BD national math olympiad questions 2006
Q1. āϏāĻŦāĻā§āϝāĻŧā§ āĻā§āĻ āĻā§āύ āϏāĻāĻā§āϝāĻžāĻā§ 2,3,4,5,6,7,8,9 āĻāĻŦāĻ 10 āĻĻāĻŋāϝāĻŧā§ āĻāĻžāĻ āĻāϰāϞ⧠āĻāĻžāĻāĻļā§āώ 1 āĻšāϝāĻŧ?
Find the smallest number that gives the remainder 1 if divided by 2,3,4,5,6,7,8,9 and 10.Â
Q2. āϏā§āϞāĻŋāĻŽ 10 āĻāĻžāĻāĻžāϝāĻŧ 3āĻāĻŋ āĻĒā§āύā§āϏāĻŋāϞ āĻāĻŋāύā§, 10 āĻāĻžāĻāĻžāϝāĻŧ 2āĻāĻŋ āĻŦāĻŋāĻā§āϰāϝāĻŧ āĻāϰāϞ⧠āϤāĻžāϰ āĻļāϤāĻāϰāĻž āĻāϤ āĻāĻžāĻāĻž āϞāĻžāĻ āĻŦāĻž āĻā§āώāϤāĻŋ āĻšāĻŦā§?
Selim buys 3 pencils for 10 taka and sells 2 pencils for 10 taka, what will be his profit or loss in percentage?
Q3. āĻāϞāĻŽ āύāĻž āϤā§āϞ⧠āĻāĻŦāĻ āĻāĻāĻāĻŋ āϰā§āĻāĻžāϰ āĻāĻĒāϰ āĻĻāĻŋāϝāĻŧā§ āĻĻā§āĻāĻŦāĻžāϰ āύāĻž āĻāĻŋāϝāĻŧā§ āĻā§āύāĻāĻž āĻāĻāĻāĻž āϏāĻŽā§āĻāĻŦ āĻāĻŦāĻ āĻā§āύāĻāĻž āĻāĻāĻž āϏāĻŽā§āĻāĻŦ āύāϝāĻŧ?

Which one of the figures can you draw without lifting the pen or retracing a line?
Q4. āĻāĻ āϏā§āĻā§āϞ⧠āϤāĻŋāύāĻāύ āĻāĻžāϤā§āϰāĻā§ 7000 āĻāĻžāĻāĻžāϰ āĻŦā§āϤā§āϤāĻŋ āĻĻā§āĻāϝāĻŧāĻž āĻšāϞ āĨ¤ āĻĒā§āϰāĻĨāĻŽ āĻāύ āϝ⧠āĻāĻžāĻāĻž āĻĒā§āϞ, āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āĻāύ āĻĒā§āϞ āϤāĻžāϰ āĻ āϰā§āϧā§āĻ āĻāĻŦāĻ āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āĻāύ āϝ⧠āĻāĻžāĻāĻž āĻĒā§āϞ āϤā§āϤā§āϝāĻŧ āĻāύ āĻĒā§āϞ āϤāĻžāϰ āĻ āϰā§āϧā§āĻ āĨ¤ āĻā§ āĻāϤ āĻāĻžāĻāĻž āĻĒā§āϞ?
Three students from a school got scholarship of 7000 taka. The second student got half of the amount of the first person and the third student got half of the amount of the second person. Find the amount of scholarship of the three individual students.
Q5. āĻāĻāĻāĻŋ 1000 āĻŦāϰā§āĻ āĻŽāĻŋāĻāĻžāϰ āĻŦāϰā§āĻāĻžāĻā§āϤāĻŋ āĻĒā§āĻā§āϰā§āϰ āĻāĻžāϰāĻā§āύāĻžāϝāĻŧ āĻāĻžāϰāĻāĻŋ āĻāĻžāĻ āϰāϝāĻŧā§āĻā§āĨ¤ āĻāĻžāĻāĻā§āϞā§āĻā§ āύāĻž āĻā§āĻā§ āĻāĻŦāĻŋāϤ⧠āϝā§āĻāĻžāĻŦā§ āĻĻā§āĻāĻžāύ⧠āĻšāϝāĻŧā§āĻā§ āϏā§āĻāĻžāĻŦā§ āĻĒā§āĻā§āϰāĻāĻŋāĻā§ āĻŦāϰā§āĻāĻžāĻā§āϤāĻŋāϤ⧠āĻā§āĻā§ āĻŦāĻĄāĻŧ āĻāϰāĻž āĻšāϞāĨ¤ āĻāĻāύ āĻĒā§āĻā§āϰāĻāĻŋāϰ āĻā§āώā§āϤā§āϰāĻĢāϞ āĻāϤā§?

