Bd math Olympiad national questions 2014
1. āĻā§āύ āϏāĻāĻā§āϝāĻžāĻā§ āϏā§āĻ āϏāĻāĻā§āϝāĻž āĻĻāĻŋāϝāĻŧā§ āĻā§āĻŖ āĻāϰāϞ⧠āĻĒā§āϰāĻžāĻĒā§āϤ āĻā§āĻŖāĻĢāϞ āĻāĻāĻāĻŋ āĻĒā§āϰā§āĻŖāĻŦāϰā§āĻ āϏāĻāĻā§āϝāĻžāĨ¤ āϝā§āĻŽāύ- 2Ã2=4 āĻāĻāĻāĻŋ āĻĒā§āϰā§āĻŖāĻŦāϰā§āĻ āϏāĻāĻā§āϝāĻžāĨ¤ āϤāĻŋāύāĻāĻŋ āĻā§āϰāĻŽāĻŋāĻ āϧāύāĻžāϤā§āĻŽāĻ āϏāĻāĻā§āϝāĻžāϰ āϝā§āĻāĻĢāϞ āĻāĻāĻāĻŋ āĻĒā§āϰā§āĻŖāĻŦāϰā§āĻ āϏāĻāĻā§āϝāĻžāĨ¤ āĻāϰā§āĻĒ āϏāϰā§āĻŦāύāĻŋāĻŽā§āύ āĻĒā§āϰā§āĻŖāĻŦāϰā§āĻ āϏāĻāĻā§āϝāĻž
āĻāϤ?
If a number is multiplied by itself, then the obtained product is a square number. For example, 2×2=4_ is a square number. The sum of three consecutive positive numbers is a square number. Which is the smallest such square number?
2. à āĻā§ 10 āĻĻāĻŋāϝāĻŧā§ āĻāĻžāĻ āĻāϰāϞ⧠āĻāĻžāĻāĻĢāϞ āĻšāϝāĻŧ āĨ¤ āĻāĻŦāĻ āĻ
āĻŦāĻļāĻŋāώā§āĻ āĻĨāĻžāĻā§ 4āĨ¤ āϝāĻĻāĻŋ x āĻ y āĻāĻāϝāĻŧāĻ āϧāύāĻžāϤā§āĻŽāĻ āĻĒā§āϰā§āĻŖāϏāĻāĻā§āϝāĻž āĻšāϝāĻŧ, āϤāĻžāĻšāϞ⧠x āĻā§ 5 āĻĻāĻŋāϝāĻŧā§ āĻāĻžāĻ āĻāϰāϞ⧠āĻāϤ āĻ
āĻŦāĻļāĻŋāώā§āĻ āĻĨāĻžāĻāĻŦā§?
When x is divided by 10, the quotient is y with a remainder of 4. If x and y are both positive integers, what is the remainder when x is divided by 5?
3. āϰā§āĻŦāĻžāĻ āĻāϰ āĻŦāĻŋāĻĻā§āώā§āϰ āĻāĻžāĻā§ āĻāĻŋāĻā§ āĻŽāĻžāϰā§āĻŦā§āϞ āĻāĻā§āĨ¤ āĻŦāĻŋāĻĻā§āώ⧠āϰā§āĻŦāĻžāĻāĻā§ āĻŦāϞāϞ, âāϤā§āĻŽāĻŋ āĻāĻŽāĻžāĻā§ āϝāϤāĻā§āϞ⧠āĻŽāĻžāϰā§āĻŦā§āϞ āĻĻā§āĻŦā§ āĻāĻŽāĻŋ āϤā§āĻŽāĻžāĻā§ āϤāĻžāϰ āĻā§āϝāĻŧā§ āĻāĻāĻāĻž āĻŽāĻžāϰā§āĻŦā§āϞ āĻŦā§āĻļāĻŋ āĻĢā§āϰāϤ āĻĻā§āĻŦāĨ¤â āϰā§āĻŦāĻžāĻ āĻŦāϞāϞ, âāĻ āĻŋāĻ āĻāĻā§ āĻāĻŽāĻŋ āϤā§āĻŽāĻžāĻā§ āĻĒā§āϰāĻĨāĻŽā§ 6 āĻāĻž āĻŽāĻžāϰā§āĻŦā§āϞ āĻĻā§āĻŦāĨ¤â āĻāϰāĻĒāϰ, āϰā§āĻŦāĻžāĻ āĻŦāĻŋāĻĻā§āώā§āĻā§ 6 āĻāĻž āĻŽāĻžāϰā§āĻŦā§āϞ āĻĻāĻŋāϞ āĻāĻŦāĻ āĻŦāĻŋāĻĻā§āώ⧠āϰā§āĻŦāĻžāĻāĻā§ 7āĻāĻž āĻŽāĻžāϰā§āĻŦā§āϞ āĻĢā§āϰāϤ āĻĻāĻŋāϞāĨ¤ āĻāĻāĻžāĻŦā§, 5āĻŦāĻžāϰ āĻŽāĻžāϰā§āĻŦā§āϞ āĻĻā§āĻāϝāĻŧāĻž āύā§āĻāϝāĻŧāĻžāϰ āĻĒāϰ āĻŦāĻŋāĻĻā§āώā§āϰ āĻāĻžāĻā§ āĻāϰ āĻā§āύ āĻŽāĻžāϰā§āĻŦā§āϞ āĻĨāĻžāĻāϞ āύāĻžāĨ¤ āĻļā§āϰā§āϤ⧠āĻŦāĻŋāĻĻā§āώā§āϰ āĻāĻžāĻā§ āĻāϝāĻŧāĻāĻŋ āĻŽāĻžāϰā§āĻŦā§āϞ āĻāĻŋāϞ?
