Bd national math Olympiad questions of 2008

Primary Category
1. āĻĻ⧁āχāϟāĻŋ āĻĒāϰāĻĒāϰ āĻŦ⧇āĻœā§‹āĻĄāĻŧ āϏāĻ‚āĻ–ā§āϝāĻžāϰ āϗ⧁āĻŖāĻĢāϞ 143āĨ¤ āϏāĻ‚āĻ–ā§āϝāĻž āĻĻ⧁āχāϟāĻŋ āĻŦ⧇āϰ āĻ•āϰāĨ¤ (āϏāĻžāĻšāĻžāĻ¯ā§āϝ – āĻĒā§āϰāĻĨāĻŽ āĻŦ⧇āĻœā§‹āĻĄāĻŧ āϏāĻ‚āĻ–ā§āϝāĻž āĻšāϞ⧇ x āĻĒāϰ⧇āϰāϟāĻŋ āĻ•āϤ⧋? The product of two consecutive odd numbers is 143. Find the numbers. (Hint: If the first odd number is x, what is the next odd number?)
2. āĻŦāĻžāĻ¸ā§āϕ⧇āϟāĻŦāϞ āϞāĻŋāϗ⧇ āĻŽā§‹āϟ āĻĻāϞ⧇ 6 āĻ¸ā§āϕ⧁āϞ āĻ…āĻ‚āĻļ āύāĻŋāĻšā§āϛ⧇āĨ¤ āĻĒā§āϰāϤ⧋āĻ• āĻĻāϞ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ• āĻĻāϞ⧇āϰ āĻŦāĻŋāϰ⧁āĻĻā§āϧ⧇ āĻāĻ•āĻŦāĻžāϰ āĻ•āϰ⧇ āϖ⧇āϞāϛ⧇āĨ¤ āĻŽā§‹āϟ āĻ•āϝāĻŧāϟāĻŋ āϖ⧇āϞāĻž āĻ…āύ⧁āĻˇā§āĻ āĻŋāϤ āĻšāĻŦ⧇? There are six teams in a basketball league. Each team plays each other team only once during the season. How many total games will be played in the league during the season?
3. ⧧⧍ āϜāύ āϞ⧋āĻ• āĻ…āĻĨāĻŦāĻž ā§§ā§Ģ āϜāύ āĻŽāĻšāĻŋāϞāĻž ā§Ēā§Ē āĻĻāĻŋāύ⧇ āĻāĻ•āϟāĻŋ āĻ•ā§āώ⧇āϤ⧇āϰ āĻĢāϏāϞ āĻ•āĻžāϟāϤ⧇ āĻĒāĻžāϰ⧇āĨ¤ ā§Ž āϜāύ āϞ⧋āĻ• āĻ“ ⧧⧍ āϜāύ āĻŽāĻšāĻŋāϞāĻž āĻāĻ•āĻ¤ā§āϰ⧇ āϐ āĻŽāĻžāϠ⧇āϰ āĻĢāϏāϞ āĻ•āϤāĻĻāĻŋāύ⧇ āĻ•āĻžāϟāϤ⧇ āĻĒāĻžāϰāĻŦ⧇? 12 men or 15 women can reap a field in 44 days. In how many days, 8 men and 12 women will take to reap the given field?

4.Bd national math Olympiad questions of 2008

āĻ›āĻŦāĻŋ āĻĨ⧇āϕ⧇ āĻĻ⧇āĻ–āĻž āϝāĻžāĻšā§āϛ⧇ āϝ⧇, āĻāĻ• āĻ•āĻžāĻ āĻŋ āĻ­ā§‚āĻŽāĻŋ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻ¤ā§āϰāĻŋāϭ⧁āϜ āĻŦāĻžāύāĻžāϤ⧇ āĻ“āϟāĻŋ āĻŽā§āϝāĻžāϚ āĻ•āĻžāĻ āĻŋ āϞāĻžāϗ⧇, 2 āĻ•āĻžāĻ āĻŋ āĻ­ā§‚āĻŽāĻŋāϰ āϜāĻ¨ā§āϝ ā§­āϟāĻŋ āĻāĻŦāĻ‚ 3 āĻ•āĻžāĻ āĻŋāϰ āϜāĻ¨ā§āϝ 18āϟāĻŋ āĻ•āĻžāĻ āĻŋ āϞāĻžāϗ⧇āĨ¤ 7 āĻ•āĻžāĻ āĻŋ āϭ⧁āĻŽāĻŋ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻ¤ā§āϰāĻŋāϭ⧁āϜ āĻŦāĻžāύāĻžāϤ⧇ āĻ•āϝāĻŧāϟāĻŋ āĻŽā§āϝāĻžāĻšā§‡āϰ āĻ•āĻžāĻ āĻŋ āϞāĻžāĻ—āĻŦ⧇ ?
Referring to the sketches, it is seen that 3 matches are required to make the triangular pattern with a 1-match base, 9 matches are required to make the triangular pattern with a 2-match base, 18 matches are required to make the triangular pattern with a 3-match base. How many matches would be required to construct a similar figure with a 7-match base?
5. āĻāĻ•āϟāĻŋ āĻŦāĻ°ā§āĻ—āĻžāĻ•āĻžāϰ āĻŦāĻžāĻ—āĻžāύ⧇āϰ āϚāĻžāϰāĻĒāĻžāĻļ⧇ 1.5 āĻŽāĻŋāϟāĻžāϰ āϚāĻ“āĻĄāĻŧāĻž āĻāĻ•āϟāĻŋ āϰāĻžāĻ¸ā§āϤāĻž āϤ⧈āϰ⧀ āĻ•āϰāĻž āĻšāϞāĨ¤ āϰāĻžāĻ¸ā§āϤāĻžāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ 129 āĻŦāĻ°ā§āĻ—āĻŽāĻŋāϟāĻžāϰ āĻšāϞ⧇ āϰāĻžāĻ¸ā§āϤāĻž āĻŦāĻžāĻĻ⧇ āĻŦāĻžāĻ—āĻžāύ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻ•āϤ? A path 1.5 meters in width is laid all around a square lawn on the ouside. If the area of the path is 129 m2, then what is the area of the lawn (excluding the path?