A1000 sqm square pond had four threes at the four corners. The pond was enlarged to a new square without cutting down the trees as shown in the figure. Find the area of the enlarged pond.
Q6. āĻāĻāĻāĻŋ āϏāĻžāĻŽāĻžāύā§āϤāϰāĻŋāĻā§āϰ āϏāύā§āύāĻŋāĻšāĻŋāϤ āĻŦāĻžāĻšā§ āĻĻā§’āĻāĻŋāϰ āĻĻā§āϰā§āĻā§āϝ 8 cm āĻ 6 cmāĨ¤ āϏāĻžāĻŽāĻžāύā§āϤāϰāĻŋāĻāĻāĻŋāϰ āĻāĻāĻāĻŋ āĻļā§āϰā§āώāĻŦāĻŋāύā§āĻĻā§ āĻĨā§āĻā§ 8 cm āĻŦāĻŋāĻļāĻŋāώā§āĻ āĻŦāĻžāĻšā§āϰ āĻāĻĒāϰ āϞāĻŽā§āĻŦ āĻĻā§āϰāϤā§āĻŦ 3 cm āĻšāϞ⧠āĻāĻāĻ āĻļā§āϰā§āώ āĻŦāĻŋāύā§āĻĻā§ āĻĨā§āĻā§ āĻ
āύā§āϝ āĻŦāĻžāĻšā§āϰ āĻāĻĒāϰ āϞāĻŽā§āĻŦ āĻĻā§āϰāϤā§āĻŦ āĻŦā§āϰ āĻāϰ?
The adjacent edges of a parallelogram are 8 cm and 6 cm respectively. If the perpendicular distance of the 8 cm edge from a vertex is 3 cm, find the perpendicular distance to the other edge from the same vertex.
Q7. 1+2+5+6+9+10+13+14+… āϧāĻžāϰāĻžāĻāĻŋāϰ āĻĒāĻĨāĻŽ 100 āĻĒāĻĻā§āϰ āϝā§āĻāĻĢāϞ āĻāϤ? [āϏāĻžāĻšāĻžāϝā§āϝ : āĻĻā§’āĻāĻŋ āĻĻā§’āĻāĻŋ āĻĒāĻĻ āύāĻŋāϝāĻŧā§ āϝā§āĻ āĻāϰ]
Find the sum of the first 100 terms of the series 1+2+5+6+9+10+13+14+…… [Hint: Add every two terms]
Q8. 1 āĻĨā§āĻā§ āĻļā§āϰ⧠āĻāϰ⧠9 āĻĒāϰā§āϝāύā§āϤ āĻā§āϰāĻŽāĻŋāĻ āϏāĻāĻā§āϝāĻž āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰ⧠āĻāĻāĻāĻŋ āĻŽā§āϝāĻžāĻāĻŋāĻ āϏā§āĻāϝāĻŧāĻžāϰ āϤā§āϰāĻŋ āĻāϰāĻž āĻšāϝāĻŧā§āĻā§ āϝā§āĻāĻžāύ⧠āϏāĻāĻā§āϝāĻžāĻā§āϞ⧠āĻāĻĒāϰ āĻĨā§āĻā§ āύāĻŋāĻā§, āĻŦāĻžāĻŽ āĻĨā§āĻā§ āĻĄāĻžāύ⧠āĻāĻŋāĻāĻŦāĻž āĻā§āύāĻžāĻā§āύāĻŋ āϝā§āĻāĻžāĻŦā§āĻ āϝā§āĻ āĻāϰāĻž āĻšā§āĻ āύāĻž āĻā§āύ āϝā§āĻāĻĢāϞ āĻšāĻŦā§ 15āĨ¤ āϤā§āĻŽāĻŋ āĻāĻāĻžāĻŦā§ āĻ āύā§āϝ āύāϝāĻŧāĻāĻŋ āĻā§āϰāĻŽāĻŋāĻ āϏāĻāĻā§āϝāĻž āĻŦā§āϰ āĻāϰ⧠āĻāϰā§āĻāĻāĻŋ āĻŽā§āϝāĻžāĻāĻŋāĻ āϏā§āĻāϝāĻŧāĻžāϰ āϤā§āϰ⧠āĻāϰ⧠āϝāĻžāϰ āϝā§āĻāĻĢāϞ āϏāĻŦāϏāĻŽāϝāĻŧā§āĻ āĻšāĻŦā§ 27 āĨ¤

Successive integers from 1 to 9 were used to construct a magic square such that the sum of the three numbers is always 15 if added vertically, horizontally or diagonally. Construct a similar magic square using 9 different successive integers such that the sum is always 27.