Rubai and Bidushi have some marbles. Bidushi told Rubai, âIf you give me some marbles, I will return you one more marble than as many as you gave me.â Rubai said, âAlright, I will first give you 6 marbles.â Then, Rubai gave Bidushi 6 marbles and Bidushi returned 7 marbles to Rubai. Thus, after they have exchanged marbles 5 times, Bidushi has no marbles left. How many marbles did Bidushi have in the beginning?
4. āĻāĻŽāύ āĻāϤāĻāĻŋ āĻāĻžāϰ āĻ āĻā§āĻā§āϰ āϏāĻāĻā§āϝāĻž āĻāĻā§ āϝāĻžāĻĻā§āϰ āĻļā§āώ āĻĻā§āĻāĻŋ āĻ āĻā§āĻ āĻĻā§āĻŦāĻžāϰāĻž āĻāĻāĻ āĻā§āϰāĻŽā§ āĻāĻ āĻŋāϤ āϏāĻāĻā§āϝāĻžāĻā§ āϤāĻŋāύ āĻā§āĻŖ āĻāϰāϞ⧠āĻĒā§āϰāĻĨāĻŽ āĻĻā§āĻāĻŋ āĻ āĻā§āĻ āĻĻā§āĻŦāĻžāϰāĻž āĻāĻāĻ āĻā§āϰāĻŽā§ āĻāĻ āĻŋāϤ āϏāĻāĻā§āϝāĻž āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧ? āϝā§āĻŽāύ- 3612, āϝā§āĻāĻžāύ⧠āĻļā§āώ āĻĻā§āĻāĻŋ āĻ āĻā§āĻ āĻĻā§āĻŦāĻžāϰāĻž āĻāĻāĻ āĻā§āϰāĻŽā§ āĻāĻ āĻŋāϤ āϏāĻāĻā§āϝāĻž 12 āĻā§ āϤāĻŋāύ āĻā§āĻŖ āĻāϰāϞ⧠36 āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧāĨ¤
How many four digit numbers are there for which, the number formed by its last two digits in the same order when multiplied by three gives the number formed by its first two digits, in the same order? For example, 3612 is such a number where the number formed by the last two digits in the same order is 12 and when multiplied by 3 gives 36.
5. āϏā§āĻŦā§āϰāϤ āĻāĻāĻāĻŋ āύāϤā§āύ āϧāϰāύā§āϰ āĻāĻĄāĻŧāĻŋ āĻāĻŦāĻŋāώā§āĻāĻžāϰ āĻāϰā§āĻā§ āϝā§āĻāĻŋāϤ⧠15 āĻāύā§āĻāĻžāϝāĻŧ āĻāĻ āĻĻāĻŋāύ āĻāĻŦāĻ ā§Ēā§Ļ āĻŽāĻŋāύāĻŋāĻā§ āĻāĻ āĻāύā§āĻāĻžāĨ¤ āϝā§āĻŽāύ, āϏāĻžāϧāĻžāϰāύ āĻāĻĄāĻŧāĻŋāϤ⧠āϝāĻāύ 16:00 āĻŦāĻžāĻā§, āϤāĻāύ āϏā§āĻŦā§āϰāϤ’āϰ āĻāĻĄāĻŧāĻŋāϤ⧠āĻŦāĻžāĻā§ 10:00āĨ¤ āϝāĻĻāĻŋ āϏāĻžāϧāĻžāϰāύ āĻāĻĄāĻŧāĻŋāϤ⧠āϏāĻŽāϝāĻŧ āĻĻā§āĻāĻžāϝāĻŧ 20:36, āϤāĻāύ āϏā§āĻŦā§āϰāϤ’āϰ āĻāĻĄāĻŧāĻŋāϤ⧠āϏāĻŽāϝāĻŧ āĻāϤ āĻĻā§āĻāĻžāĻŦā§?
Subrata has invented a new type of clock, according to which there are 15 hours in each day and 80 minutes in each hour. For example, Subrata’s clock shows 10:00 when the actual time is 16:00 in a traditional clock. If the time is 20:36 in a traditional clock, then what will be the time in Subrata’s clock? (6) āĻāĻāĻāĻž āĻāĻžāĻ 18 āĻĻāĻŋāύ⧠āϏāĻŽā§āĻĒāύā§āύ āĻāϰāĻž 6.
6. āĻĒā§āϰāϝāĻŧā§āĻāύāĨ¤ āĻāĻāĻāύ āĻāύā§āĻā§āϰāĻžāĻā§āĻāϰ 12 āĻāύ āϞā§āĻāĻā§ āĻāĻžāĻāĻāĻž āĻāϰāϤ⧠āύāĻŋāϝāĻŧā§āĻ āĻĻāĻŋāϞ āĻāĻŋāύā§āϤ⧠10 āĻĻāĻŋāύ āĻĒāϰ āĻĻā§āĻāĻž āĻā§āϞ āϝ⧠āĻļā§āϧ⧠āĻ āϰā§āϧā§āĻ āĻāĻžāĻ āϏāĻŽā§āĻĒāύā§āύ āĻšāϝāĻŧā§āĻā§āĨ¤ āĻāϤāĻāύ āϞā§āĻāĻā§ āϤāĻžāϰ āύāĻŋāϝāĻŧā§āĻ āĻĻā§āϝāĻŧāĻž āϞāĻžāĻāĻŦā§ āϝāĻžāϤ⧠āĻāĻžāĻāĻāĻŋ āĻĒā§āϰā§āĻŦāύāĻŋāϰā§āϧāĻžāϰāĻŋāϤ āϏāĻŽāϝāĻŧā§ āϏāĻŽā§āĻĒāύā§āύ āĻšāϝāĻŧ?
