ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ•āϟāĻŋ āĻĒāĻžāĻĨāϰ āĻĨ⧇āϕ⧇ āĻāĻ•āϟāĻŋ āĻ•āϰ⧇ āĻĒāĻžāĻĨāϰ āĻŦ⧇āϰ āĻšā§ŸāĨ¤ āĻĒāĻžāĻĨāϰ āϏāĻ‚āĻ–ā§āϝāĻž 100 āĻšāĻ“ā§ŸāĻžāϰ āϜāĻ¨ā§āϝ āĻ•āϤāĻŦāĻžāϰ āĻĒāĻžāĻĨāϰ āϘāώāϤ⧇ āĻšā§Ÿā§‡āĻ›āĻŋāϞ?

Majed has two magic stones in his hand. If they are rubbed once, a stone will come out from each stone. How many times the stones had to be rubbed to make the stone
number 𝟏𝟎𝟎?

2. āĻļ⧁āϧ⧁āĻŽāĻžāĻ¤ā§āϰ 16 āϏāĻ‚āĻ–ā§āϝāĻž āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰ⧇ 61 āĻŦāĻžāύāĻžāϤ⧇ āĻšāĻŦ⧇āĨ¤ āϏāĻšāĻžā§ŸāĻ• āĻšāĻŋāϏāĻžāĻŦ⧇ āϝ⧋āĻ—, āĻŦāĻŋāϝāĻŧā§‹āĻ—, āϗ⧁āĻŖ, āĻ­āĻžāĻ— āĻāĻŦāĻ‚ āĻŦāĻ°ā§āĻ—āĻŽā§‚āϞ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰāĻž āϝāĻžāĻŦ⧇āĨ¤ āĻāϟāĻž āĻ•āϰāϤ⧇ āϏāĻ°ā§āĻŦāύāĻŋāĻŽā§āύ āĻ•āϤāϟāĻŋ 16 āĻĒā§āĻ°ā§Ÿā§‹āϜāύ āĻšāĻŦ⧇? (āϧāĻžāϰāĻŖāĻ•ā§āώāĻŽ āϏāĻ‚āĻ–ā§āϝāĻž āωāĻ˛ā§āϞ⧇āĻ– āĻ•āϰ⧋āĨ¤)

𝟔𝟏 has to be made by only using the number 𝟏𝟔. Addition, subtraction, multiplication,division and square root can be used as helpers. Minimum how many 𝟏𝟔 will be needed for this? (Avoid negative numbers)

3. \[2^{20} \times 3^{10} \times 5^8\] āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋāϰ āĻ•āϤāϗ⧁āϞ⧋ āĻĒā§‚āĻ°ā§āĻŖ āϘāύ āĻ‰ā§ŽāĻĒāĻžāĻĻāĻ• āφāϛ⧇?

How many cubic factors does the number \[\(2^{20} \times 3^{10} \times 5^8\] have?

4. OA = 2 āĻāĻŦāĻ‚ OBDF āĻŦāĻ°ā§āĻ— OD = 8 āĨ¤ āĻ•āĻžāϞ⧋ āĻ…āĻ‚āĻļāϟāĻŋāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞāϕ⧇ \[\frac{a – \pi}{b}\] āφāĻ•āĻžāϰ⧇ āϞ⧇āĻ–āĻž āϝāĻžā§ŸāĨ¤ a + b-āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋āĨ¤

%Focuse keyword%

đ‘ļ𝑨 = 𝟐 and in the square đ‘ļ𝑩đ‘Ģ𝑭, đ‘ļđ‘Ģ = 𝟖. The area of the shadowed region can be written as 𝒂 − 𝝅𝒃. Find the value of 𝒂 + 𝒃.