Q9. āĻāĻāĻāĻŋ āĻāĻžāĻāĻ \[\frac18\] mm āĻĒā§āϰā§, āĻāĻžāĻāĻāĻāĻŋāĻā§ āĻāĻŦāĻŋāϤ⧠āĻĻā§āĻāĻžāύ⧠āĻāĻĒāĻžāϝāĻŧā§ ā§Ē āĻŦāĻžāϰ āĻāĻžāĻ āĻāϰāϞ⧠āĻāϤā§āĻā§āĻā§ āĻĒā§āϰ⧠āĻšāĻŦā§?

If a paper of thickness \[\frac18\] mm is folded 8 times in the way shown below, what will be the total thickness?
Q10. 1 + \[\frac12 + \frac14 + \frac18 + ………\] āϧāĻžāϰāĻžāĻāĻŋāϤ⧠āĻĒāϰā§āϰ āĻĒāĻĻāĻāĻŋ āĻāĻā§āϰ āĻĒāĻĻā§āϰ āĻ
āϰā§āϧā§āĻ (\[\frac12\]), āĻāϰāĻāĻŽ āϧāĻžāϰāĻžāϰ āϝā§āĻāĻĢāϞ \[\frac{1}{1- \frac12}\] āϧāĻžāϰāĻžāĻāĻŋāϰ āϝā§āĻāĻĢāϞ āĻšāϤ⧠( āĻāϰāĻāĻŽ āϝāĻĻāĻŋ āĻĒāϰā§āϰ āĻĒāĻĻāĻāĻŋ āĻāĻā§āϰ āĻĒāĻĻā§āϰ āĻāĻ āϤā§āϤā§āϝāĻŧāĻžāĻāĻļ (\[\frac13\]) āĻšāϤ⧠āϤāĻžāĻšāϞ⧠\[\frac{1}{1- \frac13}\] , āĻāϤā§āϝāĻžāĻĻāĻŋ)
1m āĻŦāĻžāĻšā§ āĻŦāĻŋāĻļāĻŋāώā§āĻ āĻāĻāĻāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āϤā§āϰāĻŋāĻā§āĻā§āϰ āĻŽāϧā§āϝāĻŦāĻŋāύā§āĻĻā§ āϤāĻŋāύāĻāĻŋ āϝā§āĻ āĻāϰ⧠āĻāϰā§āĻāĻāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āϤā§āϰāĻŋāĻā§āĻ āĻāĻāĻž āϝāĻžāϝāĻŧāĨ¤ āϏā§āĻ āϏāĻŽāĻŦāĻžāĻšā§ āϤā§āϰāĻŋāĻā§āĻā§āϰ āĻŽāϧā§āϝāĻŦāĻŋāύā§āĻĻā§āĻā§āϞ⧠āϝā§āĻ āĻāϰ⧠āĻāϰā§āĻāĻāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āϤā§āϰāĻŋāĻā§āĻ āĻāĻāĻž āϝāĻžāϝāĻŧāĨ¤ āϝāĻĻāĻŋ āĻāĻāĻžāĻŦā§ āĻā§āϰāĻŽāĻžāĻāϤ āĻ
āϏā§āĻŽ āϏāĻāĻā§āϝāĻ āϏāĻŽāĻŦāĻžāĻšā§ āϤā§āϰāĻŋāĻā§āĻ āĻāĻāĻž āĻšāϝāĻŧ āϤāĻžāĻšāϞ⧠āϏāĻŦāĻā§āϞ⧠āϤā§āϰāĻŋāĻā§āĻā§āϰ āϏāĻŦāĻā§āϞ⧠āĻŦāĻžāĻšā§āϰ
āϝā§āĻāĻĢāϞ āĻāϤ?

