BD national math olympiad questions 2006

Q1. āϏāĻŦāĻšā§‡āϝāĻŧ⧇ āϛ⧋āϟ āϕ⧋āύ āϏāĻ‚āĻ–ā§āϝāĻžāϕ⧇ 2,3,4,5,6,7,8,9 āĻāĻŦāĻ‚ 10 āĻĻāĻŋāϝāĻŧ⧇ āĻ­āĻžāĻ— āĻ•āϰāϞ⧇ āĻ­āĻžāĻ—āĻļ⧇āώ 1 āĻšāϝāĻŧ?
Find the smallest number that gives the remainder 1 if divided by 2,3,4,5,6,7,8,9 and 10. 

Q2. āϏ⧇āϞāĻŋāĻŽ 10 āϟāĻžāĻ•āĻžāϝāĻŧ 3āϟāĻŋ āĻĒ⧇āĻ¨ā§āϏāĻŋāϞ āĻ•āĻŋāύ⧇, 10 āϟāĻžāĻ•āĻžāϝāĻŧ 2āϟāĻŋ āĻŦāĻŋāĻ•ā§āϰāϝāĻŧ āĻ•āϰāϞ⧇ āϤāĻžāϰ āĻļāϤāĻ•āϰāĻž āĻ•āϤ āϟāĻžāĻ•āĻž āϞāĻžāĻ­ āĻŦāĻž āĻ•ā§āώāϤāĻŋ āĻšāĻŦ⧇?
Selim buys 3 pencils for 10 taka and sells 2 pencils for 10 taka, what will be his profit or loss in percentage?

Q3. āĻ•āϞāĻŽ āύāĻž āϤ⧁āϞ⧇ āĻāĻŦāĻ‚ āĻāĻ•āϟāĻŋ āϰ⧇āĻ–āĻžāϰ āωāĻĒāϰ āĻĻāĻŋāϝāĻŧ⧇ āĻĻ⧁āχāĻŦāĻžāϰ āύāĻž āĻ—āĻŋāϝāĻŧ⧇ āϕ⧋āύāϟāĻž āφāρāĻ•āĻž āϏāĻŽā§āĻ­āĻŦ āĻāĻŦāĻ‚ āϕ⧋āύāϟāĻž āφāĻ•āĻž āϏāĻŽā§āĻ­āĻŦ āύāϝāĻŧ?

BD national math olympiad questions 2006
Which one of the figures can you draw without lifting the pen or retracing a line?

Q4. āĻāĻ• āĻ¸ā§āϕ⧁āϞ⧇ āϤāĻŋāύāϜāύ āĻ›āĻžāĻ¤ā§āϰāϕ⧇ 7000 āϟāĻžāĻ•āĻžāϰ āĻŦ⧃āĻ¤ā§āϤāĻŋ āĻĻ⧇āĻ“āϝāĻŧāĻž āĻšāϞ āĨ¤ āĻĒā§āϰāĻĨāĻŽ āϜāύ āϝ⧇ āϟāĻžāĻ•āĻž āĻĒ⧇āϞ, āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āϜāύ āĻĒ⧇āϞ āϤāĻžāϰ āĻ…āĻ°ā§āϧ⧇āĻ• āĻāĻŦāĻ‚ āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āϜāύ āϝ⧇ āϟāĻžāĻ•āĻž āĻĒ⧇āϞ āϤ⧃āϤ⧀āϝāĻŧ āϜāύ āĻĒ⧇āϞ āϤāĻžāϰ āĻ…āĻ°ā§āϧ⧇āĻ• āĨ¤ āϕ⧇ āĻ•āϤ āϟāĻžāĻ•āĻž āĻĒ⧇āϞ?

Three students from a school got scholarship of 7000 taka. The second student got half of the amount of the first person and the third student got half of the amount of the second person. Find the amount of scholarship of the three individual students.