A work has to be done in 18 days. A contractor assigned 12 men to do the task but after 10 days it was found that only half of the work was done. So how many men should he add so that the work will be finished in time?
7. 1, 2, 3, 4…………., 30 āĻāĻ āϧāĻžāϰāĻžāĻāĻŋ āĻĨā§āĻā§ āĻāĻŋāĻā§ āϏāĻāĻā§āϝāĻž āĻā§āĻā§ āĻĻāĻŋāϝāĻŧā§ āύāϤā§āύ āĻāĻāĻāĻŋ āϧāĻžāϰāĻž āϤā§āϰāĻŋ āĻāϰāϤ⧠āĻšāĻŦā§ āϝā§āύ āύāϤā§āύ āϧāĻžāϰāĻžāϰ āϝā§āĻā§āύ⧠āϏāĻāĻā§āϝāĻžāϰ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāϰāϞ⧠āύāϤā§āύ āϧāĻžāϰāĻžāϰ āĻ āύā§āϝ āĻāĻāĻāĻŋ āĻĒāĻĻ āύāĻž āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧāĨ¤ āύāϤā§āύ āϧāĻžāϰāĻžāϝāĻŧ āϏāϰā§āĻŦā§āĻā§āĻ āĻāϤāĻāĻŋ āĻĒāĻĻ āĻĨāĻžāĻāĻŦā§?
A new series is to be formed by removing some terms from the series 1, 2, 3, 4…………., 30 such that no term of the new series is obtained if any term of the new series is doubled. Maximum how many terms can there be in the new series?
8. āĻāĻāĻāĻŋ 14Ã14 āĻāĻā§āϤāĻŋāϰ āĻā§āϰāĻŋāĻĄ āĻŦāĻž āĻāĻāĻā§ āĻāĻŋ āĻāĻŋāϤā§āϰā§āϰ T āĻāĻā§āϤāĻŋāϰ āĻāĻŖā§āĻĄ āĻĻā§āĻŦāĻžāϰāĻž āĻĸā§āĻā§ āĻĢā§āϞāĻž āϏāĻŽā§āĻāĻŦ, āϝā§āĻāĻžāύ⧠āĻāĻŖā§āĻĄāĻā§āϞ⧠āĻāĻāĻāĻŋ āĻ āĻĒāϰāĻāĻŋāϰ āĻāĻĒāϰ āĻŦāϏāĻŦā§ āύāĻž? āĻāϤā§āϤāϰā§āϰ āϝā§āĻā§āϤāĻŋ āĻāĻĒāϏā§āĻĨāĻžāĻĒāύ āĻāϰā§āĨ¤

Is it possible to completely cover a 14Ã14 grid by T shaped blocks from the diagram such that no block overlaps any other block? Explain your answer with logic.
Junior Category
(1) 2āĻŽāĻŋ., 4āĻŽāĻŋ., 6āĻŽāĻŋ. āĻāĻŦāĻ ā§ĒāĻŽāĻŋ. āĻĻā§āϰā§āĻā§āϝā§āϰ āĻāĻžāϰāĻāĻŋ āϞāĻžāĻ āĻŋ āĻĨā§āĻā§ āĻĒā§āϰāϤāĻŋāĻŦāĻžāϰ āϤāĻŋāύāĻāĻŋ āϞāĻžāĻ āĻŋ āύāĻŋāϝāĻŧā§ āĻŽā§āĻ āĻāϝāĻŧāĻāĻŋ āϤā§āϰāĻŋāĻā§āĻ āϤā§āϰāĻŋ āĻāϰāĻž āϝāĻžāϝāĻŧ?
How many triangles can be made in total by choosing three out of four sticks of 2m, 4m, 6m and 8m length?
(2) āĻāĻŽāύ āĻāϤāĻāĻŋ āĻāĻžāϰ āĻ
āĻā§āĻā§āϰ āϏāĻāĻā§āϝāĻž āĻāĻā§ āϝāĻžāĻĻā§āϰ āĻļā§āώ āĻĻā§āĻāĻŋ āĻ
āĻā§āĻ āĻĻā§āĻŦāĻžāϰāĻž āĻāĻāĻ āĻā§āϰāĻŽā§ āĻāĻ āĻŋāϤ āϏāĻāĻā§āϝāĻžāĻā§ āĻāĻžāϰ āĻā§āĻŖ āĻāϰāϞ⧠āĻĒā§āϰāĻĨāĻŽ āĻĻā§āĻāĻŋ āĻ
āĻā§āĻ āĻĻā§āĻŦāĻžāϰāĻž āĻāĻāĻ āĻā§āϰāĻŽā§ āĻāĻ āĻŋāϤ āϏāĻāĻā§āϝāĻž āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧ? āϝā§āĻŽāύ- 4812, āϝā§āĻāĻžāύ⧠āĻļā§āώ āĻĻā§āĻāĻŋ āĻ
āĻā§āĻ āĻĻā§āĻŦāĻžāϰāĻž āĻāĻāĻ āĻā§āϰāĻŽā§ āĻāĻ āĻŋāϤ āϏāĻāĻā§āϝāĻž 12 āĻā§ 4 āĻā§āĻŖ āĻāϰāϞ⧠48 āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧāĨ¤
How many four digit numbers are there for which, the number formed by its last two digits in the same order when multiplied by four gives the number formed by its first two digits, in the same order? For example, 4812 is such a number where the number formed by the last two digits in the same order is 12 and when multiplied by 4 gives 48.