The successive terms of the series 1 + \[\frac12 + \frac14 + \frac18 + ………\] is half(\[\frac12\]) of the previous term. The sum of such a series is \[\frac{1}{1- \frac12}\] (Similarly if the successive term is one third of the previous term then the sum of the series is \[\frac{1}{1- \frac13}\].
Now, by joining the three midpoints of an equilateral triangle one can draw another equilateral triangle; similarly one can draw another equilateral triangle by joining the midpoint of the second equilateral triangle. If infinite numbers of such triangles are drawn, what will be the sum of the sides of all the triangle, assuming the edge of the original triangle to be 1m.
Junior Category
Q1. 11āĻā§ 3 āĻĻāĻŋāϝāĻŧā§ āĻāĻžāĻ āĻāϰāϞ⧠āĻāĻžāĻāĻĢāϞ āĻāϤ? āĻāĻžāĻāĻļā§āώ āĻāϤā§?
If 11 is divided by 3 what is the quotient ? What is the remainder?
Q2. āĻāĻāĻāĻŋ āϏāĻŽāĻžāύā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ n āϏāĻāĻā§āϝāĻ āĻĒāĻĻā§āϰ āϝā§āĻāĻĢāϞ \[ n^2 + 3n \] āĨ¤ āϧāĻžāϰāĻžāĻāĻŋ āĻā§?
The sum of first n terms of an arithmetic series is \[ n^2 + 3n \]. Find the series.
Q3. āĻĒā§āϰāĻŽāĻžāĻŖ āĻāϰ āĻĻā§’āĻāĻŋ āĻŦāĻžāϏā§āϤāĻŦ āϏāĻāĻā§āϝāĻž a āĻāĻŦāĻ b -āĻāϰ āĻā§āĻŖāĻĢāϞ āĻŦā§āĻšāϤā§āϤāĻŽ āĻšāĻŦā§ āϝāĻāύ āϏāĻāĻā§āϝāĻž āĻĻā§āĻāĻŋ āϏāĻŽāĻžāύ āĻšāĻŦā§ āĻāĻŦāĻ a +b = āϧā§āϰā§āĻŦāĻ āĨ¤
Prove that the product of two real numbers is maximum when the numbers are equal to each other while a +b = constant.
Q4. āϤāĻŋāύāĻāĻŋ āĻā§āϰāĻŽāĻŋāĻ āϏāĻāĻā§āϝāĻžāϰ āĻā§āĻŖāĻĢāϞ āĻāĻŦāĻ āϝā§āĻāĻĢāϞ āϏāĻŽāĻžāύ, āϏāĻāĻā§āϝāĻžāĻā§āϞāĻŋ āĻā§? āϏāĻŽā§āĻāĻžāĻŦā§āϝ āϏāĻŦāĻā§āϞāĻŋ āϏāĻŽāĻžāϧāĻžāύ āϞāĻŋāĻ?
The sum and product of three successive numbers are equal, find the numbers. Find all the possible solutions.
Q5. x=2+â3 āĻšāϞ⧠\[ x^4 + x^3 + x^2 + \frac{1}{x} + \frac{1}{x^2} + \frac{1}{x^3} + \frac{1}{x^4} \] āĻāϰ āĻŽāĻžāύ āύāĻŋāϰā§āύāϝāĻŧ āĻāϰāĨ¤
Find the value of \[ x^4 + x^3 + x^2 + \frac{1}{x} + \frac{1}{x^2} + \frac{1}{x^3} + \frac{1}{x^4} \] if x=2+â3
Q6. (â5+â6+â7)(â5+â6-â7)(â5-â6+â7)(- â5+â6+â7) =?
Q7. 1+2+5+6+9+10+13+14+….. āϧāĻžāϰāĻžāĻāĻŋāϰ āĻĒāĻĨāĻŽ 100 āĻĒāĻĻā§āϰ āϝā§āĻāĻĢāϞ āĻāϤ?
Find the sum of the first 100 terms of the series 1+2+5+6+9+10+13+14+…..