6. āĻŦāĻžāĻŦ⧁āϞ, āĻŦāĻĻāϰ⧁āϞ āĻ“ āϜāϏāĻŋāĻŽ āĻāĻ•āχ āϏāĻŽāϝāĻŧ⧇ āĻāĻ•āϟāĻŋ āĻŦ⧃āĻ¤ā§āϤāĻžāĻ•āϰ āĻĒāĻĨ⧇ āĻĻ⧌āĻĄāĻŧāĻžāϤ⧇ āĻļ⧁āϰ⧁ āĻ•āϰāϞāĨ¤ āĻĒā§āϰāϤāĻŋ āĻŽāĻŋāύāĻŋāĻŸā§‡ āĻŦāĻžāĻŦ⧁āϞ \[\frac13\] āϚāĻ•ā§āĻ•āϰ, āĻŦāĻĻāϰ⧁āϞ \[\frac15\] āϚāĻ•ā§āĻ•āϰ āĻ“ āϜāϏāĻŋāĻŽ \[\frac16\] āϚāĻ•ā§āĻ•āϰ āĻĻ⧌āĻĄāĻŧāĻžāϤ⧇ āĻĒāĻžāϰ⧇āĨ¤ āϏāĻ°ā§āĻŦāύāĻŋāĻŽā§āύ āĻ•āϤ⧋ āϚāĻ•ā§āĻ•āϰ āĻĻ⧌āĻĄāĻŧāĻžāϞ⧇ āĻ“āϰāĻž āϏāĻŦāĻžāχ āĻāĻ•āχ āϏāĻ™ā§āϗ⧇ āĻĻ⧌āĻĄāĻŧ⧇āϰ āĻļ⧇āώ āϏ⧀āĻŽāĻžāϝāĻŧ āĻĒ⧌āĻ›āĻžāĻŦ⧇ ? Babul, Badrul and Jashim start at the same time at the start line. Babul runs \[\frac13\] rd lap per minute. Badrul runs \[\frac15\] th lap per min., and Jashim runs \[\frac16\] th lap per min. How many laps need to be run by all in order to cross the finish line at the same time?
7. āϕ⧋āύ āĻĒāϰ⧀āĻ•ā§āώāĻžāϝāĻŧ 24 āϜāύ āĻļāĻŋāĻ•ā§āώāĻžāĻ°ā§āĻĨā§€āϰ āĻ—āĻĄāĻŧ āύāĻŽā§āĻŦāϰ 42āĨ¤ āϝāĻĻāĻŋ āϝ⧇ āĻļāĻŋāĻ•ā§āώāĻžāĻ°ā§āĻĨā§€ ā§Ēā§Ē āĻĒ⧇āϝāĻŧ⧇āϛ⧇ āϏ⧇ āĻ…āύ⧁āĻĒāĻ¸ā§āĻĨāĻŋāϤ āĻĨāĻžāĻ•āϤ⧋ āϤāĻžāĻšāϞ⧇ āϤāĻžāĻĻ⧇āϰ āĻ—āĻĄāĻŧ āύāĻŽā§āĻŦāϰ āĻ•āϤ⧋ āĻšāϤ⧋? The average mark of 24 candidates taking an examination is 42. Find what the average mark would have been if one candidate, who scored 88, had been absent.
ā§Ē. āĻĻ⧁āχ āĻ…āĻ‚āϕ⧇āϰ āĻ•āϝāĻŧāϟāĻŋ āϏāĻ‚āĻ–ā§āϝāĻž āφāϛ⧇ āϝāĻžāϰ āĻ…āĻ™ā§āĻ•āĻĻā§āĻŦāϝāĻŧ⧇āϰ āĻ¸ā§āĻĨāĻžāύ āĻŦāĻŋāύāĻŋāĻŽāϝāĻŧ āĻ•āϰāϞ⧇ āϤāĻž 9 āĻŦ⧇āĻĄāĻŧ⧇ āϝāĻžāϝāĻŧ? How many two-digit integers are increased by exactly nine when the digits are reversed?