(3) āϏā§āĻŦā§āϰāϤ āĻāĻāĻāĻŋ āύāϤā§āύ āϧāϰāύā§āϰ āĻāĻĄāĻŧāĻŋ āĻāĻŦāĻŋāώā§āĻāĻžāϰ āĻāϰā§āĻā§ āϝā§āĻāĻŋāϤ⧠15 āĻāύā§āĻāĻžāϝāĻŧ āĻāĻ āĻĻāĻŋāύ āĻāĻŦāĻ ā§Ēā§Ļ āĻŽāĻŋāύāĻŋāĻā§ āĻāĻ āĻāύā§āĻāĻžāĨ¤ āϝā§āĻŽāύ, āϏāĻžāϧāĻžāϰāύ āĻāĻĄāĻŧāĻŋāϤ⧠āϝāĻāύ 16:00 āĻŦāĻžāĻā§, āϤāĻāύ āϏā§āĻŦā§āϰāϤ’āϰ āĻāĻĄāĻŧāĻŋāϤ⧠āĻŦāĻžāĻā§ 10:00āĨ¤ āϝāĻĻāĻŋ āϏāĻžāϧāĻžāϰāύ āĻāĻĄāĻŧāĻŋāϤ⧠āϏāĻŽāϝāĻŧ āĻĻā§āĻāĻžāϝāĻŧ 20:36, āϤāĻāύ āϏā§āĻŦā§āϰāϤ’āϰ āĻāĻĄāĻŧāĻŋāϤ⧠āϏāĻŽāϝāĻŧ āĻāϤ āĻĻā§āĻāĻžāĻŦā§?
Subrata has invented a new type of clock, according to which there are 15 hours in each day and 80 minutes in each hour. For example, Subrata’s clock shows 10:00 when the actual time is 16:00 in a traditional clock. If the time is 20:36 in a traditional clock, then what will be the time in Subrata’s clock?
(4) āĻāϝāĻŧ āĻ
āĻāĻā§āϰ āĻāĻāĻāĻŋ āϏāĻāĻā§āϝāĻžāϰ āϏāϰā§āĻŦāĻĄāĻžāύā§āϰ āĻ
āĻāĻāĻāĻŋ 1āĨ¤ āĻāĻāĻŋāĻā§ āϏāϰāĻŋāϝāĻŧā§ āĻāĻāĻŦāĻžāϰ⧠āĻļā§āϰā§āϤ⧠āĻŦāϏāĻŋāϝāĻŧā§ āĻĻā§āĻāϝāĻŧāĻž āĻšāϞā§āĨ¤ āύāϤā§āύ āϝ⧠āϏāĻāĻā§āϝāĻžāĻāĻŋ āĻĒāĻžāĻāϝāĻŧāĻž āĻā§āϞ āϏā§āĻāĻŋ āĻŽā§āϞ āϏāĻāĻā§āϝāĻžāĻāĻŋāϰ \[\frac13\] āĻā§āύāĨ¤ āĻŽā§āϞ āϏāĻāĻā§āϝāĻžāĻāĻŋ āĻāϤ?
The unit digit of a six-digit number is 1 and it is removed, leaving a five-digit number. The removed unit digit 1 is then placed at the far left of the five-digit number, making a new six-digit number. If the new number is \[\frac13\] of the original number, what is the original number?
(5) 1, 2, 3, 4…………., 30 āĻāĻ āϧāĻžāϰāĻžāĻāĻŋ āĻĨā§āĻā§ āĻāĻŋāĻā§ āϏāĻāĻā§āϝāĻž āĻā§āĻā§ āĻĻāĻŋāϝāĻŧā§ āύāϤā§āύ āĻāĻāĻāĻŋ āϧāĻžāϰāĻž āϤā§āϰāĻŋ āĻāϰāϤ⧠āĻšāĻŦā§ āϝā§āύ āύāϤā§āύ āϧāĻžāϰāĻžāϰ āϝā§āĻā§āύ⧠āϏāĻāĻā§āϝāĻžāϰ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāϰāϞ⧠āύāϤā§āύ āϧāĻžāϰāĻžāϰ āĻ
āύā§āϝ āĻāĻāĻāĻŋ āĻĒāĻĻ āύāĻž āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧāĨ¤ āύāϤā§āύ āϧāĻžāϰāĻžāϝāĻŧ āϏāϰā§āĻŦā§āĻā§āĻ āĻāϤāĻāĻŋ āĻĒāĻĻ āĻĨāĻžāĻāĻŦā§?