Qā§Ē. āϏāĻŽāĻžāϧāĻžāύ āĻāϰ :
Solve :
(x-2) \[ (x^2 +5x+3) = x-2 \]
Q9. āĻāĻāĻāĻŋ āĻŦāϰā§āĻāĻā§āώā§āϤā§āϰ āĻĻā§āĻāϝāĻŧāĻž āĻāĻā§āĨ¤ āĻļā§āϧ⧠āĻāĻŽā§āĻĒāĻžāϏ āĻāĻŦāĻ āϰā§āϞāĻžāϰ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰ⧠āĻ āĻŦāϰā§āĻāĻā§āώā§āϤā§āϰā§āϰ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻā§āώā§āϤā§āϰāĻĢāϞ āĻŦāĻŋāĻļāĻŋāώā§āĻ āĻāĻāĻāĻŋ āĻŦāϰā§āĻāĻā§āώā§āϤā§āϰ āĻāĻāĻā§ āĨ¤
Using compass and Ruler only, draw a square with area twice a given square.
Q10. (a) āϤā§āϰāĻŋāĻā§āĻā§āϰ āĻĻā§’āĻāĻŋ āĻŦāĻžāĻšā§ (a=5 cm, b=6 cm) āĻāĻŦāĻ āĻāĻŽāύ āĻāĻāĻāĻŋ āĻā§āĻŖ ((B=60°) āĻĻā§āĻāϝāĻŧāĻž āĻāĻā§ āϝāĻž āĻ āĻĻā§āĻā§ āĻŦāĻžāĻšā§āϰ āĻŽāϧā§āϝāĻāĻžāϰ āύāϝāĻŧ āĨ¤ āĻļā§āϧ⧠āĻŽāĻžāϤā§āϰ āĻāĻŽā§āĻĒāĻžāϏ āĻ āϰā§āϞāĻžāϰ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰ⧠āϤā§āϰāĻŋāĻā§āĻāĻāĻŋ āĻāĻāĻāĨ¤
(b) b āĻŦāĻžāĻšā§āϰ āĻĻā§āϰā§āĻā§āϝ 6 cm āύāĻž āĻšāϝāĻŧā§ 4.5 cm āĻšāϞ⧠āĻā§ āĻšāϤā§?
(a) Two sides of a triangle (a=5cm, b=6 cm) and an angle not between these two sides ((B =60°) are given. Draw the triangle using only a compass and a ruler.
(b) If the length of one side is 4.5 cm instead of 6 cm, what is going to happen?
Q11. āĻāĻāĻāĻŋ āĻāϝāĻŧāϤ āĻā§āώā§āϤā§āϰā§āϰ āĻĻā§āϰā§āĻā§āϝ āĻĒā§āϰāϏā§āĻĨ āĻĨā§āĻā§ 5 cm āĻŦā§āĻļāĻŋāĨ¤ āϝāĻĻāĻŋ āĻĻā§āϰā§āĻā§āϝāĻā§ āĻ
āϰā§āϧā§āĻ āĻāϰ⧠āĻĢā§āϞāĻž āĻšāϝāĻŧ āĻāĻŦāĻ āĻĒā§āϰāϏā§āĻĨ 3 cm āĻāĻŽā§ āϝāĻžāϝāĻŧ āϤāĻžāĻšāϞ⧠āĻā§āώā§āϤā§āϰāĻĢāϞ 40 cm āĻāĻŽā§ āϝāĻžāϝāĻŧ āĨ¤ āĻāϝāĻŧāϤāĻā§āώā§āϤā§āϰā§āϰ āĻĻā§āϰā§āĻā§āϝ āĻāϤā§?
The length of a rectangle is 5 cm longer than its width. If the length is halved, the width is reduced by 3 cm, and then the area is decreased by 40 cm2. What is the length of the rectangle?