9. āϏ⧇āχ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋ āĻ•āϤ⧋ āϝāĻžāϕ⧇, āĻĒā§āϰāĻĨāĻŽā§‡ 3 āĻĻā§āĻŦāĻžāϰāĻž āϗ⧁āύ āĻ•āϰāĻž āĻšāϞ, āĻāϰāĻĒāϰ āĻāϰ āϏāĻ™ā§āϗ⧇ āϗ⧁āύāĻĢāϞ⧇āϰ āϤāĻŋāύ-āϚāϤ⧁āĻ°ā§āĻĨāĻžāĻ‚āĻļ āϝ⧋āĻ— āĻ•āϰāĻž āĻšāϞ, 7 āĻĻāĻŋāϝāĻŧ⧇ āĻ­āĻžāĻ— āĻ•āϰāĻž āĻšāϞ, āĻ­āĻžāĻ—āĻĢāϞ⧇āϰ āĻāĻ•-āϤ⧃āϤ⧀āϝāĻŧāĻžāĻ‚āĻļ āĻŦāĻžāĻĻ āĻĻ⧇āĻ“āϝāĻŧāĻž āĻšāϞ, āĻĒā§āϰāĻžāĻĒā§āϤ āϏāĻ‚āĻ–ā§āϝāĻž āĻĻāĻŋāϝāĻŧ⧇ āϗ⧁āύ āĻ•āϰāĻž āĻšāϞ, āĻŦāĻŋāϝāĻŧā§‹āĻ— āĻ•āϰāĻž āĻšāϞ 52, 8 āϝ⧋āĻ— āĻ•āϰ⧇ 10 āĻĻāĻŋāϝāĻŧ⧇ āĻ­āĻžāĻ— āĻ•āϰ⧇ āĻĒāĻžāĻ“āϝāĻŧāĻž āϗ⧇āϞ 2? Which is the number that, multiplied by 3, then increased by three-fourths of the product, divided by 7, diminished by one-third of the quotient, multiplied by itself, diminished by 52, the square root found, addition of 8, division by 10 gives the number 2?
10.200 āĻŽāĻŋāϟāĻžāϰ āĻĻā§€āĻ°ā§āϘ āĻāĻ•āϟāĻŋ āĻĻ⧌āĻĄāĻŧ āĻĒā§āϰāϤāĻŋāϝ⧋āĻ—āĻŋāϤāĻžāϝāĻŧ āφāϰāĻŽāĻžāύ āĻŽāĻžāύāĻŋāϕ⧇āϰ āĻšā§‡āϝāĻŧ⧇ 20 āĻŽāĻŋāϟāĻžāϰ āĻ“ āĻŦāĻŋāĻĨāĻŋāϰ āĻšā§‡āϝāĻŧ⧇ 29 āĻŽāĻŋāϟāĻžāϰ āĻāĻ—āĻŋāϝāĻŧ⧇ āĻĨ⧇āϕ⧇ āĻĻ⧌āĻĄāĻŧ āĻļ⧇āώ āĻ•āϰāϞ⧋āĨ¤ āϝāĻĻāĻŋ āϤāĻ–āύ⧋ āĻŽāĻžāύāĻŋāĻ• āĻ“ āĻŦāĻŋāĻĨā§€ āφāϗ⧇āϰ āĻ—āϤāĻŋāϤ⧇ āĻĻ⧌āĻĄāĻŧāĻžāϝāĻŧ āϤāĻžāĻšāϞ⧇ āĻŦāĻŋāĻĨāĻŋāϰ āĻ•āϤ⧋ āĻŽāĻŋāϟāĻžāϰ āφāϗ⧇ āĻŽāĻžāύāĻŋāĻ• āĻĻā§‹āĻĄāĻŧ āĻĒā§āϰāϤāĻŋāϝ⧋āĻ—āĻŋāϤāĻž āĻļ⧇āώ āĻ•āϰāĻŦ⧇? In a race of 200m, Arman finishes 20 m ahead of Manik and 29 m ahead of Bithi . If Manik and Bithi continue to run at their previous speeds, by how many meters will Manik finish ahead of Bithi ?