A new series is to be formed by removing some terms from the series 1, 2, 3, 4…………., 30 such that no term of the new series is obtained if any term of the new series is doubled. Maximum how many
(6)āĻāĻāĻāĻŋ 14Ã14 āĻāĻā§āϤāĻŋāϰ āĻā§āϰāĻŋāĻĄ āĻŦāĻž āĻāĻāĻā§ āĻāĻŋ āĻāĻŋāϤā§āϰā§āϰ T āĻāĻā§āϤāĻŋāϰ āĻāĻŖā§āĻĄ āĻĻā§āĻŦāĻžāϰāĻž āĻĸā§āĻā§ āĻĢā§āϞāĻž āϏāĻŽā§āĻāĻŦ, āϝā§āĻāĻžāύ⧠āĻāĻŖā§āĻĄāĻā§āϞ⧠āĻāĻāĻāĻŋ āĻ āĻĒāϰāĻāĻŋāϰ āĻāĻĒāϰ āĻŦāϏāĻŦā§ āύāĻž? āĻāϤā§āϤāϰā§āϰ āϝā§āĻā§āϤāĻŋ āĻāĻĒāϏā§āĻĨāĻžāĻĒāύ āĻāϰā§āĨ¤

Is it possible to completely cover a 14Ã14 grid by T shaped blocks from the diagram such that no block overlaps any other block? Explain your answer with logic.
(7) āĻāĻŋāϤā§āϰ⧠āϝāĻĻāĻŋ AB= 10, āϤāĻžāĻšāϞ⧠CD āĻŦāĻžāĻšā§āϰ āĻĻā§āϰā§āĻā§āϝ āĻāϤ?

In the figure, if AB= 10, what is the length of the side CD?
(8) AVIK āĻāĻāĻāĻŋ āĻŦāϰā§āĻāĻā§āώā§āϤā§āϰāĨ¤ VK āĻāϰ āĻāĻĒāϰ E āĻŦāĻŋāύā§āĻĻā§ āĻāĻŽāύāĻāĻžāĻŦā§ āύā§āĻāϝāĻŧāĻž āĻšāϞ āϝā§āύ 3VE=EK āĨ¤ AK āĻāϰ āĻŽāϧā§āϝāĻŦāĻŋāύā§āĻĻā§ F āĻšāϞ⧠â FEI āĻāϰ āĻŽāĻžāύ āĻāϤ?
AVIK is a square. The point E is taken on VK in such a way that 3VE=EK. F is the midpoint of AK. What is the value of â FEI?
(9) āϝāĻĻāĻŋ N āĻāĻāĻāĻŋ āĻā§āĻĄāĻŧ āĻĒā§āϰā§āĻŖāϏāĻāĻā§āϝāĻž āĻšāϝāĻŧ, āĻĒā§āϰāĻŽāĻžāĻŖ āĻāϰ⧠āϝ⧠48 āĻĻā§āĻŦāĻžāϰāĻž \[N(N^2 + 20)\] āύāĻŋāĻāĻļā§āώ⧠āĻŦāĻŋāĻāĻžāĻā§āϝāĨ¤
If N is an even integer, prove that 48 divides \[N(N^2 + 20)\] .
(10) āĻāύā§āĻĻā§āϰāĻŋāϰ āĻāĻžāĻā§ 100āĻāĻŋ āĻāĻāϞā§āĻ āĻāĻā§āĨ¤ āϏ⧠āĻĒā§āϰāϤāĻŋāĻĻāĻŋāύ āĻāĻŽāĻĒāĻā§āώ⧠āĻāĻāĻāĻŋ āĻāĻāϞā§āĻ āĻā§āϝāĻŧā§ 58 āĻĻāĻŋāύ⧠āϏāĻŦāĻā§āϞ⧠āĻāĻāϞā§āĻ āĻļā§āώ āĻāϰāϞāĨ¤ āĻĒā§āϰāĻŽāĻžāύ āĻāϰ āϝā§, āϏ⧠āϧāĻžāϰāĻžāĻŦāĻžāĻšāĻŋāĻāĻāĻžāĻŦā§ āĻāϝāĻŧā§āĻāĻĻāĻŋāύ⧠āĻ āĻŋāĻ 15āĻāĻŋ āĻāĻāϞā§āĻ āĻā§āϝāĻŧā§āĻā§āĨ¤
Oindri has 100 chocolates. She finished eating all her chocolates in 58 days by eating at least one chocolate each day. Prove that, in how many consecutive days did she eat exactly 15 chocolates.
Secondary Category
(1) x āĻā§ 10 āĻĻāĻŋāϝāĻŧā§ āĻāĻžāĻ āĻāϰāϞ⧠āĻāĻžāĻāĻĢāϞ āĻšāϝāĻŧ y āĻāĻŦāĻ āĻ
āĻŦāĻļāĻŋāώā§āĻ āĻĨāĻžāĻā§ 3āĨ¤ āϝāĻĻāĻŋ x āĻ y āĻāĻāϝāĻŧāĻ āĻĒā§āϰā§āĻŖ āϧāύāĻžāϤā§āĻŽāĻ āϏāĻāĻā§āϝāĻž āĻšāϝāĻŧ, āϤāĻžāĻšāϞ⧠x āĻā§ 5 āĻĻāĻŋāϝāĻŧā§ āĻāĻžāĻ āĻāϰāϞ⧠āĻāϤ āĻ
āĻŦāĻļāĻŋāώā§āĻ āĻĨāĻžāĻāĻŦā§?