5. āχāύāύ āĻāĻ•āϟāĻŋ āĻ•āĻžāĻšā§‡āϰ āĻ—ā§‹āϞāϕ⧇āϰ āĻ­āĻŋāϤāϰ āĻŦāĻ¨ā§āĻĻāĻŋāĨ¤ āϏ⧇ āĻ—ā§‹āϞāϕ⧇āϰ āĻĒ⧃āĻˇā§āϠ⧇āϰ āϏāĻžāĻĨ⧇ āĻĻāĻžāĻĄāĻŧāĻŋāϝāĻŧ⧇ āĻāĻ•āϟāĻŋ āϞ⧇āϜāĻžāϰ āϞāĻžāχāϟ āĻāĻŽāύāĻ­āĻžāĻŦ⧇ āϧāϰ⧇ āϝ⧇ āϤāĻž āĻ—ā§‹āϞāϕ⧇āϰ āĻ­āĻŋāϤāϰ⧇āϰ āĻĒ⧃āĻˇā§āϠ⧇ āĻāĻ•āϟāĻŋ āύāĻŋāĻ°ā§āĻĻāĻŋāĻˇā§āϟ āϕ⧋āϪ⧇ āĻŦāĻžāρāĻ• āĻšāϝāĻŧāĨ¤ āϝāĻĻāĻŋ \[\alpha = 60^\circ\] āĻšāϝāĻŧ, āϤāĻžāĻšāϞ⧇ āϞāĻžāχāϟāϟāĻŋ āĻ—ā§‹āϞāϕ⧇āϰ āĻĒ⧃āĻˇā§āϠ⧇ 2 āĻŦāĻžāϰ āĻŦāĻžāρāĻ• āύāĻŋāϝāĻŧ⧇ āχāύāĻžāύ⧇āϰ āĻ•āĻžāϛ⧇ āĻĢāĻŋāϰ⧇ āφāϏ⧇āĨ¤ \[\alpha = 20^\circ\] āĻšāϞ⧇, āϞāĻžāχāϟāϟāĻŋ āϏāĻ°ā§āĻŦāύāĻŋāĻŽā§āύ āĻ•āϤāĻŦāĻžāϰ āĻŦāĻžāρāĻ• āύāĻŋāϝāĻŧ⧇ āχāύāĻžāύ⧇āϰ āĻ•āĻžāϛ⧇ āĻĢāĻŋāϰ⧇ āφāϏāĻŦ⧇?

Emon is trapped inside a glass sphere. He stood against the surface of the sphere and held a laser beam so that it makes a particular angle with the inner surface of the sphere.If đœļ = 𝟔𝟎°, then the light reflects 𝟐 times on the surface of the sphere and returns to Emon. If đœļ = 𝟐𝟎°, then minimum how many number of turns will the light take to return to Emon?

6. āϚāĻŋāĻ¤ā§āϰ⧇āϰ āϤāĻŋāύāϟāĻŋ āϏāĻŽāĻžāύ āĻŦ⧃āĻ¤ā§āϤ āĻāϕ⧇ āĻ…āĻĒāϰāϕ⧇ āĻŦāĻšāĻŋāσāĻ¸ā§āĻĒāĻ°ā§āĻļ āĻ•āϰ⧇āĨ¤ āĻŦ⧃āĻ¤ā§āϤāϗ⧁āϞ⧋āϰ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ 8āĨ¤ āĻ—āĻžāĻĸāĻŧāĻ•ā§ƒāϤ āĻ…āĻ‚āĻļ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞāϕ⧇ \[a\sqrt{b} – c \pi\] āφāĻ•āĻžāϰ⧇ āĻĒā§āϰāĻ•āĻžāĻļ āĻ•āϰāĻž āϝāĻžāϝāĻŧāĨ¤ a + b + c-āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰ⧋āĨ¤

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The three circles in the figure externally touches each other. The radius of the circles are 𝟖. The area of the shaded region can be represented by \[a\sqrt{b} – c \pi\]. Find the value of 𝒂 + 𝒃 + 𝒄.