 

Junior Category 

1. āϤ⧋āĻŽāĻžāϕ⧇ āĻ…āĻĢ⧁āϰāĻ¨ā§āϤ 1×1, 2×2, 3×3, 4×4 5×5 36×6 āφāĻ•āĻžāϰ⧇āϰ āĻŦā§āϞāĻ• āĻĻ⧇āĻ“āϝāĻŧāĻž āĻšāϞāĨ¤ āĻ āĻĨ⧇āϕ⧇ 10āϟāĻŋ āĻŦā§āϞāĻ• āĻŦāĻžāĻ›āĻžāχ āĻ•āϰ⧋ āϝāĻžāϤ⧇ āĻŽā§‹āϟ āϕ⧇āĻ¤ā§āϰāĻĢāϞ 48 āĻšāϝāĻŧāĨ¤
You are given an unlimited supply of 1×1, 2×2, 3×3, 4×4 5×5, and 6×6 square. Find a set of 10 squares whose areas add
to 48.
2. āĻĢāĻžāϰāĻŋāϝāĻŧāĻž āϤāĻžāϰ āĻŽāϟāϰ āϏāĻžāχāϕ⧇āϞ⧇ āĻ•āϰ⧇ āύāĻžāϜāĻŋāϝāĻŧāĻžāϰ āĻŦāĻžāϏāĻžāϰ āĻĻāĻŋāϕ⧇ āϰāĻ“āύāĻž āĻšāϞāĨ¤ āĻāĻ•āχ āϏāĻŽāϝāĻŧ⧇ āύāĻžāϜāĻŋāϝāĻŧāĻžāĻ“ āϤāĻžāϰ āĻ—āĻžāĻĄāĻŧāĻŋāϤ⧇, āĻāĻ•āχ āϏ⧋āϜāĻž āϰāĻžāĻ¸ā§āϤāĻžāϝāĻŧ āĻĢāĻžāϰāĻŋāϝāĻŧāĻžāϰ āĻŦāĻžāϏāĻžāϰ āĻĻāĻŋāϕ⧇ āϰāĻ“āύāĻž āĻšāϞāĨ¤ āĻ•āϤāĻ• āϏāĻŽāϝāĻŧ āĻĒāϰ⧇ āϤāĻžāϰāĻž āϰāĻžāĻ¸ā§āϤāĻžāϝāĻŧ āύāĻŋāĻœā§‡āĻĻ⧇āϰ āĻ…āϤāĻŋāĻ•ā§āϰāĻŽ āĻ•āϰāϞ⧋, āϝāĻĻāĻŋāĻ“ āϕ⧇āω āĻ•āĻžāωāϕ⧇ āϞāĻ•ā§āώ āĻ•āϰ⧇āύāĻŋāĨ¤ āĻāϰ āĻ•āĻŋāϛ⧁āĻ•ā§āώāύ āĻĒāϰ⧇, āύāĻžāϜāĻŋāϝāĻŧāĻž āĻĢāĻžāϰāĻŋāϝāĻŧāĻžāϰ āĻŦāĻžāϏāĻžāϝāĻŧ āĻĒ⧌āρāϛ⧇ āĻĻ⧇āĻ–āϞ⧋ āĻĢāĻžāϰāĻŋāϝāĻŧāĻž āĻŦāĻžāϏāĻžāϝāĻŧ āύ⧇āχāĨ¤ āϤāĻ–āύ āϏ⧇ āϏ⧇āĻ–āĻžāύ⧇ 22 āĻŽāĻŋāύāĻŋāϟ āĻ…āĻĒ⧇āĻ•ā§āώāĻž āĻ•āϰāϞ⧋āĨ¤ āϤāĻžāϰāĻĒāϰ āϏ⧇ āφāĻŦāĻžāϰ āĻāĻ•āχ āϰāĻžāĻ¸ā§āϤāĻžāϝāĻŧ āύāĻŋāĻœā§‡āϰ āĻŦāĻžāϏāĻžāϰ āĻĻāĻŋāϕ⧇ āϰāĻ“āύāĻž āĻĻāĻŋāϞāĨ¤ āĻĢāĻžāϰāĻŋāϝāĻŧāĻž āφāϰ āύāĻžāϜāĻŋāϝāĻŧāĻž āĻĻ⧁āϜāύ⧇āχ āĻāĻ•āϏāĻ™ā§āϗ⧇ āύāĻžāϜāĻŋāϝāĻŧāĻžāϰ āĻŦāĻžāϏāĻžāϝāĻŧ āĻĒ⧌āρāĻ›āĻžāϞ⧋āĨ¤ āĻĢāĻžāϰāĻŋāϝāĻŧāĻžāϰ āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻ›āĻŋāϞ āϏāĻŦāϏāĻŽāϝāĻŧ āĻāĻ•āχāĨ¤ āĻ…āĻ¨ā§āϝāĻĻāĻŋāϕ⧇ āĻĢāĻžāϰāĻŋāϝāĻŧāĻžāϰ āĻŦāĻžāϏāĻžāϝāĻŧ āϝāĻžāĻ“āϝāĻŧāĻžāϰ āϏāĻŽāϝāĻŧ āύāĻžāϜāĻŋāϝāĻŧāĻžāϰ āĻ—āĻžāĻĄāĻŧāĻŋāϰ āĻ—āϤāĻŋ āĻ›āĻŋāϞ āĻĢāĻžāϰāĻŋāϝāĻŧāĻžāϰ āĻŽāϟāϰ āϏāĻžāχāϕ⧇āϞ⧇āϰ āĻ—āϤāĻŋāϰ 4 āϗ⧁āύ āφāϰ āĻĢ⧇āϰāĻžāϰ āĻĒāĻĨ⧇ 5 āϗ⧁āύāĨ¤ āύāĻžāϜāĻŋāϝāĻŧāĻžāϰ āĻŦāĻžāϏāĻžāϝāĻŧ āĻĒ⧌āρāĻ›āĻžāύ⧋āϰ āϜāĻ¨ā§āϝ āĻĢāĻžāϰāĻŋāϝāĻŧāĻžāϰ āĻ•āϤ⧋ āϏāĻŽāϝāĻŧ āϞ⧇āϗ⧇āϛ⧇āĨ¤

Faria sets of her bike to Nazia’s house. At exactly the same time, Nazia sets off to Faria’s house along the same straight road in her car. A while later, they pass each other (neither spotting the other) and shortly after, Nazia arrives at Faria’s house and find that she is not there. Nazia waits for 22 minutes and then heads back along the same road, arriving at her own place at exactly the same time as Faria. Faria traveled at the same speed the whole time whereas Nazia traveled 4 times as fast as Faria on the way to Faria’s house and 5 times as fast on the way back. How many minutes did it take Faria to reach Nazia’s house.