Q12. āϤāĻŋāύ āĻŦāύā§āϧ⧠A, B āĻ C āĻāĻāĻāĻŋ āĻŦāĻžāĻāĻĻāϰā§āϰ āϏāĻšāĻžāϝāĻŧāϤāĻžāϝāĻŧ āĻāĻŋāĻā§ āύāĻžāϰāĻā§āϞ āϏāĻāĻā§āϰāĻš āĻāϰ⧠āĻā§āĻŽāĻŋāϝāĻŧā§ āĻĒāĻĄāĻŧāϞā§āĨ¤ āĻāĻŋāĻā§āĻā§āώāĻŖ āĻĒāϰ A āĻā§āĻŽ āĻĨā§āĻā§ āĻāĻ ā§ āύāĻžāϰāĻā§āϞāĻā§āϞā§āĻā§ āϏāĻŽāĻžāύ āϤāĻŋāύāĻāĻžāĻā§ āĻāĻžāĻ āĻāϰāϞ⧠āĻāĻŦāĻ āĻ
āĻŦāĻļāĻŋāώā§āĻ 1āĻāĻŋ āύāĻžāϰāĻā§āϞ āĻŦāĻžāĻāĻĻāϰāĻā§ āĻĻāĻŋāϝāĻŧā§ āĻĻāĻŋāϞāĨ¤ āϤāĻžāϰāĻĒāϰ āĻāĻāĻāĻžāĻ āύāĻŋāĻā§āϰ āĻāύā§āϝ āϏāϰāĻŋāϝāĻŧā§ āϰā§āĻā§ āĻāĻŦāĻžāϰ āĻā§āĻŽāĻŋāϝāĻŧā§ āĻĒāĻĄāĻŧāϞā§āĨ¤ āĻāĻŋāĻā§āĻā§āώāĻŖ āĻĒāϰ⧠B āĻā§āĻā§ āĻāĻ ā§ āĻāĻāĻ āĻāĻžāĻ āĻāϰāϞā§āĨ¤ āϝā§āĻšā§āϤ⧠āϏ⧠āĻāĻžāύ⧠āύāĻž āϝā§, A āĻāϤāĻŋāĻŽāϧā§āϝ⧠āĻāĻ āĻāĻžāĻ āĻāϰā§āĻā§ āϤāĻžāĻ āϏ⧠āϏāĻŦ āύāĻžāϰāĻŋāĻā§āϞ āϏāĻžāĻŽāύ āϤāĻŋāύāĻāĻžāĻ āĻāϰ⧠āĻ
āĻŦāĻļāĻŋāώā§āĻ āĻāĻāĻāĻŋ āĻŦāĻžāύāϰāĻāĻŋāĻā§ āĻĻāĻŋāϞ āĻāϰ āĻāĻāĻāĻžāĻ āύāĻŋāĻā§ āϏāϰāĻŋāϝāĻŧā§ āĻā§āĻŽāĻŋāϝāĻŧā§ āĻĒāĻĄāĻŧāϞā§āĨ¤ āϏāĻŦāĻļā§āώ⧠C āĻā§āĻā§ āĻāĻ ā§āĻ āĻāĻāĻ āĻāĻžāĻ āĻāϰāϞā§āĨ¤ āϏāĻāĻžāϞ⧠āϤāĻŋāύ āĻŦāύā§āϧ⧠āĻā§āĻā§ āύāĻžāϰāĻā§āϞāĻā§āϞ⧠āϏāĻŽāĻžāύ āϤāĻŋāύāĻāĻžāĻ āĻāϰ⧠āĻĒā§āϰāϤā§āϝā§āĻā§ āĻāĻāĻāĻžāĻ āĻāϰ⧠āύāĻŋāϞ āĻāĻŦāĻ āĻ
āĻŦāĻļāĻŋāώā§āĻāĻāĻŋ āĻŦāĻžāύāϰāĻā§ āĻĻāĻŋāϝāĻŧā§ āĻĻāĻŋāϞ āϤāĻžāϰ āĻ
āĻā§āϞāĻžāύā§āϤ āĻĒāϰāĻŋāĻļā§āϰāĻŽā§āϰ āĻāύā§āϝāĨ¤ āĻļā§āϰā§āϤ⧠āĻāϰāĻž āĻāĻŽāĻĒāĻā§āώ⧠āĻāϝāĻŧāĻāĻŋ āύāĻžāϰāĻā§āϞ āϏāĻāĻā§āϰāĻš āĻāϰā§āĻāĻŋāϞ?
3 friends A, B and C with the help of a monkey collected many cocoanuts, got tired and fell asleep. At night A woke up and decided to have his share. He divided cocoanuts into 3 equal shares giving the left out single cocoanut to monkey for it hard labour and fell asleep again. In the same way in order B and C woke up. Not knowing whether anybody woke up and each of them divided the cocoanuts into three shares, every time giving the left out single cocoanut to the monkey. Early in the morning all of them woke up together, divided the cocoanuts into 3 equal shares and a left out cocoanut gave to the monkey. What is the minimum number of cocoanuts they collected?