Q5. āĻāĻ•āϟāĻŋ 1000 āĻŦāĻ°ā§āĻ— āĻŽāĻŋāϟāĻžāϰ āĻŦāĻ°ā§āĻ—āĻžāĻ•ā§ƒāϤāĻŋ āĻĒ⧁āϕ⧁āϰ⧇āϰ āϚāĻžāϰāϕ⧋āύāĻžāϝāĻŧ āϚāĻžāϰāϟāĻŋ āĻ—āĻžāĻ› āϰāϝāĻŧ⧇āϛ⧇āĨ¤ āĻ—āĻžāĻ›āϗ⧁āϞ⧋āϕ⧇ āύāĻž āϕ⧇āĻŸā§‡ āĻ›āĻŦāĻŋāϤ⧇ āϝ⧇āĻ­āĻžāĻŦ⧇ āĻĻ⧇āĻ–āĻžāύ⧋ āĻšāϝāĻŧ⧇āϛ⧇ āϏ⧇āĻ­āĻžāĻŦ⧇ āĻĒ⧁āϕ⧁āϰāϟāĻŋāϕ⧇ āĻŦāĻ°ā§āĻ—āĻžāĻ•ā§ƒāϤāĻŋāϤ⧇ āϕ⧇āĻŸā§‡ āĻŦāĻĄāĻŧ āĻ•āϰāĻž āĻšāϞāĨ¤ āĻāĻ–āύ āĻĒ⧁āϕ⧁āϰāϟāĻŋāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻ•āϤ⧋?

%Focuse keyword%
A1000 sqm square pond had four threes at the four corners. The pond was enlarged to a new square without cutting down the trees as shown in the figure. Find the area of the enlarged pond.

Q6. āĻāĻ•āϟāĻŋ āϏāĻžāĻŽāĻžāĻ¨ā§āϤāϰāĻŋāϕ⧇āϰ āϏāĻ¨ā§āύāĻŋāĻšāĻŋāϤ āĻŦāĻžāĻšā§ āĻĻ⧁’āϟāĻŋāϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ 8 cm āĻ“ 6 cmāĨ¤ āϏāĻžāĻŽāĻžāĻ¨ā§āϤāϰāĻŋāĻ•āϟāĻŋāϰ āĻāĻ•āϟāĻŋ āĻļā§€āĻ°ā§āώāĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻĨ⧇āϕ⧇ 8 cm āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻŦāĻžāĻšā§āϰ āĻ“āĻĒāϰ āϞāĻŽā§āĻŦ āĻĻā§‚āϰāĻ¤ā§āĻŦ 3 cm āĻšāϞ⧇ āĻāĻ•āχ āĻļā§€āĻ°ā§āώ āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻĨ⧇āϕ⧇ āĻ…āĻ¨ā§āϝ āĻŦāĻžāĻšā§āϰ āĻ“āĻĒāϰ āϞāĻŽā§āĻŦ āĻĻā§‚āϰāĻ¤ā§āĻŦ āĻŦ⧇āϰ āĻ•āϰ?
The adjacent edges of a parallelogram are 8 cm and 6 cm respectively. If the perpendicular distance of the 8 cm edge from a vertex is 3 cm, find the perpendicular distance to the other edge from the same vertex.
Q7. 1+2+5+6+9+10+13+14+… āϧāĻžāϰāĻžāϟāĻŋāϰ āĻĒāĻĨāĻŽ 100 āĻĒāĻĻ⧇āϰ āϝ⧋āĻ—āĻĢāϞ āĻ•āϤ? [āϏāĻžāĻšāĻžāĻ¯ā§āϝ : āĻĻ⧁’āϟāĻŋ āĻĻ⧁’āϟāĻŋ āĻĒāĻĻ āύāĻŋāϝāĻŧ⧇ āϝ⧋āĻ— āĻ•āϰ]
Find the sum of the first 100 terms of the series 1+2+5+6+9+10+13+14+…… [Hint: Add every two terms]

Q8. 1 āĻĨ⧇āϕ⧇ āĻļ⧁āϰ⧁ āĻ•āϰ⧇ 9 āĻĒāĻ°ā§āϝāĻ¨ā§āϤ āĻ•ā§āϰāĻŽāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰ⧇ āĻāĻ•āϟāĻŋ āĻŽā§āϝāĻžāϜāĻŋāĻ• āĻ¸ā§āĻ•āϝāĻŧāĻžāϰ āϤ⧈āϰāĻŋ āĻ•āϰāĻž āĻšāϝāĻŧ⧇āϛ⧇ āϝ⧇āĻ–āĻžāύ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋ āĻ“āĻĒāϰ āĻĨ⧇āϕ⧇ āύāĻŋāĻšā§‡, āĻŦāĻžāĻŽ āĻĨ⧇āϕ⧇ āĻĄāĻžāύ⧇ āĻ•āĻŋāĻ‚āĻŦāĻž āϕ⧋āύāĻžāϕ⧁āύāĻŋ āϝ⧇āĻ­āĻžāĻŦ⧇āχ āϝ⧋āĻ— āĻ•āϰāĻž āĻšā§‹āĻ• āύāĻž āϕ⧇āύ āϝ⧋āĻ—āĻĢāϞ āĻšāĻŦ⧇ 15āĨ¤ āϤ⧁āĻŽāĻŋ āĻāĻ­āĻžāĻŦ⧇ āĻ…āĻ¨ā§āϝ āύāϝāĻŧāϟāĻŋ āĻ•ā§āϰāĻŽāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āĻŦ⧇āϰ āĻ•āϰ⧇ āφāϰ⧇āĻ•āϟāĻŋ āĻŽā§āϝāĻžāϜāĻŋāĻ• āĻ¸ā§āĻ•āϝāĻŧāĻžāϰ āϤ⧈āϰ⧀ āĻ•āϰ⧋ āϝāĻžāϰ āϝ⧋āĻ—āĻĢāϞ āϏāĻŦāϏāĻŽāϝāĻŧ⧇āχ āĻšāĻŦ⧇ 27 āĨ¤