3. āύāĻŋāĻšā§‡āϰ āϧāĻžāϰāĻžāϰ āĻĻāĻļāĻŽ āĻĒāĻĻāϟāĻŋ āĻ•āϤ? n āϤāĻŽ āĻĒāĻĻāχ āĻŦāĻž āĻ•āϤ?

Find the 10th terms of the following sequence? What is the n-th term?
3,8,17,32,57…
4. p, 3-āĻāϰ āĻšā§‡āϝāĻŧ⧇ āĻŦāĻĄāĻŧ āĻāĻ•āϟāĻŋ āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻžāĨ¤ \[ p^2 \] āϕ⧇ 12 āĻĻā§āĻŦāĻžāϰāĻž āĻ­āĻžāĻ— āĻ•āϰāϞ⧇ āĻ•āϤ⧋ āĻ…āĻŦāĻļāĻŋāĻˇā§āϟ āĻĨāĻžāĻ•āĻŦ⧇?

p is a prime number and given that p>3. What be the reminder if \[ p^2 \] is divided by 12.
5. āϕ⧋āύ āĻāĻ•āϟāĻŋ āĻ¤ā§āϰāĻŋāĻ­ā§‚āĻœā§‡āϰ āϤāĻŋāύ āĻŦāĻžāĻšā§āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ a,b,cāĨ¤ āϝāĻĻāĻŋ \[ a^2 + b^2 + c^2 \] = ab + bc + ca āĻšāϝāĻŧ āϤāĻŦ⧇ āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰ āϝ⧇, āĻ¤ā§āϰāĻŋāĻ­ā§‚āϜāϟāĻŋ āϏāĻŽāĻŦāĻžāĻšā§āĨ¤

The three sides of a triangle are a,b,c . Given that \[ a^2 + b^2 + c^2 \] = ab + bc + ca. Prove that the triangle is equilateral.
6. āĻāĻ•āϟāĻŋ āφāϝāĻŧāϤāĻ•āĻžāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻ•āĻ°ā§āϪ⧇āϰ āĻāϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝāϰ āĻšā§‡āϝāĻŧ⧇ 2 āϏ⧇āĻŽāĻŋ āĻŦ⧇āĻļāĻŋāĨ¤ āϝāĻĻāĻŋ āĻāϰ āĻĒā§āϰāĻ¸ā§āϤ 10 āϏ⧇āĻŽāĻŋ āĻšāϝāĻŧ āϤāĻŦ⧇ āĻāϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻ•āϤ? The diagonal of a rectangle exceeds the length by 2 cm. If the width of the rectangle is 10 cm, find the length.
7. āĻāĻ•āϟāĻŋ āĻ­āĻžāϞ āϏāĻ‚āĻ–ā§āϝāĻž āĻšāϞ āĻĻ⧁āχāĻ…āĻ™ā§āϕ⧇āϰ āĻāĻ•āϟāĻŋ āϏāĻ‚āĻ–ā§āϝāĻž āϝāĻžāϰ āĻ…āĻ™ā§āĻ• āĻĻā§āĻŦāϝāĻŧ āĻ­āĻŋāĻ¨ā§āύ, āĻāĻŦāĻ‚ āĻāϰ āĻ…āĻĻā§āĻŦāϝāĻŧ āĻ¸ā§āĻĨāĻžāύ āĻŦāĻŋāύāĻŋāĻŽāϝāĻŧ āĻ•āϰāϞ⧇ āϝ⧇ āϏāĻ‚āĻ•ā§āϝāĻž āĻĒāĻžāĻ“āϝāĻŧāĻž āϝāĻžāϝāĻŧ āϤāĻžāϰ āϝ⧋āĻ—āĻĢāϞāĨ¤ āϝ⧇āĻŽāύ 110 = 37+73 āĻāĻ•āϟāĻŋ āĻ­āĻžāϞ āϏāĻ‚āĻ–ā§āϝāĻžāĨ¤ āĻ•āϤāϗ⧁āϞ⧋