If x is divided by 10 then the quotient is y and the remainder is 3. If x and y both are positive integers then what will be the remainder if x is divided by 5?
(2) āϏā§āĻŦā§āϰāϤ āĻāĻāĻāĻŋ āύāϤā§āύ āĻāĻĄāĻŧāĻŋ āĻāĻŦāĻŋāώā§āĻāĻžāϰ āĻāϰā§āĻā§ āϝāĻž āĻ
āύā§āϏāĻžāϰ⧠15 āĻāύā§āĻāĻžāϝāĻŧ āĻāĻāĻĻāĻŋāύ āĻāĻŦāĻ ā§Ēā§Ļ āĻŽāĻŋāύāĻŋāĻā§ āĻāĻāĻāύā§āĻāĻž āĻšāϝāĻŧāĨ¤ āĻāĻĻāĻžāĻšāϰāĻŖ āĻšāĻŋāϏā§āĻŦā§ āĻŦāϞāĻž āϝāĻžāϝāĻŧ, āϝāĻāύ āĻĒā§āϰāĻā§āϤ āĻĒāĻā§āώ⧠āϏāĻŽāϝāĻŧ 16:00 āϤāĻāύ āϏā§āĻŦā§āϰāϤāϰ āĻāĻĄāĻŧāĻŋāϤ⧠āĻŦāĻžāĻā§ 10:00āĨ¤ āϝāĻĻāĻŋ āĻāĻāĻāĻŋ āĻĒā§āϰāĻāϞāĻŋāϤ āĻāĻĄāĻŧāĻŋāϤ⧠āϏāĻŽāϝāĻŧ āĻšāϝāĻŧ 18:42 āϤāĻŦā§ āϏā§āĻŦā§āϰāϤāϰ āĻāĻĄāĻŧāĻŋāϤ⧠āϤāĻāύ āĻāϝāĻŧāĻāĻž āĻŦāĻžāĻā§?
Subrata has invented a new type of clock, according to which there are 15 hours in each day and 80 minutes in each hour. For example, Subrata’s clock shows 10:00 when the actual time is 16:00. If the time is 18:42 in a traditional clock, then what will be the time in Subrata’s clock?
(3) āĻāĻāĻāĻŋ 19Ã21 āĻĻāĻžāĻŦāĻžāĻŦā§āϰā§āĻĄā§ āϤāĻāϏāĻŋāĻĢ āĻā§āĻ āĻŦāύā§āϧ āĻāϰ⧠āĻā§āĻĄāĻŧāĻž āĻŦāϏāĻžāϤ⧠āϞāĻžāĻāϞā§āĨ¤ āĻŽā§āĻ āĻāϤāĻāĻŋ āĻā§āĻĄāĻŧāĻž āĻŦāϏāĻžāύā§āϰ āĻĒāϰ āϏ⧠āύāĻŋāĻļā§āĻāĻŋāϤ āĻāĻžāĻŦā§ āĻŦāϞāϤ⧠āĻĒāĻžāϰāĻŦā§ āϝ⧠āĻĒāϰā§āϰ āĻāĻžāϞ⧠āĻā§āύ⧠āĻā§āĻĄāĻŧāĻž āĻ
āύā§āϝ āĻā§āύ⧠āĻā§āĻĄāĻŧāĻž āĻā§ āĻāĻā§āϰāĻŽāĻŖ āĻāϰāĻŦā§? ( āĻā§āĻĄāĻŧāĻž āĻāĻāĻāĻŋ āĻāĻžāϞ⧠āϝā§āĻā§āύ⧠āĻĻāĻŋāĻā§ 2 āĻāϰ āϝāĻžāĻŦāĻžāϰ āĻĒāϰ āϞāĻŽā§āĻŦāĻāĻžāĻŦā§ 1 āĻāϰ āϝāĻžāĻŦā§āĨ¤)
Closing his eyes Towsif begins to place knights on a Chess board of 19Ã21. After placing how many knights Towsif will be sure that on the next move at least one knight will attack another one. (In one move knight goes straight for 2 steps and the 3rd step should be at right angle to the previous path.)
(4) ABC āϤā§āϰāĻŋāĻā§āĻā§ â B = 90°āĨ¤ AB āĻā§ āĻā§āϝāĻž āϧāϰ⧠āĻāĻāĻāĻŋ āĻŦā§āϤā§āϤ āĻāĻāĻāĻž āĻšāϞāĨ¤ o āĻŦā§āϤā§āϤā§āϰ āĻā§āύā§āĻĻā§āϰāĨ¤ O āĻāĻŦāĻ C, AB āĻāϰ āĻāĻāĻ āĻĒāĻžāĻļā§ āĻ
āĻŦāϏā§āĻĨāĻŋāϤ āύāϝāĻŧāĨ¤ BD, AC āĻāϰ āĻāĻĒāϰ āϞāĻŽā§āĻŦāĨ¤ āĻĒā§āϰāĻŽāĻžāĻŖ āĻāϰ āϝā§, BD āĻŦā§āϤā§āϤā§āϰ āĻāĻāĻāĻŋ āϏā§āĻĒāϰā§āĻļāĻ āĻšāĻŦā§ āϝāĻĻāĻŋ āĻ āĻā§āĻŦāϞ āϝāĻĻāĻŋ BAO = â BAC āĻšāϝāĻŧāĨ¤
In ÎABC, â B = 90°. A circle is drawn taking AB as a chord O is the center of the circle. O and C isn’t on the same side of AB. BD is perpendicular to AC. Prove that, BD will be a tangent to the circle if and only if â BAO = â BAC.