%Focuse keyword%
Successive integers from 1 to 9 were used to construct a magic square such that the sum of the three numbers is always 15 if added vertically, horizontally or diagonally. Construct a similar magic square using 9 different successive integers such that the sum is always 27.
Q9. āĻāĻ•āϟāĻŋ āĻ•āĻžāĻ—āϜ \[\frac18\] mm āĻĒ⧁āϰ⧁, āĻ•āĻžāĻ—āϜāϟāĻŋāϕ⧇ āĻ›āĻŦāĻŋāϤ⧇ āĻĻ⧇āĻ–āĻžāύ⧋ āωāĻĒāĻžāϝāĻŧ⧇ ā§Ē āĻŦāĻžāϰ āĻ­āĻžāϜ āĻ•āϰāϞ⧇ āĻ•āϤ⧁āϟ⧁āϕ⧁ āĻĒ⧁āϰ⧁ āĻšāĻŦ⧇?

%Focuse keyword%
If a paper of thickness \[\frac18\] mm is folded 8 times in the way shown below, what will be the total thickness?
Q10. 1 + \[\frac12 + \frac14 + \frac18 + ………\] āϧāĻžāϰāĻžāϟāĻŋāϤ⧇ āĻĒāϰ⧇āϰ āĻĒāĻĻāϟāĻŋ āφāϗ⧇āϰ āĻĒāĻĻ⧇āϰ āĻ…āĻ°ā§āϧ⧇āĻ• (\[\frac12\]), āĻāϰāĻ•āĻŽ āϧāĻžāϰāĻžāϰ āϝ⧋āĻ—āĻĢāϞ \[\frac{1}{1- \frac12}\] āϧāĻžāϰāĻžāϟāĻŋāϰ āϝ⧋āĻ—āĻĢāϞ āĻšāϤ⧋ ( āĻāϰāĻ•āĻŽ āϝāĻĻāĻŋ āĻĒāϰ⧇āϰ āĻĒāĻĻāϟāĻŋ āφāϗ⧇āϰ āĻĒāĻĻ⧇āϰ āĻāĻ• āϤ⧃āϤ⧀āϝāĻŧāĻžāĻ‚āĻļ (\[\frac13\]) āĻšāϤ⧋ āϤāĻžāĻšāϞ⧇ \[\frac{1}{1- \frac13}\] , āχāĻ¤ā§āϝāĻžāĻĻāĻŋ)
1m āĻŦāĻžāĻšā§ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻāĻ•āϟāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āĻ¤ā§āϰāĻŋāĻ­ā§‚āĻœā§‡āϰ āĻŽāĻ§ā§āϝāĻŦāĻŋāĻ¨ā§āĻĻ⧁ āϤāĻŋāύāϟāĻŋ āϝ⧋āĻ— āĻ•āϰ⧇ āφāϰ⧇āĻ•āϟāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āĻ¤ā§āϰāĻŋāĻ­ā§‚āϜ āφāĻ•āĻž āϝāĻžāϝāĻŧāĨ¤ āϏ⧇āχ āϏāĻŽāĻŦāĻžāĻšā§ āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻŽāĻ§ā§āϝāĻŦāĻŋāĻ¨ā§āĻĻ⧁āϗ⧁āϞ⧋ āϝ⧋āĻ— āĻ•āϰ⧇ āφāϰ⧇āĻ•āϟāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āĻ¤ā§āϰāĻŋāϭ⧁āϜ āφāĻ•āĻž āϝāĻžāϝāĻŧāĨ¤ āϝāĻĻāĻŋ āĻāĻ­āĻžāĻŦ⧇ āĻ•ā§āϰāĻŽāĻžāĻ—āϤ āĻ…āϏ⧀āĻŽ āϏāĻ‚āĻ–ā§āϝāĻ• āϏāĻŽāĻŦāĻžāĻšā§ āĻ¤ā§āϰāĻŋāĻ­ā§‚āϜ āφāĻ•āĻž āĻšāϝāĻŧ āϤāĻžāĻšāϞ⧇ āϏāĻŦāϗ⧁āϞ⧋ āĻ¤ā§āϰāĻŋāĻ­ā§‚āĻœā§‡āϰ āϏāĻŦāϗ⧁āϞ⧋ āĻŦāĻžāĻšā§āϰ
āϝ⧋āĻ—āĻĢāϞ āĻ•āϤ?