A good number is the sum of a two-digit number, with distinct digits, and its reverse. For example, 110 = 37+73 is good. How many good numbers are perfect squares?
ā§Ē. 100-āĻāϰ āϛ⧋āϟ āϚāĻžāϰāϟāĻŋ āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āĻŦ⧇āϰ āĻ•āϰ⧋ āϝāĻž \[ 3^{32} – 2^{32}\] āĻāϰ āĻ‰ā§ŽāĻĒāĻžāĻĻāĻ•āĨ¤ Find four prime numbers less than 100 which are factors of \[ 3^{32} – 2^{32}\]
9. ABCD āĻāĻ•āϟāĻŋ āϚāϤ⧁āĻ°ā§āϭ⧁āϜāĨ¤ āĻāϰ AB āϰ⧇āĻ–āĻžāϝāĻŧ M āĻ“ N āĻĻ⧁āχāϟāĻŋ āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āϝāĻžāϤ⧇ AM=MN=NB āĻāĻŦāĻ‚ CD āϰ⧇āĻ–āĻžāϝāĻŧ āĻ“ Q āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āϝāĻžāϤ⧇ CP=PQ=QDI āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰ⧋ āϝ⧇, āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ AMCP = \[\frac13\] āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ ABCD In the convex quadrilateral ABCD, points M, N lie on the side AB such that AM = MN = NB, and points P, Q lie on the side CD such that CP PQ = QD. Prove that Area
of AMCP = \[\frac13\] Area of ABCD.
10. ABC āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡ D, E āĻ“ F āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ AB, BC āĻ“ CA āĻŦāĻžāĻšā§āϰ āĻ“āĻĒāϰ āĻ…āĻŦāĻ¸ā§āĻĨāĻŋāϤāĨ¤ āĻāĻŦāĻ‚ AD = DB, CE = 3BE āĻ“ AF = 2CF. āϝāĻĻāĻŋ ABC āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ 480 āĻŦāĻ°ā§āĻ— āϏ⧇āĻŽāĻŋ āĻšāϝāĻŧ āϤāĻŦ⧇ DEF āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ PO? In triangle ABC, points D, E, F are on sides AB, BC, CA respectively, with AD DB, CE = 3BE and AF = 2CF. If the area of triangle ABC is 480 square cm, then find the area of the triangle DEF.

%Focuse keyword%

Secondary Category

1. āĻĒā§āϰāĻĨāĻŽ 2008āϟāĻŋ āϧāύāĻžāĻ¤ā§āĻŦāĻ• āĻœā§‹āĻĄāĻŧ āϏāĻ‚āĻ–ā§āϝāĻžāϰ āϝ⧋āĻ—āĻĢāϞ āĻĨ⧇āϕ⧇ āĻĒā§āϰāĻĨāĻŽ 2008āϟāĻŋ āĻŦ⧇āĻœā§‹āĻĄāĻŧ āϏāĻ‚āĻ–ā§āϝāĻžāϰ āϝ⧋āĻ—āĻĢāϞ āĻŦāĻŋāϝāĻŧā§‹āĻ— āĻ•āϰāĻž āĻšāϞāĨ¤ āĻŦāĻŋāϝāĻŧā§‹āĻ—āĻĢāϞ āĻ•āϤ⧋ ? The sum of the first 2008 odd positive integer is subtracted from the sum of the first 2008 even positive integers. Find the result.
2. āĻāĻ•āϟāĻŋ āĻŽā§āĻĻā§āϰāĻžāϰ āĻĒāĻŋāϠ⧇1, āĻĻ⧁āχāϟāĻŋ āĻ­āĻŋāĻ¨ā§āύ āĻŽā§āĻĻā§āϰāĻžāϰ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ•āϟāĻŋāϰ āĻĒāĻŋāϠ⧇ 2, āϤāĻŋāύāϟāĻŋ āĻ­āĻŋāĻ¨ā§āύ āĻŽā§āĻĻā§āϰāĻžāϰ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ•āϟāĻŋāϰ āĻĒāĻŋāϠ⧇ 3, , āωāύāĻĒāĻžā§āϚāĻžāĻļāϟāĻŋ āĻ­āĻŋāĻ¨ā§āύ āĻŽā§āĻĻā§āϰāĻžāϰ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ•āϟāĻŋāϰ āĻĒāĻŋāϠ⧇ 49 āĻāĻŦāĻ‚ āĻĒāĻžā§āϚāĻžāĻļāϟāĻŋ āĻ­āĻŋāĻ¨ā§āύ āĻŽā§āĻĻā§āϰāĻžāϰ āĻĒā§āϰāĻ¤ā§āϝ⧇āĻ•āϟāĻŋāϰ āĻĒāĻŋāϠ⧇ 50 āϞāĻŋāĻ–āĻž āφāϛ⧇āĨ¤ āϏāĻŦāϗ⧁āϞ⧋ āĻŽā§āĻĻā§āϰāĻžāϕ⧇ āĻāĻ•āϟāĻŋ āĻ•āĻžāϞ⧋ āĻŦā§āϝāĻžāϗ⧇ āϰ⧇āϖ⧇ āϏ⧇āĻ–āĻžāύ āĻĨ⧇āϕ⧇ āĻĻ⧈āĻŦāϚāϝāĻŧāύ⧇ āĻāĻ•āϟāĻŋ āĻāĻ•āϟāĻŋ āĻ•āϰ⧇ āĻŽā§āĻĻā§āϰāĻž āύ⧇āĻ“āϝāĻŧāĻž āĻšāϞāĨ¤ āĻ•āĻŽāĻĒāĻ•ā§āώ⧇ āĻ•āϝāĻŧāϟāĻŋ āĻŽā§āĻĻā§āϰāĻž āύāĻŋāϞ⧇ āύāĻŋāĻļā§āϚāϤ āĻšāĻ“āϝāĻŧāĻž āϝāĻžāĻŦ⧇ āϝ⧇, āϝ⧇ āϕ⧋āύ āĻāĻ• āĻĒā§āϰāĻ•āĻžāϰ⧇āϰ āĻ…āĻ¨ā§āϤāϤ 10āϟāĻŋ āĻŽā§āĻĻā§āϰāĻž āĻ“āĻ āĻžāύ⧋ āĻšāϝāĻŧ⧇āϛ⧇? One coin is labeled with the number 1, two different
coins are labeled with the number 2, three different coins are labeled with the number 3,…,forty-nine different coins are labeled with the number 49, and fifty different coins are labeled with the number 50. All of these coins are then put into a black bag. The coins are then randomly drawn one by one. We need 10 coins of any type. What is the minimum number of coins that must be drawn to make sure that we have at least 10 coins of one type ?
3. āϧāϰāĻž āϝāĻžāĻ• a āĻāĻ•āϟāĻŋ āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻžāĨ¤ āφāĻŦāĻžāϰ m = 4a + 3 āĻ“ m, 11-āĻāϰ āϗ⧁āύāĻŋāϤāĻ•āĨ¤ \[ a^4 \] āϕ⧇ 11 āĻĻā§āĻŦāĻžāϰāĻž āĻ­āĻžāĻ— āĻ•āϰāĻž āĻšāϞ⧇ āĻ•āϤ⧋ āĻ…āĻŦāĻļāĻŋāĻˇā§āϟ āĻĨāĻžāĻ•āĻŦ⧇? āĻŦāĻŋāĻ¸ā§āϤāĻžāϰāĻŋāϤ āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰāĨ¤ Let a be an integer. The number m which has the form m = 4a + 3 is a multiple of 11. If we divide \[ a^4 \] by 11, what is the remainder ? Show with proof.