(5) 97+98+ ……….+114+115 = 2014. āĻāĻāĻžāύ⧠19 āĻāĻŋ āĻā§āϰāĻŽāĻŋāĻ āϏāĻāĻā§āϝāĻžāϰ āϝā§āĻāĻĢāϞ 2014āĨ¤ āϏāϰā§āĻŦā§āĻā§āĻ āĻāϤāĻāĻŋ āĻā§āϰāĻŽāĻŋāĻ āϏāĻāĻā§āϝāĻžāϰ āϝā§āĻāĻĢāϞ 2014 āĻšāϤ⧠āĻĒāĻžāϰā§? āĻāϤā§āϤāϰā§āϰ āĻĒāĻā§āώ⧠āϝā§āĻā§āϤāĻŋ āĻĻā§āĻāĻžāĻāĨ¤
97+98+ ………..+114+115 = 2014. Here sum of 19 consecutive numbers is 2014. Find the largest
number of consecutive positive integers whose sum is exactly 2014 and justify why you think this must be the largest number.
(6) ÎABC āĻāĻāĻāĻŋ āϏā§āĻā§āώā§āĻŽāĻā§āĻŖā§ āϤā§āϰāĻŋāĻā§āĻ āϝāĻžāϰ â C=60° āĨ¤ A āĻāĻŦāĻ B āĻŦāĻŋāύā§āĻĻā§ āĻšāϤ⧠BC, AC āĻŦāĻžāĻšā§āϰ āĻāĻĒāϰ āĻ āĻā§āĻāĻŋāϤ āϞāĻŽā§āĻŦ āĻĻā§āĻāĻŋ āϝāĻĨāĻžāĻā§āϰāĻŽā§ \[ AA_1 \] āĻāĻŦāĻ \[ BB_1 \] āĨ¤ AB āĻāϰ āĻŽāϧā§āϝ āĻŦāĻŋāύā§āĻĻā§ M āĨ¤ āϤāĻŦā§ \[ \frac{\angle A_1MB_1}{\angle A_1CB_1}\] āĻāϰ āĻŽāĻžāύ āĻāϤ?
Let ÎABC be an acute angled triangle with C=60°. Perpendiculars \[ AA_1 \] & \[ BB_1 \] are drawn from point A and B to the sides BC & AC respectively. Let M be the midpoint of AB. What is the value of \[ \frac{\angle A_1MB_1}{\angle A_1CB_1}\] ?
(7) AABC-āĻ AC āĻāĻŦāĻ AB āĻāϰ āĻāĻĒāϰ āĻ āĻŦāϏā§āĻĨāĻŋāϤ āĻĻā§āĻāĻŋ āĻŦāĻŋāύā§āĻĻā§ E,F āϝā§āύ EF||ACāĨ¤ Q,AB āĻāϰ āĻāĻĒāϰ āĻāĻŽāύ āĻāĻāĻāĻŋ āĻŦāĻŋāύā§āĻĻā§ āϝā§āύ \[\frac{AQ}{FQ} = \frac{30}{13}\]āĨ¤ PQ, EF āĻāϰ āϏāĻŽāĻžāύā§āϤāϰāĻžāϞ āϝā§āĻāĻžāύ⧠P,CB āĻāϰ āĻāĻĒāϰ āĻ āĻŦāϏā§āĻĨāĻŋāϤāĨ¤ EQ āĻāϰ āĻŦāϰā§āϧāĻŋāϤ āĻ āĻāĻļā§āϰ āĻāĻĒāϰ āĻāĻāĻāĻŋ āĻŦāĻŋāύā§āĻĻā§ X āĻāĻŽāύ āĻāĻžāĻŦā§ āύā§āϝāĻŧāĻž āĻšāϞ āϝā§āύ CX= 20.4āĨ¤ āĻĻā§āϝāĻŧāĻž āĻāĻā§, \[\frac{CY}{EY} = \frac{XY}{CF}\] , PX=15.6; āϝāĻĻāĻŋ â YCE=22.5° āĻšāϝāĻŧ â PXQ=?
In ÎABC E, F are two points on AC and AB such that EF||AC. Q is a point on AB such that \[\frac{AQ}{FQ} = \frac{30}{13}\]. PQ is parallel to EF where P lies on CB. X is taken on extended EQ such that CX=20.4. Given \[\frac{CY}{EY} = \frac{XY}{CF}\] , PX=15.6;; if â YCE=22.5°, â PXQ=?
(ā§Ē) āĻāĻāĻāĻŋ āϤā§āϰāĻŋāĻā§āĻā§āϰ āĻĻā§āĻāĻŋ āĻļā§āϰā§āώāĻŦāĻŋāύā§āĻĻā§ āĻĨā§āĻā§ āĻŦāĻŋāĻĒāϰā§āϤ āĻŦāĻžāĻšā§āϰ āĻāĻĒāϰ āĻ
āĻā§āĻāĻŋāϤ āϞāĻŽā§āĻŦāĻĻā§āĻŦāϝāĻŧā§āϰ āĻĻā§āϰā§āĻā§āϝ 2014 āĻāĻāĻ āĻāĻŦāĻ 1 āĻāĻāĻ āĻšāϞ⧠āϤā§āϤā§āϝāĻŧ āĻļā§āϰā§āώāĻŦāĻŋāύā§āĻĻā§ āĻšāϤ⧠āϤāĻžāϰ āĻŦāĻŋāĻĒāϰā§āϤ āĻŦāĻžāĻšā§āϰ āĻāĻĒāϰ āĻ
āĻā§āĻāĻŋāϤ āϞāĻŽā§āĻŦā§āϰ āĻĻā§āϰā§āĻā§āϝ āĻāϤ āĻšāĻŦā§?