%Focuse keyword%

The successive terms of the series 1 + \[\frac12 + \frac14 + \frac18 + ………\] is half(\[\frac12\]) of the previous term. The sum of such a series is \[\frac{1}{1- \frac12}\] (Similarly if the successive term is one third of the previous term then the sum of the series is \[\frac{1}{1- \frac13}\].
Now, by joining the three midpoints of an equilateral triangle one can draw another equilateral triangle; similarly one can draw another equilateral triangle by joining the midpoint of the second equilateral triangle. If infinite numbers of such triangles are drawn, what will be the sum of the sides of all the triangle, assuming the edge of the original triangle to be 1m.

 

Junior Category

Q1. 11āϕ⧇ 3 āĻĻāĻŋāϝāĻŧ⧇ āĻ­āĻžāĻ— āĻ•āϰāϞ⧇ āĻ­āĻžāĻ—āĻĢāϞ āĻ•āϤ? āĻ­āĻžāĻ—āĻļ⧇āώ āĻ•āϤ⧋?
If 11 is divided by 3 what is the quotient ? What is the remainder?
Q2. āĻāĻ•āϟāĻŋ āϏāĻŽāĻžāĻ¨ā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ n āϏāĻ‚āĻ–ā§āϝāĻ• āĻĒāĻĻ⧇āϰ āϝ⧋āĻ—āĻĢāϞ \[ n^2 + 3n \] āĨ¤ āϧāĻžāϰāĻžāϟāĻŋ āϕ⧀?
The sum of first n terms of an arithmetic series is \[ n^2 + 3n \]. Find the series.
Q3. āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰ āĻĻ⧁’āϟāĻŋ āĻŦāĻžāĻ¸ā§āϤāĻŦ āϏāĻ‚āĻ–ā§āϝāĻž a āĻāĻŦāĻ‚ b -āĻāϰ āϗ⧁āĻŖāĻĢāϞ āĻŦ⧃āĻšāĻ¤ā§āϤāĻŽ āĻšāĻŦ⧇ āϝāĻ–āύ āϏāĻ‚āĻ–ā§āϝāĻž āĻĻ⧁āϟāĻŋ āϏāĻŽāĻžāύ āĻšāĻŦ⧇ āĻāĻŦāĻ‚ a +b = āĻ§ā§āϰ⧁āĻŦāĻ• āĨ¤
Prove that the product of two real numbers is maximum when the numbers are equal to each other while a +b = constant.
Q4. āϤāĻŋāύāϟāĻŋ āĻ•ā§āϰāĻŽāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻžāϰ āϗ⧁āĻŖāĻĢāϞ āĻāĻŦāĻ‚ āϝ⧋āĻ—āĻĢāϞ āϏāĻŽāĻžāύ, āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞāĻŋ āϕ⧀? āϏāĻŽā§āĻ­āĻžāĻŦā§āϝ āϏāĻŦāϗ⧁āϞāĻŋ āϏāĻŽāĻžāϧāĻžāύ āϞāĻŋāĻ–?
The sum and product of three successive numbers are equal, find the numbers. Find all the possible solutions.
Q5. x=2+√3 āĻšāϞ⧇ \[ x^4 + x^3 + x^2 + \frac{1}{x} + \frac{1}{x^2} + \frac{1}{x^3} + \frac{1}{x^4} \] āĻāϰ āĻŽāĻžāύ āύāĻŋāĻ°ā§āύāϝāĻŧ āĻ•āϰāĨ¤
Find the value of \[ x^4 + x^3 + x^2 + \frac{1}{x} + \frac{1}{x^2} + \frac{1}{x^3} + \frac{1}{x^4} \] if x=2+√3
Q6. (√5+√6+√7)(√5+√6-√7)(√5-√6+√7)(- √5+√6+√7) =?
Q7. 1+2+5+6+9+10+13+14+….. āϧāĻžāϰāĻžāϟāĻŋāϰ āĻĒāĻĨāĻŽ 100 āĻĒāĻĻ⧇āϰ āϝ⧋āĻ—āĻĢāϞ āĻ•āϤ?
Find the sum of the first 100 terms of the series 1+2+5+6+9+10+13+14+…..