4. f(x) āĻāĻ•āϟāĻŋ āϜāϟāĻŋāϞ āύāύ-āϞāĻŋāύāĻŋāϝāĻŧāĻžāϰ āĻĢāĻžāĻ‚āĻļāύāĨ¤ f(x)+ f(1-x)=1 āĻšāϞ⧇ \[ \int_0^1 \]f(x)dx -āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āĻŖāϝāĻŧ āĻ•āϰāĨ¤ The function f(x) is a complicated nonlinear function. It satisfies, f(x)+ f(1-x) = 1. Evaluate\[ \int_0^1 \]f(x)dx.
5. āφāϏāĻŽāĻž āĻ“ āϤāĻžāϰ āĻ­āĻžāχ āφāĻšāĻŽā§‡āĻĻ āĻĻāĻžāĻŦāĻž āϖ⧇āϞ⧋āϝāĻŧāĻžāĻĄāĻŧāĨ¤ āĨ¤ āφāϏāĻŽāĻžāϰ āϛ⧇āϞ⧇ āĻļāĻžāĻŽā§€āĻŽ āĻ“ āĻŽā§‡āϝāĻŧ⧇ āĻļāĻžāϰāĻŽā§€āύāĻ“ āĻĻāĻžāĻŦāĻž āϖ⧇āϞ⧇āĨ¤ āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āĻ–āĻžāϰāĻžāĻĒ āϖ⧇āϞ⧋āϝāĻŧāĻžāĻĄāĻŧ⧇āϰ āϝāĻŽāϜ (āϐ āϚāĻžāϰāϜāύ⧇āϰ āĻāĻ•āϜāύ) āĻāĻŦāĻ‚ āϏ⧇āϰāĻž āϖ⧇āϞ⧋āϝāĻŧāĻžāĻĄāĻŧ āĻĒāϰāĻ¸ā§āĻĒāϰ āĻŦāĻŋāĻĒāϰ⧀āϤ āϞāĻŋāĻ™ā§āϗ⧇āϰāĨ¤ āĻ–āĻžāϰāĻžāĻĒ āĻāĻŦāĻ‚ āϏ⧇āϰāĻž āϖ⧇āϞ⧋āϝāĻŧāĻžāĻĄāĻŧ⧇āϰ āĻāĻ•āχ āĻŦāϝāĻŧāϏāĨ¤ āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āĻ–āĻžāϰāĻžāĻĒ āϖ⧇āϞ⧇ āϕ⧇ ?
Asmaa, and her brother Ahmed are chess players. Asmaa’s son Shamim and her daughter Sharmeen are also chess players. The worst player’s twin (who is one of the 4 chess players) and best player are of the opposite sex. The worst player and the best player are the same age. Who is the worst player?

6. 1,2 3 3 āĻāχ āϤāĻŋāύāϟāĻŋ āĻ…āĻ™ā§āĻ• āĻĻāĻŋāϝāĻŧ⧇ āĻāĻ•āϟāĻŋ 5 āĻ…āĻ™ā§āĻ• āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āϏāĻ‚āĻ–ā§āϝāĻž āϤ⧈āϰāĻŋ āĻ•āϰāĻž āĻšāϞāĨ¤ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋāϤ⧇ āĻ•āĻŽāĻĒāĻ•ā§āώ⧇ 1,2 3 3 āĻāĻ•āĻŦāĻžāϰ āĻ•āϰ⧇ āφāϛ⧇āχāĨ¤ āĻāϰāĻ•āĻŽ āĻ•āϤ⧋āϟāĻŋ 5 āĻ…āĻ™ā§āĻ• āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āϏāĻ‚āĻ–ā§āϝāĻž āϤ⧈āϰāĻŋ āĻ•āϰāĻž āϝāĻžāĻŦ⧇? (āϏāĻžāĻšāĻžāĻ¯ā§āϝ āϝ⧇ āϏāĻŦ āϏāĻ‚āĻ–ā§āϝāĻžāϰ āĻŽāĻ§ā§āϝ⧇ 1,2 3 3 āύ⧇āχ āϏ⧇āϗ⧁āϞ⧋ āĻĒā§āϰāĻĨāĻŽā§‡ āĻ—āĻŖāύāĻž āĻ•āϰāĻž āϝ⧇āϤ⧇ āĻĒāĻžāϰ⧇āĨ¤ The three numbers 1,2,3 are used to make a 5 digit number. The five digit number must contain at least one 1, at least one 2, and at least one 3. How many such five digit numbers can be made? (Hint: First count the number of words missing either a 1 or a 2 or a 3.)