Secondary Category
Q1. āϏāĻŽāĻžāϧāĻžāύ āĻāϰ : Solve :
\[ 4^x â 3^{x-\frac12} = 3^{x + \frac12} â 2^{2x â 1} \]
Q2. āĻāĻāĻāĻŋ āϏāĻŽāĻžāύā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ, āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āĻāĻŦāĻ āϤā§āϤā§āϝāĻŧ āĻĒāĻĻ āϝāĻĨāĻžāĻā§āϰāĻŽā§ a, b āĻ \[a^2 \] āϝā§āĻāĻžāύ⧠a āĻāĻāĻāĻŋ āĻāĻŖāĻžāϤā§āĻŦāĻ āϏāĻāĻā§āϝāĻž āĨ¤ āĻāĻŦāĻžāϰ āĻāĻāĻāĻŋ āĻā§āĻŖā§āϤā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ, āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āĻāĻŦāĻ āϤā§āϤā§āϝāĻŧ āĻĒāĻĻ āϝāĻĨāĻžāĻā§āϰāĻŽā§ a, \[a^2 \] āĻ b āĨ¤
i) a āĻ b -āĻāϰ āĻŽāĻžāύ āĻāϤā§?
ii) āĻā§āĻŖā§āϤā§āϤāϰ āϧāĻžāϰāĻžāϰ āϝā§āĻāĻĢāϞ āĻāϤā§?
iii) āϏāĻŽāĻžāύā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ 40 āĻĒāĻĻā§āϰ āϝā§āĻāĻĢāϞ āĻāϤ?
The 1st, 2nd and 3rd terms of an arithmetic series are a, b and \[a^2 \] where a is negative.
The 1st, 2nd and 3rd terms of a geometric series are a, \[a^2 \] and b . Find the
a. The value of a and b
b. The sum of the geometric series.
c. The sum of the first 40 terms of the arithmetic series.
Q3. āĻĒā§āϰāĻŽāĻžāĻŖ āĻāϰ P āϝāĻĻāĻŋ āĻŽā§āϞāĻŋāĻ āϏāĻāĻā§āϝāĻž āύāĻž āĻšāϝāĻŧ āϤāĻžāĻšāϞ⧠\[ 2^p â 1 \] āĻŽā§āϞāĻŋāĻ āϏāĻāĻā§āϝāĻž āύāϝāĻŧ?
Prove that \[ 2^p â 1 \] is not a prime number if P is not a prime number
Q4. \[ 3^{999} \] āϏāĻāĻā§āϝāĻžāĻāĻŋāϰ āĻļā§āώ āĻĻā§’āĻāĻŋ (āϏāϰā§āĻŦ āĻĄāĻžāύā§) āĻ
āĻāĻ āĻā§ āĻā§?
Find the last two digits (rightmost) of \[ 3^{999} \].
Q5. 5 cm āĻŦā§āϝāĻžāϏāĻžāϰā§āϧ āĻŦāĻŋāĻļāĻŋāώā§āĻ āĻāĻāĻāĻŋ āĻŦā§āϤā§āϤā§āϰ āĻ
āύā§āϤāϏā§āĻĨāĻ āĻ āĻŦāĻšāĻŋāϏā§āĻĨāĻ āĻŦāϰā§āĻā§āϰ āĻā§āώā§āϤā§āϰāĻĢāϞā§āϰ āĻĒāĻžāϰā§āĻĨāĻā§āϝ āĻŦā§āϰ āĻāϰ āĨ¤
Find the difference of the area of the external and internal square of a circle of radius 5 cm.