Qā§Ē. āϏāĻŽāĻžāϧāĻžāύ āĻ•āϰ :
Solve :
(x-2) \[ (x^2 +5x+3) = x-2 \]
Q9. āĻāĻ•āϟāĻŋ āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ āĻĻ⧇āĻ“āϝāĻŧāĻž āφāϛ⧇āĨ¤ āĻļ⧁āϧ⧁ āĻ•āĻŽā§āĻĒāĻžāϏ āĻāĻŦāĻ‚ āϰ⧁āϞāĻžāϰ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰ⧇ āĻ āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻĻā§āĻŦāĻŋāϗ⧁āĻŖ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻāĻ•āϟāĻŋ āĻŦāĻ°ā§āĻ—āĻ•ā§āώ⧇āĻ¤ā§āϰ āφāρāϕ⧋ āĨ¤
Using compass and Ruler only, draw a square with area twice a given square.
Q10. (a) āĻ¤ā§āϰāĻŋāϭ⧁āĻœā§‡āϰ āĻĻ⧁’āϟāĻŋ āĻŦāĻžāĻšā§ (a=5 cm, b=6 cm) āĻāĻŦāĻ‚ āĻāĻŽāύ āĻāĻ•āϟāĻŋ āϕ⧋āĻŖ ((B=60°) āĻĻ⧇āĻ“āϝāĻŧāĻž āφāϛ⧇ āϝāĻž āϐ āĻĻ⧁āĻŸā§‹ āĻŦāĻžāĻšā§āϰ āĻŽāĻ§ā§āϝāĻ•āĻžāϰ āύāϝāĻŧ āĨ¤ āĻļ⧁āϧ⧁ āĻŽāĻžāĻ¤ā§āϰ āĻ•āĻŽā§āĻĒāĻžāϏ āĻ“ āϰ⧁āϞāĻžāϰ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰ⧇ āĻ¤ā§āϰāĻŋāϭ⧁āϜāϟāĻŋ āφāρāĻ•āĨ¤
(b) b āĻŦāĻžāĻšā§āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ 6 cm āύāĻž āĻšāϝāĻŧ⧇ 4.5 cm āĻšāϞ⧇ āϕ⧀ āĻšāϤ⧋?
(a) Two sides of a triangle (a=5cm, b=6 cm) and an angle not between these two sides ((B =60°) are given. Draw the triangle using only a compass and a ruler.
(b) If the length of one side is 4.5 cm instead of 6 cm, what is going to happen?