If the lengths of two altitudes drawn from two vertices of a triangle on their opposite sides are 2014 and 1 unit, then what will be the length of the altitude drawn from the third vertex of the triangle on its opposite side?
(9) āĻāĻāĻāĻŋ āĻĻāĻžāĻŦāĻž āĻā§āϰā§āύāĻžāĻŽā§āύā§āĻā§ n āϏāĻāĻā§āϝāĻ āĻā§āϞā§āϝāĻŧāĻžāĻĄāĻŧ āĻāĻā§āĨ¤ āĻĒā§āϰāϤā§āϝā§āĻ āĻā§āϞā§āϝāĻŧāĻžāĻĄāĻŧ āĻ āĻĒāϰ āĻĒā§āϰāϤā§āϝā§āĻ āĻā§āϞā§āϝāĻŧāĻžāĻĄāĻŧā§āϰ āϏāĻžāĻĨā§ āĻ āĻŋāĻ āĻāĻāĻŦāĻžāϰāĻ āĻā§āϞ⧠āĻāĻŦāĻ āĻāĻ āĻā§āϞāĻžāϝāĻŧ āĻā§āύ āĻĄā§āϰ āύā§āĻāĨ¤ āĻĒā§āϰāĻŽāĻžāĻŖ āĻāϰ āϝā§, āĻā§āϞā§āϝāĻŧāĻžāĻĄāĻŧāĻĻā§āϰāĻā§ 1, 2, āĻĻā§āĻŦāĻžāϰāĻž āϞā§āĻŦā§āϞ āĻāϰāĻž āϝāĻžāĻŦā§ āϝā§āĻāĻžāύ⧠i āϤāĻŽ āĻā§āϞā§āϝāĻŧāĻžāĻĄāĻŧ i+1 āϤāĻŽ āĻāύāĻā§ āĻĒāϰāĻžāĻāĻŋāϤ āĻāϰ⧠āĻāĻŦāĻ i â (1, 2, 3,…… n – 1.
There are n players in a chess tournament. Every player plays every other player exactly once, and there are no draws Prove that the players can be labeled 1, 2, ………., n so that i beats i+1 for each i â (1,2,3…….,n-1}.
(10) āϧāϰ, āϤā§āĻŽāĻŋ āĻāĻāĻāĻŋ n à n āĻā§āϰāĻŋāĻĄā§āϰ āĻāĻā§āĻŦāĻžāϰ⧠āύāĻŋāĻā§ āĻŦāĻžāĻŽ āĻĒāĻžāĻļā§āϰ āĻā§āĻŖāĻžāϝāĻŧ āĻāĻāĨ¤ āĻāĻāύ āϤā§āĻŽāĻžāĻā§ āϏāĻŦāĻā§āϝāĻŧā§ āĻāĻĒāϰā§āϰ āĻĄāĻžāύ āĻĒāĻžāĻļā§āϰ āĻā§āύāĻžāϝāĻŧ āϝā§āϤ⧠āĻšāĻŦā§āĨ¤ āĻāĻŋāύā§āϤ⧠āύāĻŋāϝāĻŧāĻŽ āĻšāϞ⧠āϤā§āĻŽāĻŋ āĻļā§āϧ⧠āĻāĻĒāϰ⧠āĻŦāĻž āĻĄāĻžāύ⧠āϝā§āϤ⧠āĻĒāĻžāϰāĻŦā§, āĻāĻŋāύā§āϤ⧠āĻŦāĻžāĻŽā§ āĻŦāĻž āύāĻŋāĻā§ āĻĢāĻŋāϰāϤ⧠āĻĒāĻžāϰāĻŦā§ āύāĻžāĨ¤ āĻāϰ āĻā§āϰāĻŋāĻĄā§āϰ āĻāϰā§āĻŖ āĻŦāϰāĻžāĻŦāϰ āĻāϰ āĻā§āϞā§āϤ⧠āĻŽāĻžāĻāύ āĻĨāĻžāĻāĻžāϝāĻŧ āϤā§āĻŽāĻŋ āϏā§āĻāĻžāύā§āĻ āϝā§āϤ⧠āĻĒāĻžāϰāĻŦā§ āύāĻžāĨ¤ āϤāĻžāĻšāϞ⧠āϤā§āĻŽāĻŋ āĻāϤ āĻāĻĒāĻžāϝāĻŧā§ āĻāύā§āϤāĻŦā§āϝ⧠āϝā§āϤ⧠āĻĒāĻžāϰāĻŦā§?

Suppose that, you are on the left most bottom point of a non grid. You have to reach the rightmost and topmost point. But the rule is you can move just only toward the upper or right direction. Can’t move down or to the left. And as there are mines at the squares which are along the diagonal you can’t go those places too. Determine how many ways are there to reach the destination.
2014 national primary_Complete