Q6. AB āĻ CD āĻāĻāĻāĻŋ āĻŦā§āϤā§āϤā§āϰ āĻŦā§āϝāĻžāϏ āĻāĻŦāĻ o āĻ āĻŦā§āϤā§āϤā§āϰ āĻā§āύā§āĻĻā§āϰ āĨ¤ AB āĻ CD āĻĒāϰāϏā§āĻĒāϰā§āϰ āĻāĻĒāϰ āϞāĻŽā§āĻŦāĨ¤ āĻŦā§āϤā§āϤā§āϰ āĻāĻāĻāĻŋ āĻā§āϝāĻž DF āĻŦā§āϝāĻžāϏ ABāĻā§ E āĻŦāĻŋāύā§āĻĻā§āϤ⧠āĻā§āĻĻ āĻāϰā§āĨ¤ āϝāĻĻāĻŋ DE=6 āĻāĻŦāĻ EF=2āĻšāϝāĻŧ āϤāĻžāĻšāϞ⧠āĻŦā§āϤā§āϤā§āϰ āĻā§āώā§āϤā§āϰāĻĢāϞ āĻāϤ?

AB and CD are diameters of the circle with center O. Also AB is perpendicular to CD and chord DF intersects AB at E. If DE=6 and EF=2, what is the area of the circle.
Q7. āϏāĻŽāĻžāϧāĻžāύ āĻāϰ:
Solve :
\[ \sqrt{3 â x} +1 = x \]
Q8. \[\cos\left(\frac12\theta\right) = \pm\sqrt{\frac{1+\cos\theta}2} \] āϏāĻŽā§āĻāϰāĻŖāĻāĻŋ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰ⧠\[\cos\frac{9\mathrm\pi}8 \] āĻāϰ āĻŽāĻžāύ āĻŦā§āϰ āĻāϰ
Find the value of \[\cos\frac{9\mathrm\pi}8 \] using the equation \[\cos\left(\frac12\theta\right) = \pm\sqrt{\frac{1+\cos\theta}2} \]
Q10. O āĻ OâāĻā§āύā§āĻĻā§āϰ āĻŦāĻŋāĻļāĻŋāώā§āĻ āĻĻā§āĻāĻŋ āĻŦā§āϤā§āϤ A āĻŦāĻŋāύā§āĻĻā§āϤ⧠āĻŦāĻšāĻŋāĻāϏā§āĻĒāϰā§āĻļ āĻāϰā§āĻā§āĨ¤ TT’ āϏā§āĻĒāϰā§āĻļāĻ āĻŦā§āϤā§āϤ āĻĻā§āĻāĻŋāĻā§ āϝāĻĨāĻžāĻā§āϰāĻŽā§ P āĻ Q āĻŦāĻŋāύā§āĻĻā§āϤ⧠āϏā§āĻĒāϰā§āĻļ āĻāϰā§āĻā§āĨ¤ āĻĒā§āϰāĻŽāĻžāĻŖ āĻāϰ (PAO + (QAO = āĻāĻ āϏāĻŽāĻā§āĻŖ āĨ¤

Two circles with the centres O and O’, touch each other externally at A. The tangent TT’ touches the two circles at P and Q respectively. Prove (PAO+(QAO=Right angle.
f(x)=x if x 20
Q11.
āϝāĻĻāĻŋ If f(x) = |x| āĻ
āϰā§āĻĨāĻžā§ \[ \left\{\begin{array}{l}f(x)=x\;if\;x\geq0\\f(x)=-x\;if\;x<0\end{array}\right. \] āĻāĻŦāĻ g(x) =\[ x^2 â 5 \] āĻšāϝāĻŧ
āϤāĻŦā§ \[f\left(f\left(g\left(f\left(-1\right)\right)\right)\right) \] = ?
If f(x) = |x| ie \[ \left\{\begin{array}{l}f(x)=x\;if\;x\geq0\\f(x)=-x\;if\;x<0\end{array}\right. \] and g(x) = \[ x^2 â 5 \]
then \[f\left(f\left(g\left(f\left(-1\right)\right)\right)\right) \] = ?
Q12. āϤāĻŋāύāĻāĻŋ āĻā§āϰāĻŽāĻŋāĻ āϏāĻāĻā§āϝāĻžāϰ āĻā§āĻŖāĻĢāϞ āĻāĻŦāĻ āϝā§āĻāĻĢāϞ āϏāĻŽāĻžāύ, āϏāĻāĻā§āϝāĻžāĻā§āϞāĻŋ āĻā§? āϏāĻŽā§āĻāĻžāĻŦā§āϝ āϏāĻŦāĻā§āϞāĻŋ āϏāĻŽāĻžāϧāĻžāύ āϞāĻŋāĻ āĨ¤ The sum and product of three successive numbers are equal, find the numbers. Find all the possible solutions.