Q11. āĻāĻ•āϟāĻŋ āφāϝāĻŧāϤ āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻĒā§āϰāĻ¸ā§āĻĨ āĻĨ⧇āϕ⧇ 5 cm āĻŦ⧇āĻļāĻŋāĨ¤ āϝāĻĻāĻŋ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝāϕ⧇ āĻ…āĻ°ā§āϧ⧇āĻ• āĻ•āϰ⧇ āĻĢ⧇āϞāĻž āĻšāϝāĻŧ āĻāĻŦāĻ‚ āĻĒā§āϰāĻ¸ā§āĻĨ 3 cm āĻ•āĻŽā§‡ āϝāĻžāϝāĻŧ āϤāĻžāĻšāϞ⧇ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ 40 cm āĻ•āĻŽā§‡ āϝāĻžāϝāĻŧ āĨ¤ āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§āϰ⧇āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻ•āϤ⧋?
The length of a rectangle is 5 cm longer than its width. If the length is halved, the width is reduced by 3 cm, and then the area is decreased by 40 cm2. What is the length of the rectangle?
Q12. āϤāĻŋāύ āĻŦāĻ¨ā§āϧ⧁ A, B āĻ“ C āĻāĻ•āϟāĻŋ āĻŦāĻžāρāĻĻāϰ⧇āϰ āϏāĻšāĻžāϝāĻŧāϤāĻžāϝāĻŧ āĻ•āĻŋāϛ⧁ āύāĻžāϰāϕ⧇āϞ āϏāĻ‚āĻ—ā§āϰāĻš āĻ•āϰ⧇ āϘ⧁āĻŽāĻŋāϝāĻŧ⧇ āĻĒāĻĄāĻŧāϞ⧋āĨ¤ āĻ•āĻŋāϛ⧁āĻ•ā§āώāĻŖ āĻĒāϰ A āϘ⧁āĻŽ āĻĨ⧇āϕ⧇ āωāϠ⧇ āύāĻžāϰāϕ⧇āϞāϗ⧁āϞ⧋āϕ⧇ āϏāĻŽāĻžāύ āϤāĻŋāύāĻ­āĻžāϗ⧇ āĻ­āĻžāĻ— āĻ•āϰāϞ⧋ āĻāĻŦāĻ‚ āĻ…āĻŦāĻļāĻŋāĻˇā§āϟ 1āϟāĻŋ āύāĻžāϰāϕ⧇āϞ āĻŦāĻžāρāĻĻāϰāϕ⧇ āĻĻāĻŋāϝāĻŧ⧇ āĻĻāĻŋāϞāĨ¤ āϤāĻžāϰāĻĒāϰ āĻāĻ•āĻ­āĻžāĻ— āύāĻŋāĻœā§‡āϰ āϜāĻ¨ā§āϝ āϏāϰāĻŋāϝāĻŧ⧇ āϰ⧇āϖ⧇ āφāĻŦāĻžāϰ āϘ⧁āĻŽāĻŋāϝāĻŧ⧇ āĻĒāĻĄāĻŧāϞ⧋āĨ¤ āĻ•āĻŋāϛ⧁āĻ•ā§āώāĻŖ āĻĒāϰ⧇ B āĻœā§‡āϗ⧇ āωāϠ⧇ āĻāĻ•āχ āĻ•āĻžāϜ āĻ•āϰāϞ⧋āĨ¤ āϝ⧇āĻšā§‡āϤ⧁ āϏ⧇ āϜāĻžāύ⧇ āύāĻž āϝ⧇, A āχāϤāĻŋāĻŽāĻ§ā§āϝ⧇ āĻāχ āĻ•āĻžāϜ āĻ•āϰ⧇āϛ⧇ āϤāĻžāχ āϏ⧇ āϏāĻŦ āύāĻžāϰāĻŋāϕ⧇āϞ āϏāĻžāĻŽāύ āϤāĻŋāύāĻ­āĻžāĻ— āĻ•āϰ⧇ āĻ…āĻŦāĻļāĻŋāĻˇā§āϟ āĻāĻ•āϟāĻŋ āĻŦāĻžāύāϰāϟāĻŋāϕ⧇ āĻĻāĻŋāϞ āφāϰ āĻāĻ•āĻ­āĻžāĻ— āύāĻŋāĻœā§‡ āϏāϰāĻŋāϝāĻŧ⧇ āϘ⧁āĻŽāĻŋāϝāĻŧ⧇ āĻĒāĻĄāĻŧāϞ⧋āĨ¤ āϏāĻŦāĻļ⧇āώ⧇ C āĻœā§‡āϗ⧇ āωāϠ⧇āĻ“ āĻāĻ•āχ āĻ•āĻžāϜ āĻ•āϰāϞ⧋āĨ¤ āϏāĻ•āĻžāϞ⧇ āϤāĻŋāύ āĻŦāĻ¨ā§āϧ⧁ āĻœā§‡āϗ⧇ āύāĻžāϰāϕ⧇āϞāϗ⧁āϞ⧋ āϏāĻŽāĻžāύ āϤāĻŋāύāĻ­āĻžāĻ— āĻ•āϰ⧇ āĻĒā§āϰāĻ¤ā§āϝ⧇āϕ⧇ āĻāĻ•āĻ­āĻžāĻ— āĻ•āϰ⧇ āύāĻŋāϞ āĻāĻŦāĻ‚ āĻ…āĻŦāĻļāĻŋāĻˇā§āϟāϟāĻŋ āĻŦāĻžāύāϰāϕ⧇ āĻĻāĻŋāϝāĻŧ⧇ āĻĻāĻŋāϞ āϤāĻžāϰ āĻ…āĻ•ā§āϞāĻžāĻ¨ā§āϤ āĻĒāϰāĻŋāĻļā§āϰāĻŽā§‡āϰ āϜāĻ¨ā§āϝāĨ¤ āĻļ⧁āϰ⧁āϤ⧇ āĻ“āϰāĻž āĻ•āĻŽāĻĒāĻ•ā§āώ⧇ āĻ•āϝāĻŧāϟāĻŋ āύāĻžāϰāϕ⧇āϞ āϏāĻ‚āĻ—ā§āϰāĻš āĻ•āϰ⧇āĻ›āĻŋāϞ?
3 friends A, B and C with the help of a monkey collected many cocoanuts, got tired and fell asleep. At night A woke up and decided to have his share. He divided cocoanuts into 3 equal shares giving the left out single cocoanut to monkey for it hard labour and fell asleep again. In the same way in order B and C woke up. Not knowing whether anybody woke up and each of them divided the cocoanuts into three shares, every time giving the left out single cocoanut to the monkey. Early in the morning all of them woke up together, divided the cocoanuts into 3 equal shares and a left out cocoanut gave to the monkey. What is the minimum number of cocoanuts they collected?