7. āĻāĻ•āϟāĻŋ āĻ•āĻžāϠ⧇āϰ āĻ•āĻŋāωāĻŦ, āϝāĻžāϰ āĻāĻ• āĻŦāĻžāĻšā§ n āĻāĻ•āĻ•, āϤāĻžāϰ āϏāĻŽāĻ¸ā§āϤ āϤāϞ⧇ āϞāĻžāϞ āϰāĻ™ āĻ•āϰāĻž āĻšāϞ⧋ āĻāĻŦāĻ‚ \[n^3 \] āϟāĻŋ āĻāĻ•āĻ• āĻ•āĻŋāωāĻŦ āĻ•āϰ⧇ āĻ•āĻžāϟāĻž āĻšāϞ⧋āĨ¤ āĻāĻ•āĻ• āĻ•āĻŋāωāĻŦāϗ⧁āϞ⧋āϰ āϤāϞ⧇āϰ āĻŽā§‹āϟ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻ āĻŋāĻ• āĻāĻ•-āĻ…āĻˇā§āϟāĻŽāĻžāĻ‚āĻļ āϞāĻžāϞāĨ¤ āĻāĻ•āĻ• āĻ•āĻŋāωāĻŦāϗ⧁āϞ⧋āϰ āĻ•āϤ āĻĒāĻžāĻļ⧇ āύāϤ⧁āύ āĻ•āϰ⧇ āϞāĻžāϞ āϰāĻ™ āĻ•āϰāϤ⧇ āĻšāĻŦ⧇, āϝ⧇āύ āϏ⧇āϗ⧁āϞ⧋āϰ āĻŽā§‹āϟ āĻĒāĻžāĻļ⧇āϰ āĻāĻ•-āϚāϤ⧁āĻ°ā§āĻĨāĻžāĻ‚āĻļ āϞāĻžāϞ āĻšāϝāĻŧ?

A wooden cube, 𝒏 unit on a side, is painted red on all faces and then cut into 𝒏𝟑 unit cubes. Exactly one-eighth portions of the total number of faces of unit cubes are red. How many sides of the smaller cubes need to be newly painted red, so that exactly onefourth portion of the total number of faces of the unit cubes are red?

8. āύāĻŋāϞāϝ āϚāĻŋāĻ¤ā§āϰ⧇āϰ āĻŽāϤ⧋ āĻĒā§āϝāĻžāϟāĻžāĻ°ā§āύ āφāρāĻ•āϞ⧇ M āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻāĻŦāĻ‚ N āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϰ āĻŽāĻžāĻā§‡ āĻĒāĻžāĻļāĻžāĻĒāĻžāĻļāĻŋ āĻĻā§‚āϰāĻ¤ā§āĻŦ a āĻāĻŦāĻ‚ āωāĻĒāϰ⧇āϰ āύāĻŋāĻšā§‡ āĻĻā§‚āϰāĻ¤ā§āĻŦ b āĻĒāĻžāĻ“ā§ŸāĻž āϝāĻžā§ŸāĨ¤ āĻāχ āĻĒā§āϝāĻžāϟāĻžāĻ°ā§āύ 1
āĻĨ⧇āϕ⧇ 2024 āĻĒāĻ°ā§āϝāĻ¨ā§āϤ āφāρāĻ•āĻž āĻšāϞ⧋ āĻāĻŦāĻ‚ a, b āĻāϰ āĻŽāĻžāύ āĻŦ⧇āϰ āĻ•āϰāĻž āĻšāϞ⧋āĨ¤ āĻĒāϰāĻŦāĻ°ā§āϤ⧀ āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇ \[\frac{b}{a}\] āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āϪ⧟ āĻ•āϰ⧋āĨ¤

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Niloy drew a pattern similar to that shown in the figure, the horizontal distance between the points 𝑴 and đ‘ĩ is ‘𝒂’ and the vertical distance between the points 𝑴 and đ‘ĩ is ‘𝒃’.This pattern is drawn from 𝟏 to 𝟐𝟎𝟐𝟒 and the value of 𝒂, 𝒃 is extracted. Find the value of \[\frac{b}{a}\] in the latter case.

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