7. \[1+5.2^m = n^2\] āϏāĻŽā§€āĻ•āϰāϪ⧇āϰ āĻĒā§‚āĻ°ā§āĻŖāϏāĻ‚āĻ–ā§āϝāĻžāϰ āϏāĻŽāĻžāϧāĻžāύ (m,n) āĻŦ⧇āϰ āĻ•āϰāϤ⧇ āĻšāĻŦ⧇āĨ¤ (A) \[n^2 −1\]? (B) (n+1) āĻ“ (n −1) āĻāϰ āωāĻ­āϝāĻŧāχ āĻœā§‹āĻĄāĻŧ āύāĻž āĻŦ⧇āĻœā§‹āĻĄāĻŧ, āύāĻžāĻ•āĻŋ āĻāĻ•āϟāĻŋ āĻœā§‹āĻĄāĻŧ āφāϰ āĻ…āĻĒāϰāϟāĻŋ āĻŦ⧇āĻœā§‹āĻĄāĻŧ āϤāĻž āĻŦ⧇āϰ āĻ•āϰāĨ¤ (C) āϝāĻĻāĻŋ \[a = \frac{n – 1}{2} \] āĻšāϝāĻŧ āϤāĻŦ⧇ a(a+1) =? (D) āϝāĻĻāĻŋ āĻŦ⧇āĻœā§‹āĻĄāĻŧ āĻšāϝāĻŧ āϤāĻŦ⧇ a+1 āĻœā§‹āĻĄāĻŧ āύāĻž āĻŦ⧇āĻœā§‹āĻĄāĻŧ? (E) (C) āĻ“ (D) āĻĨ⧇āϕ⧇ āĻŦāϞ a = 1 āĻŦāĻž a+1=1 āĻšāĻ“āϝāĻŧāĻž āϕ⧀ āϏāĻŽā§āĻ­āĻŦ? (F) a-āĻāϰ āĻ“āĻ•āĻŽāĻžāĻ¤ā§āϰ āϏāĻŽā§āĻ­āĻžāĻŦā§āϝ āĻŽāĻžāύāϟāĻŋ āĻŦ⧇āϰ āĻ•āϰ⧋ āĻāĻŦāĻ‚ ” āĻ“ ” āϕ⧀ āĻšāĻ“āϝāĻŧāĻž āωāϚāĻŋā§Ž āϤāĻž āĻŦ⧇āϰ āĻ•āϰ⧋āĨ¤
We want to find all integer solutions (m, n) to \[1+5.2^m = n^2\]. First: (A) Find an expression for \[n^2 −1\]?; ( B ) are ( n + 1 ) and (n-1) both even n-1 or both odd, or is one even and the other odd? (C) Let \[a = \frac{n – 1}{2} \] Find an expression for a(a+1); (D) If a is odd, is a + 1 even or odd ? (E) From parts (C) and (D), is it possible for a = 1, or a(a + 1) = ? (F) Find the only possible values a can take and then find what m and n should be.
ā§Ē. ABCD āϚāϤ⧁āĻ°ā§āϭ⧁āĻœā§‡āϰ āĻ•āĻ°ā§āĻŖāĻĻā§āĻŦāϝāĻŧ AC āĻ“ BD, E āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āϛ⧇āĻĻ āĻ•āϰ⧇āϛ⧇āĨ¤ AB = 39; AE = 45; AD = 60; BC = 56 āĻšāϞ⧇ CD=? ABCD is a convex quadrilateral. The diagonals AC and BD intersect at E. AB = 39; AE = 45; AD = 60; BC = 56. Find the length of CD.

9: ABCD āϚāϤ⧁āĻ°ā§āϭ⧁āĻœā§‡āϰ AB = BC = CD āϤāĻŦ⧇ AC<>BD. āϚāϤ⧁āĻ°ā§āϭ⧁āĻœā§‡āϰ āĻ•āĻ°ā§āĻŖāĻĻā§āĻŦāϝāĻŧ⧇āϰ āϛ⧇āĻĻāĻŦāĻŋāĻ¨ā§āĻĻ⧁ E. AE= DE 4 <BAD+<ADC=0,0=? Let ABCD be a convex quadrilateral with AB = BC= CD. Note, AC <> BD. Let E be the intersection point of the diagonals of ABCD. AE = DE if <BAD+<ADC=0, Find e
Problem 10: A quadrilateral ABCD with ∠BAD + ∠ADC > 180 circumscribes a circle of center l. A line through l meets AB and CD at points X and Y respectively.
If IX=IY then what is (AX Âĸ DY)=(BX Âĸ CY)?

 

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