 

Secondary Category

Q1. āϏāĻŽāĻžāϧāĻžāύ āĻ•āϰ : Solve :
\[ 4^x – 3^{x-\frac12} = 3^{x + \frac12} – 2^{2x – 1} \]
Q2. āĻāĻ•āϟāĻŋ āϏāĻŽāĻžāĻ¨ā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ, āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āĻāĻŦāĻ‚ āϤ⧃āϤ⧀āϝāĻŧ āĻĒāĻĻ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ a, b āĻ“ \[a^2 \] āϝ⧇āĻ–āĻžāύ⧇ a āĻāĻ•āϟāĻŋ āĻ‹āĻŖāĻžāĻ¤ā§āĻŦāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āĨ¤ āφāĻŦāĻžāϰ āĻāĻ•āϟāĻŋ āϗ⧁āĻŖā§‹āĻ¤ā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ, āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āĻāĻŦāĻ‚ āϤ⧃āϤ⧀āϝāĻŧ āĻĒāĻĻ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ a, \[a^2 \] āĻ“ b āĨ¤
i) a āĻ“ b -āĻāϰ āĻŽāĻžāύ āĻ•āϤ⧋?
ii) āϗ⧁āĻŖā§‹āĻ¤ā§āϤāϰ āϧāĻžāϰāĻžāϰ āϝ⧋āĻ—āĻĢāϞ āĻ•āϤ⧋?
iii) āϏāĻŽāĻžāĻ¨ā§āϤāϰ āϧāĻžāϰāĻžāϰ āĻĒā§āϰāĻĨāĻŽ 40 āĻĒāĻĻ⧇āϰ āϝ⧋āĻ—āĻĢāϞ āĻ•āϤ?
The 1st, 2nd and 3rd terms of an arithmetic series are a, b and \[a^2 \] where a is negative.
The 1st, 2nd and 3rd terms of a geometric series are a, \[a^2 \] and b . Find the
a. The value of a and b
b. The sum of the geometric series.
c. The sum of the first 40 terms of the arithmetic series.
Q3. āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰ P āϝāĻĻāĻŋ āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āύāĻž āĻšāϝāĻŧ āϤāĻžāĻšāϞ⧇ \[ 2^p – 1 \] āĻŽā§ŒāϞāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āύāϝāĻŧ?
Prove that \[ 2^p – 1 \] is not a prime number if P is not a prime number
Q4. \[ 3^{999} \] āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋāϰ āĻļ⧇āώ āĻĻ⧁’āϟāĻŋ (āϏāĻ°ā§āĻŦ āĻĄāĻžāύ⧇) āĻ…āĻ‚āĻ• āϕ⧀ āϕ⧀?
Find the last two digits (rightmost) of \[ 3^{999} \].
Q5. 5 cm āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻāĻ•āϟāĻŋ āĻŦ⧃āĻ¤ā§āϤ⧇āϰ āĻ…āĻ¨ā§āϤāĻ¸ā§āĻĨāσ āĻ“ āĻŦāĻšāĻŋāĻ¸ā§āĻĨāσ āĻŦāĻ°ā§āϗ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ⧇āϰ āĻĒāĻžāĻ°ā§āĻĨāĻ•ā§āϝ āĻŦ⧇āϰ āĻ•āϰ āĨ¤
Find the difference of the area of the external and internal square of a circle of radius 5 cm.
Q6. AB āĻ“ CD āĻāĻ•āϟāĻŋ āĻŦ⧃āĻ¤ā§āϤ⧇āϰ āĻŦā§āϝāĻžāϏ āĻāĻŦāĻ‚ o āϐ āĻŦ⧃āĻ¤ā§āϤ⧇āϰ āϕ⧇āĻ¨ā§āĻĻā§āϰ āĨ¤ AB āĻ“ CD āĻĒāϰāĻ¸ā§āĻĒāϰ⧇āϰ āĻ“āĻĒāϰ āϞāĻŽā§āĻŦāĨ¤ āĻŦ⧃āĻ¤ā§āϤ⧇āϰ āĻāĻ•āϟāĻŋ āĻœā§āϝāĻž DF āĻŦā§āϝāĻžāϏ ABāϕ⧇ E āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āϛ⧇āĻĻ āĻ•āϰ⧇āĨ¤ āϝāĻĻāĻŋ DE=6 āĻāĻŦāĻ‚ EF=2āĻšāϝāĻŧ āϤāĻžāĻšāϞ⧇ āĻŦ⧃āĻ¤ā§āϤ⧇āϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ āĻ•āϤ?

%Focuse keyword%
AB and CD are diameters of the circle with center O. Also AB is perpendicular to CD and chord DF intersects AB at E. If DE=6 and EF=2, what is the area of the circle.
Q7. āϏāĻŽāĻžāϧāĻžāύ āĻ•āϰ:
Solve :
\[ \sqrt{3 – x} +1 = x \]
Q8. \[\cos\left(\frac12\theta\right) = \pm\sqrt{\frac{1+\cos\theta}2} \] āϏāĻŽā§€āĻ•āϰāĻŖāϟāĻŋ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰ⧇ \[\cos\frac{9\mathrm\pi}8 \] āĻāϰ āĻŽāĻžāύ āĻŦ⧇āϰ āĻ•āϰ
Find the value of \[\cos\frac{9\mathrm\pi}8 \] using the equation \[\cos\left(\frac12\theta\right) = \pm\sqrt{\frac{1+\cos\theta}2} \]
Q10. O āĻ“ O’āϕ⧇āĻ¨ā§āĻĻā§āϰ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻĻ⧁āϟāĻŋ āĻŦ⧃āĻ¤ā§āϤ A āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āĻŦāĻšāĻŋāσāĻ¸ā§āĻĒāĻ°ā§āĻļ āĻ•āϰ⧇āϛ⧇āĨ¤ TT’ āĻ¸ā§āĻĒāĻ°ā§āĻļāĻ• āĻŦ⧃āĻ¤ā§āϤ āĻĻ⧁āϟāĻŋāϕ⧇ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ P āĻ“ Q āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āĻ¸ā§āĻĒāĻ°ā§āĻļ āĻ•āϰ⧇āϛ⧇āĨ¤ āĻĒā§āϰāĻŽāĻžāĻŖ āĻ•āϰ (PAO + (QAO = āĻāĻ• āϏāĻŽāϕ⧋āĻŖ āĨ¤

%Focuse keyword%
Two circles with the centres O and O’, touch each other externally at A. The tangent TT’ touches the two circles at P and Q respectively. Prove (PAO+(QAO=Right angle.

f(x)=x if x 20
Q11.
āϝāĻĻāĻŋ If f(x) = |x| āĻ…āĻ°ā§āĻĨāĻžā§Ž \[ \left\{\begin{array}{l}f(x)=x\;if\;x\geq0\\f(x)=-x\;if\;x<0\end{array}\right. \] āĻāĻŦāĻ‚ g(x) =\[ x^2 – 5 \] āĻšāϝāĻŧ
āϤāĻŦ⧇ \[f\left(f\left(g\left(f\left(-1\right)\right)\right)\right) \] = ?
If f(x) = |x| ie \[ \left\{\begin{array}{l}f(x)=x\;if\;x\geq0\\f(x)=-x\;if\;x<0\end{array}\right. \] and g(x) = \[ x^2 – 5 \]
then \[f\left(f\left(g\left(f\left(-1\right)\right)\right)\right) \] = ?

Q12. āϤāĻŋāύāϟāĻŋ āĻ•ā§āϰāĻŽāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻžāϰ āϗ⧁āĻŖāĻĢāϞ āĻāĻŦāĻ‚ āϝ⧋āĻ—āĻĢāϞ āϏāĻŽāĻžāύ, āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞāĻŋ āϕ⧀? āϏāĻŽā§āĻ­āĻžāĻŦā§āϝ āϏāĻŦāϗ⧁āϞāĻŋ āϏāĻŽāĻžāϧāĻžāύ āϞāĻŋāĻ– āĨ¤ The sum and product of three successive numbers are equal, find the numbers. Find all the possible solutions.

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